SLIDE 1 Tidal Love numbers of Kerr black holes
Alexandre Le Tiec
Laboratoire Univers et Th´ eories Observatoire de Paris / CNRS
Collaborators: M. Casals & E. Franzin Submitted to PRL, gr-qc/2007.00214
SLIDE 2
Newtonian theory of Love numbers
U = M r M R
SLIDE 3
Newtonian theory of Love numbers
U = M r − 1 2xaxbEab M R Eab = −∂a∂bUext(0)
SLIDE 4
Newtonian theory of Love numbers
U = M r − 1 2xaxbEab + 3 2 xaxbQab r5 M R Eab = −∂a∂bUext(0) Qab
SLIDE 5
Newtonian theory of Love numbers
U = M r − 1 2xaxbEab + 3 2 xaxbQab r5 M R Eab = −∂a∂bUext(0) Qab = λ2Eab
SLIDE 6 Newtonian theory of Love numbers
U = M r − 1 2xaxbEab + 3 2 xaxbQab r5 M R Eab = −∂a∂bUext(0) Qab = λ2Eab = − 2
3k2R5Eab
SLIDE 7 Newtonian theory of Love numbers
U = M r − 1 2xaxbEab
R r 5 M R Eab = −∂a∂bUext(0) Qab = λ2Eab = − 2
3k2R5Eab
SLIDE 8 Newtonian theory of Love numbers
U = M r −
(ℓ − 2)! ℓ! xa1 · · · xaℓEa1···aℓ
R r 2ℓ+1 M R Eab = −∂a∂bUext(0) Qab = λ2Eab = − 2
3k2R5Eab
SLIDE 9 Newtonian theory of Love numbers
U = M r −
(ℓ − 2)! ℓ! rℓEℓm
R r 2ℓ+1 Yℓm M R Eab = −∂a∂bUext(0) Qab = λ2Eab = − 2
3k2R5Eab
SLIDE 10 Newtonian theory of Love numbers
ψ0 =
ℓ(ℓ − 1) rℓ−2 Eℓm
R r 2ℓ+1
2Yℓm
M R Eab = −∂a∂bUext(0) Qab = λ2Eab = − 2
3k2R5Eab
SLIDE 11 Newtonian theory of Love numbers
ψ0 =
ℓ(ℓ − 1) rℓ−2 Eℓm
R r 2ℓ+1
2Yℓm
M R Eab = −∂a∂bUext(0) Qab = λ2Eab = − 2
3k2R5Eab
SLIDE 12 Newtonian theory of Love numbers
ψ0 =
ℓ(ℓ − 1) rℓ−2 Eℓm
R r 2ℓ+1
2Yℓm
kℓm = k(0)
ℓ
+ imχ k(1)
ℓ
+ O(χ2) M R Eab = −∂a∂bUext(0) Qab = λ2Eab = − 2
3k2R5Eab
SLIDE 13 Newtonian theory of Love numbers
ψ0 =
ℓ(ℓ − 1) rℓ−2 Eℓm
R r 2ℓ+1
2Yℓm
Tidal Love numbers kℓm ← → body’s internal structure M R Eab = −∂a∂bUext(0) Qab = λ2Eab = − 2
3k2R5Eab
SLIDE 14
Internal structure of neutron stars
GW observations as probes of neutron star internal structure
SLIDE 15 Relativistic theory of Love numbers
- Electric-type and magnetic-type tidal moments:
EL ∝ ˆ C0a10a2;a3···aℓ and BL ∝ εa1bc ˆ Ca20bc;a3···aℓ
SLIDE 16 Relativistic theory of Love numbers
- Electric-type and magnetic-type tidal moments:
EL ∝ ˆ C0a10a2;a3···aℓ and BL ∝ εa1bc ˆ Ca20bc;a3···aℓ
- Metric and Geroch-Hansen multipole moments:
gαβ = ˚ gαβ + htidal
αβ
+ hresp
αβ
− → ML = ˚ ML + δML SL = ˚ SL + δSL
SLIDE 17 Relativistic theory of Love numbers
- Electric-type and magnetic-type tidal moments:
EL ∝ ˆ C0a10a2;a3···aℓ and BL ∝ εa1bc ˆ Ca20bc;a3···aℓ
- Metric and Geroch-Hansen multipole moments:
gαβ = ˚ gαβ + htidal
αβ
+ hresp
αβ
− → ML = ˚ ML + δML SL = ˚ SL + δSL
- Two families of tidal deformability parameters:
δML = λel
ℓ EL
and δSL = λmag
ℓ
BL
SLIDE 18 Relativistic theory of Love numbers
