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Review: Conditional Probability Conditional Probability The conditional probability of event given event is = Pr(E ) Pr Pr() Well defined only if Pr Sofya Raskhodnikova; Randomness in


  1. Review: Conditional Probability Conditional Probability The conditional probability of event ๐น given event ๐บ is = Pr(E โˆฉ ๐บ) Pr ๐น ๐บ โ‹… Pr(๐บ) Well defined only if Pr ๐‘ฎ โ‰  ๐Ÿ Sofya Raskhodnikova; Randomness in Computing 1/23/2020

  2. Review question Card dealing We deal two cards. What is the probability that the second card is an ace, given that the first is an ace? A. 3/52 B. 3/51 C. 4/52 D. 5/52 E. None of the answers above are correct. Sofya Raskhodnikova; Randomness in Computing 1/23/2020

  3. Product rule For any two events ๐น 1 and ๐น 2 , Pr ๐น 1 โˆฉ ๐น 2 = Pr(๐น 1 ) โ‹… Pr ๐น 2 |๐น 1 . For all events ๐น 1 , โ€ฆ , ๐น ๐‘œ , ๐‘œโˆ’1 ๐น ๐‘— ) ๐‘œ Pr(โˆฉ ๐‘—=1 ๐น ๐‘— ) = Pr ๐น 1 โ‹… Pr ๐น 2 ๐น 1 โ‹… โ€ฆ โ‹… (๐น ๐‘œ | โˆฉ ๐‘—=1 Sofya Raskhodnikova; Randomness in Computing 1/23/2020

  4. Law of Total Probability For any two events ๐ต and ๐น, Pr ๐ต = Pr(๐ต โˆฉ ๐น) + Pr(๐ต โˆฉ ๐น) = Pr(๐ต|๐น) โ‹… Pr ๐น + Pr(๐ต|๐น) โ‹… Pr ๐น Let A be an event and let ๐น 1 , โ€ฆ , ๐น ๐‘œ be mutually disjoint events whose union is ฮฉ . Pr(๐ต) = Pr(๐ต โˆฉ ๐น ๐‘— ) = Pr(๐ต โˆฃ ๐น ๐‘— ) โ‹… Pr(๐น ๐‘— ) . ๐‘—โˆˆ ๐‘œ ๐‘—โˆˆ ๐‘œ Sofya Raskhodnikova; Randomness in Computing 1/23/2020

  5. Bayesโ€™ Law For any two events ๐ต and ๐น with Pr(A) โ‰  0, Pr ๐น|๐ต = Pr(๐ต|๐น) โ‹… Pr(๐น) Pr(๐ต) Let A be an event with Pr(A) โ‰  0 and let ๐น 1 , โ€ฆ , ๐น ๐‘œ be mutually disjoint events whose union is ฮฉ . ๐‘˜ |๐ต) = Pr(๐น ๐‘˜ โˆฉ ๐ต) Pr(๐ต|๐น ๐‘˜ ) โ‹… Pr(๐น ๐‘˜ ) Pr(๐น = ๐‘—โˆˆ ๐‘œ Pr(๐ต โˆฃ ๐น ๐‘— ) โ‹… Pr(๐น ๐‘— ) Pr(๐ต) Sofya Raskhodnikova; Randomness in Computing 1/23/2020

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