techno economic study of simplified cooling time
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TECHNO-ECONOMIC STUDY OF SIMPLIFIED COOLING TIME ESTIMATION METHODS - PowerPoint PPT Presentation

IIR Student Competition International Congress of Refrigeration ICR2015 ICR2015 Yokohama, Japan TECHNO-ECONOMIC STUDY OF SIMPLIFIED COOLING TIME ESTIMATION METHODS APPLIED ON TWO-PHASE YOGURT MANUFACTURING TECHNOLOGY M. Okuli, M.


  1. IIR Student Competition – International Congress of Refrigeration ICR2015 ICR2015 Yokohama, Japan TECHNO-ECONOMIC STUDY OF SIMPLIFIED COOLING TIME ESTIMATION METHODS APPLIED ON TWO-PHASE YOGURT MANUFACTURING TECHNOLOGY M. Okulić, M. Ožegović and I. Zlatanović University of Belgrade – Faculty of Agriculture ICR2015 Yokohama, Japan

  2. COOLING TIME ESTIMATION IMPORTANCE ?  More efficient and economical operation of the cooling system for specific technology requirements;  Smaller capacity of refrigeration systems;  Energy savings;  Cost-effective production process.

  3. IMPORTANT PARAMETERS  Thermo-physical properties of food (heat conductivity, density and heat capacity)  Packaging material (size and shape) (plastic cup, carton box, cellophane, ...)  Cooling medium (water, air,...)  Refrigerant propeties

  4. SIMPLIFIED COOLING TIME CALCULATION METHODS 1. Cooling time estimation method based on f and j factors 2. Cooling time estimation method based on „ Equivalent Heat Transfer Dimensionality “ (EHTD)

  5. Cooling time estimation method based on f and j factors f and j factors represent the slope and j intercept, of the temperature history 2.0 curve. f 1.0 Factor j is a measure of the lag between 0.8 the onset of cooling and the exponential decrease in the temperature of the food. 0.6 Y 0.4 Factor f represents the time required to 0.3 obtain a 90% reduction in the non- 0.2  dimensional temperature difference (Y). T T  a Y  T T i a 0.1    0 10 20 30 40 50 60 f Y  , min.     ln   2.303 j - Cooling time

  6. Calculation of f and j factors for irregulary shaped products   3 1 1       – shape factor 2 4 G 0 . 25 L   2 2   8 A A 1 2  A 2 2 2 . 303 L  – f factor f   2 M 1 H A 1 L     2 0 . 0388 M j 0 . 892 e 1 – j factor

  7. Cooling time estimation method based on „ Equivalent Heat Transfer Dimensionality “ (EHTD) Cooling time estimation method based on EHTD is based on the comparison of the total heat transfer to the heat transfer through the shortest dimension.       2 3 c L j     - Cooling time ln       2 E Y  4 3 Bi 1.85  E - EHTD factor 4 3 1.85 Bi  E E  0

  8. Typical diary supply chain scheme Diary Farm Transport (processing factory) Transport Distribution Consumer Retail Transport depots Cold chain

  9. Two-phase yogurt manufacturing technology Pasteurization Reception 30 min at T=85 o C Filtration of the raw milk 10 min at T=95 o C Homogenization Separation mixing at 15 Mpa and cooling to T=43 o C Cream Skim milk Starter culture insertion Standardization at T=43 o C to acheive the desired % of fat content

  10. Small blast freezers Storage cold room

  11. Yogurt palette packaging Small blast freezer interior

  12. CALCULATION RESULTS Estimation m ethod based on f and j factors Input data: Dimension of yogurt cup ( diameter 2∙L and height H ) Ø55 x 63 mm - Shortest distance between cup center and cup surface L=0.0275 m - The minimum cross sectional area containing L A 1 =0.02375 m 2 - The cross sectional area that is orthogonal to A 1 A 2 =0.003465 m 2 - Biot number Bi=1.368 - The geometry index G=0.801 - The characteristic value M 1 2 =1.48 - Factor f f=13169 - Factor j j=0.842 - The fractional unaccomplished temperature difference Y=0.465 - Cooling time: 56.58 minutes

  13. CALCULATION RESULTS Estimation m ethod based on EHTD Input data: Yogurt cup radius L=0.0275 m - Biot number Bi=1.368 - Value of ω ω =1.776 - Form factor for Bi=0 E 0 =2.74 - Form factor for Bi → ∞ E ∞ =2.04 - (second shortest dimension of food item)/(shortest β 1 =1.15 - dimension of food item) (longest dimension of food item)/(shortest dimension of β 2 =1.15 - food item) Factor j j=0.842 - The fractional unaccomplished temperature difference Y=0.465 - Cooling time: 53.11 minutes

  14. The yogurt cup radius variation impact on cooling time

  15. CONCLUSION  Simplified cooling time calculation methods represents very usefull and reliable tool for the refrigeration system dimensioning.  Dimension, shape and geometry of cooled product has great influence on cooling process.  The type and form of packaging must be considered during the product design phase, when the application of these methodes can be of importance.  This will bring financial savings in the production process due to the higher energy efficiency of the system.

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