- Electric-type and magnetic-type tidal moments:
EL ∝ ˆ C0a10a2;a3···aℓ and BL ∝ εa1bc ˆ Ca20bc;a3···aℓ
- Metric and Geroch-Hansen multipole moments:
gαβ = ˚ gαβ + htidal
αβ
+ hresp
αβ
− → ML = ˚ ML + δML SL = ˚ SL + δSL
- Two families of tidal deformability parameters:
δML = λel
ℓ EL
and δSL = λmag
ℓ
BL
- Dimensionless tidal Love numbers:
kel/mag
ℓ
≡ −(2ℓ − 1)!! 2(ℓ − 2)! λel/mag
ℓ
R2ℓ+1
SLIDE 19 Love numbers of spinning compact objects
- The spin breaks the spherical symmetry of the background
- No proportionality between (δML, δSL) and (EL, BL)
- Degeneracy of the azimuthal number m lifted
- Parity mixing and mode couplings allowed
SLIDE 20 Love numbers of spinning compact objects
- The spin breaks the spherical symmetry of the background
- No proportionality between (δML, δSL) and (EL, BL)
- Degeneracy of the azimuthal number m lifted
- Parity mixing and mode couplings allowed
- Metric and Geroch-Hansen multipole moments:
gαβ = ˚ gαβ+htidal
αβ
+ hresp
αβ
− → Mℓm = ˚ Mℓm + δMℓm Sℓm = ˚ Sℓm + δSℓm
SLIDE 21 Love numbers of spinning compact objects
- The spin breaks the spherical symmetry of the background
- No proportionality between (δML, δSL) and (EL, BL)
- Degeneracy of the azimuthal number m lifted
- Parity mixing and mode couplings allowed
- Metric and Geroch-Hansen multipole moments:
gαβ = ˚ gαβ+htidal
αβ
+ hresp
αβ
− → Mℓm = ˚ Mℓm + δMℓm Sℓm = ˚ Sℓm + δSℓm
- Four families of tidal deformability parameters:
λME
ℓℓ′mm′ ≡ ∂δMℓm
∂Eℓ′m′ λSB
ℓℓ′mm′ ≡ ∂δSℓm
∂Bℓ′m′ λSE
ℓℓ′mm′ ≡ ∂δSℓm
∂Eℓ′m′ λMB
ℓℓ′mm′ ≡ ∂δMℓm
∂Bℓ′m′
SLIDE 22
Black holes have zero Love numbers
Reference Background Tidal field
[Binnington & Poisson 2009]
Schwarzschild weak, generic ℓ
[Damour & Nagar 2009]
Schwarzschild weak, generic ℓ
[Kol & Smolkin 2012]
Schwarzschild weak, electric-type
[Chakrabarti et al. 2013]
Schwarzschild weak, electric, ℓ = 2
[G¨ urlebeck 2015]
Schwarzschild strong, axisymmetric
[Landry & Poisson 2015]
Kerr to O(S) weak, quadrupolar
[Pani et al. 2015]
Kerr to O(S2) weak, (ℓ, m) = (2, 0) Problem of fine-tuning from an Effective-Field-Theory perspective
SLIDE 23 Investigating Kerr’s Love
(Eℓm, Bℓm) → ψ0 → Ψ → hαβ → (Mℓm, Sℓm) → λM/S,E/B
ℓm
Metric reconstruction through the Hertz potential Ψ M S = χM2 (Eℓm, Bℓm)
SLIDE 24 Perturbed Weyl scalar
- Recall that in the Newtonian limit we established
lim
c→∞ ψℓm
∝ Eℓm rℓ−2 1 + 2kℓm (R/r)2ℓ+1
2Yℓm(θ, φ)
- For a Kerr black hole the perturbed Weyl scalar reads
ψℓm ∝
3i ℓ+1 Bℓm
- Rℓm(r) 2Yℓm(θ, φ)
- Asymptotic behavior of general solution of static radial
Teukolsky equation: Rℓm(r) = rℓ−2 (1 + · · · )
ℓm
+ κℓm r−ℓ−3 (1 + · · · )
ℓm
SLIDE 25 Why analytic continuation?
