quantum coulomb systems at the brink
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Quantum Coulomb systems at the Brink Dirk Hundertmark (based on - PowerPoint PPT Presentation

Quantum Coulomb systems at the Brink Dirk Hundertmark (based on joint work with Markus Lange (UBC) and Michal Jex (KIT)) CIRM: The Analysis of Complex Quantum Systems: Large Coulomb Systems and Related Matters. Karlsruhe Institute of Technology


  1. Quantum Coulomb systems at the Brink Dirk Hundertmark (based on joint work with Markus Lange (UBC) and Michal Jex (KIT)) CIRM: The Analysis of Complex Quantum Systems: Large Coulomb Systems and Related Matters. Karlsruhe Institute of Technology – Institute for Analysis // CRC 1173 Wave Phenomena: Analysis and Numerics supported by the Deutsche Forschungsgemeinschaft (DFG) through CRC 1173.

  2. Outline The approach Outline � Some results. � Decay of eigenstates at thresholds: Repulsion is your friend � The physical heuristic. � Making the heuristic into a proof: One body operators. � Helium. 1 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  3. Outline The approach An atom The operator for an atom with nuclear charge Z is � � � � N e 2 1 j − Ze 2 mP 2 H = + | x j | | x j − x k | j = 1 1 ≤ j < k ≤ N P j = − i � ∇ j = − i � ∇ x j , the kinetic energy of particle j , m electron mass, Z nuclear charge. Real atoms: Z = ze , z ∈ N , helium: Z = 2 e , but in theory any Z > 0 allowed � . � Acts on L 2 ( R 3 N ) (either with or without symmetry constraints) � No spin, but this can be easily handled. 2 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  4. Outline The approach Scaling Let ( U λ ψ )( x ) ≔ λ 3 N ψ ( λ x ) , x = ( x 1 , · , x N ) ∈ R 3 N . Then U λ : L 2 ( R 3 N ) → L 2 ( R 3 N ) is unitary and � � � � � � N λ 2 � 2 λ e 2 (− ∆ j ψ )( λ x ) − Ze λ H ( U λ ψ )( λ x ) = λ 3 N | λ x j | ψ ( λ x ) | λ x j − λ x k | ψ ( λ x ) + 2 m j = 1 1 ≤ j < k ≤ N � N � � � � � = λ 3 N λ 2 � 2 2 me 2 2 mZ (− ∆ 2 j ψ )( λ x ) − � 2 λ | λ x j | ψ ( λ x ) � 2 λ | λ x j − λ x k | ψ ( λ x ) + 2 m j = 1 1 ≤ j < k ≤ N Choose λ = 2 mZ / � 2 , then � � = λ 3 N 2 mZ 2 2 mZ 2 � 2 [ H U ψ ] ( λ x ) = U λ � 2 H U ψ ( x ) / / with � � � � N j − 1 U P 2 H U = | x j − x k | , U = 1 / Z , P k = − i ∇ k . + | x j | 1 ≤ j < k ≤ N j = 1 3 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  5. Outline The approach Letś concentrate on helium, N = 2. So we will consider the operator � � � 2 j − 1 U P 2 H U = | x 1 − x 2 | , + | x j | j = 1 with U > 0 from now on. 4 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  6. Outline The approach Letś concentrate on helium, N = 2. So we will consider the operator � � � 2 j − 1 U P 2 H U = | x 1 − x 2 | , + | x j | j = 1 with U > 0 from now on. Known results: � Essential spectrum: σ ess ( H U ) = σ ( P 2 − | x | ) = [− 1 1 4 , ∞) , HVZ Theorem (Hunziker, van Winter, Zhislin). 4 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  7. Outline The approach Letś concentrate on helium, N = 2. So we will consider the operator � � � 2 j − 1 U P 2 H U = | x 1 − x 2 | , + | x j | j = 1 with U > 0 from now on. Known results: � Essential spectrum: σ ess ( H U ) = σ ( P 2 − | x | ) = [− 1 1 4 , ∞) , HVZ Theorem (Hunziker, van Winter, Zhislin). For Physicists: You reach the continuum spectrum once you kicked one electron to infinity! 4 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  8. Outline The approach Letś concentrate on helium, N = 2. So we will consider the operator � � � 2 j − 1 U P 2 H U = | x 1 − x 2 | , + | x j | j = 1 with U > 0 from now on. Known results: � Essential spectrum: σ ess ( H U ) = σ ( P 2 − | x | ) = [− 1 1 4 , ∞) , HVZ Theorem (Hunziker, van Winter, Zhislin). For Physicists: You reach the continuum spectrum once you kicked one electron to infinity! � If U = 1 there are infinitely many bound states below − 1 / 4. (Kato: More than 40.000, see e.g., Zhislin for full result ). 4 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  9. Outline The approach What about U > 1 ? Let E U = ground state energy of H U . Easy to see: 0 < U �→ E U is strictly increasing. So by convexity, it must ‘really increase’. 5 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  10. Outline The approach What about U > 1 ? Let E U = ground state energy of H U . Easy to see: 0 < U �→ E U is strictly increasing. So by convexity, it must ‘really increase’. � Bethe (1929): For some U > 1 one still has E U < − 1 / 4. � ⇒ there exists a critical U c > 1 with E U c = − 1 / 4. � ⇒ for any 1 < U < U c , the operator H U has a ground state ψ U with ground states energy E U < − 1 / 4. 