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4. MOS: Device Operation and Large Signal Model Lecture notes: Sec. 4 Sedra & Smith (6 th Ed): Sec. 5.1-5.3 Sedra & Smith (5 th Ed): Sec. 4.1-4.3 ECE 65, Winter2013, F. Najmabadi Operational Basis of a Field-Effect Transistor (1)


  1. 4. MOS: Device Operation and Large Signal Model Lecture notes: Sec. 4 Sedra & Smith (6 th Ed): Sec. 5.1-5.3 Sedra & Smith (5 th Ed): Sec. 4.1-4.3 ECE 65, Winter2013, F. Najmabadi

  2. Operational Basis of a Field-Effect Transistor (1) Consider the hypothetical semiconductor below: (constructed similar to a parallel plate capacitor) Electrical contact Metal Insulator Dopent ions P-type semiconductor Holes (majority carries) F. Najmabadi, ECE65, Winter 2013, Intro to MOS (2/29)

  3. Operational Basis of a Field-Effect Transistor (2)  If we apply a voltage v 1 between electrodes, a Depletion Region (no majority carrier) charge Q = C v 1 will appear on each capacitor plate. o The electric field is strongest at the interface with the insulator and charge likes to accumulate there.  Holes are pushed away from the insulator interface forming a “depletion region”.  Depth of depletion region increases with v 1. Inversion layer  If we increase v 1 above a threshold value ( V t ), (“channel”) the electric field is strong enough to “pull” free electrons to the insulator interface. As the holes are repelled in this region, a “channel” is Depletion Region formed which contains electrons in the (no majority carrier) conduction band (“inversion layer”).  Inversion layer is a “virtual” n-type material. F. Najmabadi, ECE65, Winter 2013, Intro to MOS (3/29)

  4. Operational Basis of a Field-Effect Transistor (3)  We apply a voltage across the p-type semiconductor: (Assume current flows only in the n-type material, ignore current flowing in the p-type semiconductor) No inversion layer ( v 1 < V t ): With inversion layer ( v 1 > V t ):  No current will flow  A current will flow in the channel  Current will be proportional to electron charge in the channel or ( v 1 − V t )  Magnitude of Current i 2 is controlled by voltage v 1 (a Transistor!) F. Najmabadi, ECE65, Winter 2013, Intro to MOS (4/29)

  5. Operational Basis of a Field-Effect Transistor (4)  We need to eliminate currents flowing in the p-type, i.e., current flows only in the “channel” which is a virtual n-type.  Make n-type material terminals (set up diodes between terminals & p-type “body”)  Heavy doping of the n-type terminals provides a source of free electrons for the channel.  Make insulator layer as thin as possible to increase the electric field.  Body-source and body-drain junctions should always be in reverse bias for FET to work! F. Najmabadi, ECE65, Winter 2013, Intro to MOS (5/29)

  6. Channel width (L) is the smallest feature on the chip surface MOSFET “cartoons” for deriving MOSFET (or MOS): Metal-oxide field-effect transistor MOSFET characteristics NMOS: n-channel enhancement MOS MOSFET implementation on a chip F. Najmabadi, ECE65, Winter 2013, Intro to MOS (6/29)

  7. NMOS i-v Characteristics (1)  To ensure that body-source and body-drain junctions are reversed bias, we assume that Body and Source are connected to each other and v DS ≥ 0 . o We will re-examine this assumption later  Without a channel, no current flows (“Cut-off”).  For v GS > V tn , a channel is formed. The total charge in the channel is = = |Q| CV C WL ( v -V ) ox GS tn = C C W L ox ε = ox C : Capacitanc e per unit area ox t ox t : Thickness of insulator ox ε : permitivit y of insulator ox ε = ε = × − 11 3 . 9 3 . 45 10 F/m (for SiO ) ox 0 2 Overdrive Voltage: V OV = v GS –V tn F. Najmabadi, ECE65, Winter 2013, Intro to MOS (7/29)

  8. NMOS i-v Characteristics (2)  v GS > V tn A channel is formed  Apply a small v DS between drain & source.  A current flows due to the “drift” of electrons in the n-channel: W = µ − i C ( v V ) v D n ox GS tn DS L W = µ i C V v D n ox OV DS L For small v DS , MOS acts as a resistance with its conductivity controlled by V OV (or v GS ). W = = µ i g v with g C V D DS DS DS n ox OV L F. Najmabadi, ECE65, Winter 2013, Intro to MOS (8/29)