Rℓm(r) = rℓ−2 (1 + · · · )
ℓm
+ κℓm r−ℓ−3 (1 + · · · )
ℓm
Ambiguity in the linear response [Fang & Lovelace 2005; Gralla 2018]
The decaying solution Rresp
ℓm
is affected by a radial coord. transfo.
Ambiguity in the tidal field [Pani, Gualtieri, Maselli & Ferrari 2015]
The growing solution Rtidal
ℓm +αRresp ℓm
still qualifies as a tidal solution
SLIDE 26 Kerr black hole linear response
Rℓm(r) = Rtidal
ℓm (r)
+ 2kℓm Rresp
ℓm (r) ∼r−(ℓ+3)
- The coefficients kℓm can be interpreted as the Newtonian
Love numbers of a Kerr black hole and read kℓm = −imχ (ℓ + 2)!(ℓ − 2)! 4(2ℓ + 1)!(2ℓ)!
ℓ
- n=1
- n2(1 − χ2) + m2χ2
- The linear response vanishes identically when:
- the black hole spin vanishes (χ = 0)
- the tidal field is axisymmetric (m = 0)
- Reconstruct the Kerr black hole response hresp
αβ via Ψresp
SLIDE 27 Love numbers of a Kerr black hole
- We compute the Love numbers to linear order in χ ≡ S/M2
SLIDE 28 Love numbers of a Kerr black hole
- We compute the Love numbers to linear order in χ ≡ S/M2
- The modes of the mass/current quadrupole moments are
δM2m . = imχ 180 (2M)5 E2m and δS2m . = imχ 180 (2M)5 B2m
SLIDE 29 Love numbers of a Kerr black hole
- We compute the Love numbers to linear order in χ ≡ S/M2
- The modes of the mass/current quadrupole moments are
δM2m . = imχ 180 (2M)5 E2m and δS2m . = imχ 180 (2M)5 B2m
- The black hole tidal bulge is rotated by 45◦ with respect to
the quadrupolar tidal perturbation
SLIDE 30 Love numbers of a Kerr black hole
- We compute the Love numbers to linear order in χ ≡ S/M2
- The modes of the mass/current quadrupole moments are
δM2m . = imχ 180 (2M)5 E2m and δS2m . = imχ 180 (2M)5 B2m
- The black hole tidal bulge is rotated by 45◦ with respect to
the quadrupolar tidal perturbation
- The associated dimensionless tidal Love numbers are
kME
2m = kSB 2m
. = −imχ 120 and kMB
2m = kSE 2m
. = 0
SLIDE 31 Love numbers of a Kerr black hole
- We compute the Love numbers to linear order in χ ≡ S/M2
- The modes of the mass/current quadrupole moments are
δM2m . = imχ 180 (2M)5 E2m and δS2m . = imχ 180 (2M)5 B2m
- The black hole tidal bulge is rotated by 45◦ with respect to
the quadrupolar tidal perturbation
- The associated dimensionless tidal Love numbers are
kME
2m = kSB 2m
. = −imχ 120 and kMB
2m = kSE 2m
. = 0
- For a dimensionless black hole spin χ = 0.1 this gives
|k2,±2| ≃ 2 × 10−3 − → black holes are “rigid”
SLIDE 32 Love tensor of a Kerr black hole
- For a nonspinning compact body we have the proportionality
relations δMab = λel
2 Eab
and δSab = λmag
2
Bab
- For a spinning black hole we have the more general tensorial
relations δMab = λabcdEcd and δSab = λabcdBcd
- To linear order in the black hole spin vector Sa we find
δMab . = 16 45 M3 ScEd
(aεb)cd
δSab . = 16 45 M3 ScBd
(aεb)cd
SLIDE 33 Love tensor of a Kerr black hole
(λabcd) . = χ 180 (2M)5 I11 I12 I13 I12 −I11 I23 I13 I23 I11 ≡ 1 1 I12 ≡ −1 +1 I13 ≡
1 2 1 2
I23 ≡ − 1
2
− 1
2
SLIDE 34 Newtonian static quadrupolar tide