5 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  11. Outline The approach What about U > 1 ? Let E U = ground state energy of H U . Easy to see: 0 < U �→ E U is strictly increasing. So by convexity, it must ‘really increase’. � Bethe (1929): For some U > 1 one still has E U < − 1 / 4. � ⇒ there exists a critical U c > 1 with E U c = − 1 / 4. � ⇒ for any 1 < U < U c , the operator H U has a ground state ψ U with ground states energy E U < − 1 / 4. � What happens with these ground states as U ր U c ? 5 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  12. Outline The approach What about U > 1 ? Let E U = ground state energy of H U . Easy to see: 0 < U �→ E U is strictly increasing. So by convexity, it must ‘really increase’. � Bethe (1929): For some U > 1 one still has E U < − 1 / 4. � ⇒ there exists a critical U c > 1 with E U c = − 1 / 4. � ⇒ for any 1 < U < U c , the operator H U has a ground state ψ U with ground states energy E U < − 1 / 4. � What happens with these ground states as U ր U c ? Theorem (Maria and Thomas Hoffmann-Ostenhof - Barry Simon (H 2 O 2 -S) 1984) There is binding for Helium at U c , that is, H U c has a ground state eigenfunction ψ U c ∈ L 2 ( R 6 ) and H U c ψ U c = − 1 4 ψ U c . 5 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  13. Outline The approach The result says nothing about how fast Ψ U c decays. 6 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  14. Outline The approach The result says nothing about how fast Ψ U c decays. Recall that with Agmon’s method one can show that as long as − 1 4 > E U = − ε U − 1 4 then | ψ U ( x 1 , x 2 )| � exp (−( 1 − ε ) ρ ( x )) for all 0 < ε < 1, ρ the Agmon distance ρ ( x ) = √ ε U � x ∞ � + 1 2 � x 0 � with � x ∞ � = max (� x 1 � , � x 2 �) (distance of the outer particle to the nucleus) and � x 0 � = min (� x 1 � , � x 2 �) (distance of the inner particle to the nucleus). This says nothing when U = U c , since then ε U c = 0. 6 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  15. Outline The approach Frank–Lieb–Seiringer found a different proof from the one by H 2 O 2 -S, which also yields a kind of localization result: Theorem (Frank-Lieb-Seiringer 2012) For any δ > 0 , there is a constant C δ > 0 such that for all 1 + δ ≤ U < U c and for all normalized ground states ψ U of H U one has � ψ U , � x ∞ � − 1 ψ U � ≥ C δ 7 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  16. Outline The approach Frank–Lieb–Seiringer found a different proof from the one by H 2 O 2 -S, which also yields a kind of localization result: Theorem (Frank-Lieb-Seiringer 2012) For any δ > 0 , there is a constant C δ > 0 such that for all 1 + δ ≤ U < U c and for all normalized ground states ψ U of H U one has � ψ U , � x ∞ � − 1 ψ U � ≥ C δ � By a compactness argument, this shows that a ground state at critical repulsion U = U c exists. � They have a similar result for bi-polarons and multi-polarons (for near energy minimizers). � Helium case got extended to atoms by Bellazzini–Frank–Lieb–Seiringer (2014). � Polaron case: no existence of bound states (in zero total momentum channel) Atoms: They need infinite nucleus mass approximation. 7 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  17. Outline The approach Our result for Helium Theorem (51 e , Markus Lange, Michal Jex 2019) There exist constants c 1 , c 2 > 0 such that the ground state at critical coupling obeys � � � ψ U c ( x ) � exp − c 1 � x ∞ � + c 2 log � x ∞ � 8 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

  18. Outline The approach Our result for Helium Theorem (51 e , Markus Lange, Michal Jex 2019) There exist constants c 1 , c 2 > 0 such that the ground state at critical coupling obeys � � � ψ U c ( x ) � exp − c 1 � x ∞ � + c 2 log � x ∞ � � These constants are quantitative (have a ‘physical meaning’....) � Similar result for atoms. � We do not need the infinite nuclear mass aproximation! � Similar result for multipolaron systems at critical coupling in the zero total momentum channel. 8 September 12, 2019 Dirk Hundertmark – The Brink KIT – Institute for Analysis // CRC 1173

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