  9. NMOS i-v Characteristics (4)  When v DS is increased the channel becomes narrower near the drain (local depth of the channel depends on the difference between V G and local voltage). Triode Mode [ ] W = µ − 2 i C V v 0 . 5 v D n ox OV DS DS L  When v DS is increased further such that v DS = V OV , the channel depth becomes zero at the drain (Channel “pinched off”).  When v DS is increased further, v DS > V OV , the location of channel pinch-off remains close to the Saturation Mode drain and i D remains approximately constant. W = µ 2 i 0 . 5 C V D n ox OV L F. Najmabadi, ECE65, Winter 2013, Intro to MOS (9/29)

  10. NMOS i-v Characteristics (5) For a given v GS (or V OV ) F. Najmabadi, ECE65, Winter 2013, Intro to MOS (10/29)

  11. NMOS i-v Characteristics Plot (1)  NMOS i-v characteristics is a surface i = f ( v , v ) D GS DS * Plot for V t,n = 1 V and µ n C ox ( W/L ) = 2.0 m A/V 2 F. Najmabadi, ECE65, Winter 2013, Intro to MOS (11/29)

  12. NMOS i-v Characteristics Plot (2) Looking at surface with v GS axis pointing out of the paper* *Note: surface was truncated (i.e., v GS < 5 V) F. Najmabadi, ECE65, Winter 2013, Intro to MOS (12/29)

  13. NMOS i-v Characteristics Plot (3) F. Najmabadi, ECE65, Winter 2013, Intro to MOS (13/29)

  14. Channel-Width Modulation  The expression we derived for saturation region assumed that the pinch-off point remains at the drain and thus i D remains constant.  In reality, the pinch-off point moves “slightly” away from the drain: Channel-width Modulation W ( ) = µ + λ 2 i 0 . 5 C V 1 v D n ox OV DS L λ = 1 / V A F. Najmabadi, ECE65, Winter 2013, Intro to MOS (14/29)

  15. Body Effect  Recall that Drain-Body and Source-Body diodes should be reversed biased. o We assumed that Source is connected to the body ( v SB = 0) and v DS = v DB > 0  In a chip (same body for all NMOS), it is impossible to connect all sources to the body (all NMOS sources are connected together.  Thus, the body (for NMOS) is connected to the largest negative voltage (negative terminal of the power supply).  Doing so, changes the threshold voltage (called “Body Effect”) ( ) = + γ φ + − φ V V | 2 V | | 2 | tn tn , 0 F SB F  In this course we will ignore body effect as well as other second- order effects such as velocity saturation. F. Najmabadi, ECE65, Winter 2013, Intro to MOS (15/29)

  16. P-channel Enhancement MOS (PMOS)  A PMOS can be constructed analogous to an NMOS: (n-type body), heavily doped p-type source and drain.  A virtual “p-type” channel is formed in a P-MOS (holes are carriers in the channel) by applying a negative v GS .  i-v characteristic equations of a PMOS is similar to the NMOS with the exception: o Voltages are negative (we switch the terminals to have positive voltages: use v SG instead of v GS ). o Use mobility of holes, µ p , instead of µ n in the expression for i D F. Najmabadi, ECE65, Winter 2013, Intro to MOS (16/29)

  17. MOS Circuit symbols and conventions NMOS PMOS F. Najmabadi, ECE65, Winter 2013, Intro to MOS (17/29)

  18. MOS i-v Characteristics Equations NMOS ( V OV = v GS – V tn ) ≤ = Cut - Off : V 0 i 0 OV D [ ] W ≥ ≤ = µ − 2 Triode : V 0 and v V i 0 . 5 C 2 V v v OV DS OV D n ox OV DS DS L W [ ] ≥ ≥ = µ + λ 2 Saturation : V 0 and v V i 0 . 5 C V 1 v OV DS OV D n ox OV DS L PMOS ( V OV = v SG – | V tp | )* ≤ = Cut - Off : V 0 i 0 OV D [ ] W ≥ ≤ = µ − 2 Triode : V 0 and v V i 0 . 5 C 2 V v v OV SD OV D p ox OV SD SD L W [ ] ≥ ≥ = µ + λ 2 Saturation : V 0 and v V i 0 . 5 C V 1 v OV SD OV D p ox OV SD L *Note: S&S defines | V OV |= v SG – | V tp | and uses | V OV | in the PMOS formulas. F. Najmabadi, ECE65, Winter 2013, Intro to MOS (18/29)

  19. MOS operation is “Conceptually” similar to a BJT -- i D & v DS are controlled by v GS Controlled part: i D & v DS are set by transistor state (& outside circuit) Controller part: Circuit connected to GS sets v GS (or V OV )  A similar solution method to BJT: o Write down GS-KVL and DS-KVL, assume MOS is in a particular state, solve with the corresponding MOS equation and validate the assumption.  MOS circuits are simpler to solve because i G = 0 ! o However, we get a quadratic equation to solve if MOS in triode (check MOS in saturation first!) F. Najmabadi, ECE65, Winter 2013, Intro to MOS (19/29)

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