Eab = µ r3 2 −1 −1 δMab . = 3Q 1 1 M S µ +q −q +q −q d d ↑
χ 180 (2M)5 µ r3 = qd2
SLIDE 35 Tidal torquing of a spinning black hole
[Thorne & Hartle 1980; Poisson 2004]
- An arbitrary spinning body interacting with a tidal
environment suffers a tidal torquing: ˙ Sa = −εabcMbdEd
c + SbdBd c
- Applied to a spinning black hole this yields
˙ S . = − 8 45 M5χ [2E1 + B1 − 3E2 + B2] M Sa (Eab, Bab)
SLIDE 36 Observing black hole tidal deformability
[Pani & Maselli 2019]
Accumulated GW phase in LISA band during quasi-circular inspiral down to Schwarzschild ISCO: Φtidal ≃ −2 × 103 10−7 µ/M
0.002
- like 1st order dissipative self-force
↑ k2 µ M
SLIDE 37 Summary
- Love numbers of Kerr black holes do not vanish in general
- We computed in closed-form the leading (quadrupolar) Love
numbers to linear order in the black hole spin
- Kerr black holes deform like any other self-gravitating body,
despite being particularly “rigid” compact objects
- This is closely related to the phenomenon of tidal torquing
- The black hole tidal deformation contribution to the GW
phase of EMRIs could be detectable by LISA
- New black hole test of the Kerr-like nature of the massive
compact objects at the center of galaxies Spinning black holes fall in Love!
SLIDE 38 Two basis of independent solutions
- Dimensionless radial coordinate and spin parameter:
x ≡ r − r+ r+ − r− and γ = a r+ − r−
- Smooth and unsmooth solutions:
Rsmooth
ℓm
= x−2(1 + x)−2 F(−ℓ − 2, ℓ − 1, −1 + 2imγ; −x) Runsmooth
ℓm
= (1 + 1/x)2imγ F(−ℓ + 2, ℓ + 3, 3 − 2imγ; −x)
- Tidal and response solutions:
Rtidal
ℓm
= xℓ (1 + x)2 F(−ℓ − 2, −ℓ − 2imγ, −2ℓ; −1/x) ∼ xℓ−2 Rresp
ℓm =
x−ℓ−1 (1 + x)2 F(ℓ − 1, ℓ + 1 − 2imγ, 2ℓ + 2; −1/x) ∼ x−ℓ−3
SLIDE 39 To Love or not to Love?
Rℓm(r) = rℓ−2 (1 + · · · )
ℓm
+ κℓm r−ℓ−3 (1 + · · · )
ℓm
SLIDE 40 To Love or not to Love?
Rℓm(r) = rℓ−2 (1 + · · · )
ℓm
+ κℓm r−ℓ−3 (1 + · · · )
ℓm
Eric Poisson is not in Love
- The growing solution Rtidal
ℓm
is not unique
- Specify it uniquely by requiring its smoothness
- Since Rℓm is smooth, he concludes that κℓm = 0
SLIDE 41 To Love or not to Love?
Rℓm(r) = rℓ−2 (1 + · · · )
ℓm
+ κℓm r−ℓ−3 (1 + · · · )
ℓm
Eric Poisson is not in Love
- The growing solution Rtidal
ℓm
is not unique
- Specify it uniquely by requiring its smoothness
- Since Rℓm is smooth, he concludes that κℓm = 0
Marc Casals and I are in Love
- Analytic continuation of ℓ ∈ R
- The growing/decaying solutions are specified uniquely
- Smoothness of Rℓm yields a response coefficient κℓm = 0
SLIDE 42 To Love or not to Love?
Rℓm(r) = rℓ−2 (1 + · · · )
ℓm
+ κℓm r−ℓ−3 (1 + · · · )
ℓm
Eric Poisson is not in Love
- The growing solution Rtidal
ℓm
is not unique
- Specify it uniquely by requiring its smoothness
- Since Rℓm is smooth, he concludes that κℓm = 0
Marc Casals and I are in Love
- Analytic continuation of ℓ ∈ R
- The growing/decaying solutions are specified uniquely
- Smoothness of Rℓm yields a response coefficient κℓm = 0
Edgardo Franzin has mixed feelings