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Plan for today 1st half NP-Complete Problems A sampling of some NP Complete Problems 2nd half Final review Course evaluations. The Church-Turing Thesis Lets Review (1936) The Turing Machine Any algorithmic


  1. Plan for today  1st half NP-Complete Problems  A sampling of some NP Complete Problems  2nd half  Final review  Course evaluations. The Church-Turing Thesis Let’s Review… (1936)  The Turing Machine  Any algorithmic procedure that can be carried out by a human or group of  Build a theoretical a “human computer”  Likened to a human with a paper and pencil that can solve humans can be carried out by some problems in an algorithmic way Turing Machine”  The theoretical machine provides a means to determine:  If an algorithm or procedure exists for a given problem  Equating algorithm with running on a TM  What that algorithm or procedure looks like  Turing Machine is still a valid  How long would it take to run this algorithm or procedure. computational model for most modern computers. Are you a good witch? The class P  So what should be the cutoff between a “good”  The class P contains all decision problems that are algorithm and a “bad” algorithm? decidable by an “algorithm” that runs in polynomial time.  In the 1960s, Jack Edmonds proposed:  A “good” algorithm is one whose running time is a polynomial  Does this define a class of languages? function of the size of the input  Yes…  Other algorithms are “bad”  The set of all problems whose encodings of “yes instances” (a  This definition was adopted: language) is recognized by a TM M  A problem is called tractable if there exists a “good”  M recognizes the above language in Polynomial Time. (polynomial time) algorithm that solves it.  Recall: These languages are recursive  A problem is called intractable otherwise. 1

  2. Non-deterministic TM Non-deterministic TM  Let’s reconsider the NDTM  Same as the ordinary TM except:  The transition function will return a set of triplets  (q, x, D)  For each state / symbol combination, 0 or more transitions can be defined.  The machine can “choose” which transition to take. Non- deterministic TM δ : Q x Γ → 2 Q x Γ x {R, L}  Reducing one language to The class NP another  The class NP contains all decision problems that are  Worked well for decidability…Let’s use it here. decidable by a non-deterministic “algorithm” that  Basic idea runs in polynomial time.  Take an encoding of one problem  For each w accepted, there is at least one accepting  Convert it to another problem we know to be in P or NP sequence that will run in polynomial time.  Conversion must be done in polynomial time!  Does this define a class of languages? -- Yes…  The set of all problems whose encodings of “yes instances” (a language) is recognized by a NDTM M  M recognizes the above language in Polynomial Time. Reducing one language to The class NP-complete another  The hardest of the problems in class NP are in the class of NP-complete problems:  A language L is in NP if Instance Corresponding Conversion  L ∈ NP of P 1 TM TM  For every other language L 1 ∈ NP Instance of P 2 recognizing  L 1 ≤ p L Runs in Ptime L 2  All NP-complete problems are “equally” difficult. Runs in Ptime YES NO 2

  3. The class NP-complete Satisfiability (SAT)  Implications  INSTANCE  Hardest problem  A Logical expression containing  It’s probably not worth looking for a solution for  variables x i an NP-complete problem  logical connectors &, |, and !  How do we show a problem to be NP-complete  PROBLEM  Reduction  We need a NP-complete problem to kick things off.  Is there an assignment of truth values to each of the variables such that the expression will evaluate to true. Theory Hall of Fame Cook’s Theorem  Steven Cook  SATISFIABILITY is NP-Complete  A local boy  Reduced any TM in NP to SAT  b. Buffalo, NY.  Shown by describing workings of a NDTM  PhD – Harvard (1966) as an expression involving boolean  At Berkley from 1966-1970 variables  At University of Toronto since 1970  Published this Theorem in 1971.  Now we have a problem to start the ball rolling! NP Complete Problems Lot’s of NP Complete Problems  When confronted with trying to show a  Why show that a problem is NP problem is NP-Complete complete.  There are lots to chose from which to  These problems are the hardest to solve. perform a reduction.  Unlikely you will find an efficient algorithm to solve them. Over 300 NP-Complete problems listed (and the book was published in 1979!) Wikipedia reports over 3000 known NP complete problems today 3

  4. The big 7 The Big Daddy  SATISFIABILITY (SAT)  Basic core of known NP-complete problems.  INSTANCE  A set of U boolean variables and a collection C  Basis for beginner in chosing a problem for of boolean clauses over U reduction  PROBLEM  Note: I will not cover the actual reductions  Is there a satisfying truth assignment for C?  See Garey and Johnson for details.  The one that started it all! Describing NP-Complete Problems The other 6  NAME: Name of problem  3-SATISFIABILITY (3SAT)  INSTANCE or INPUT  INSTANCE:  On what input is the problem defined.  Collection C = {c 1 ,c 2 , …, c m } of boolean clauses on a finite set of boolean variables U  PROBLEM or OUTPUT such that each c i contains exactly 3 variables.  Under what condition will the answer to the  PROBLEM: problem be “yes”.  REDUCED FROM:  Is there a truth assignment for U that satisfies all clauses of C  From what NP-Complete problem has this been  REDUCED FROM: SAT reduced 3SAT The other 6  3-DIMENSIONAL MATCHING (3DM)  Informally: Instance  A generalization of the “marriage” problem Corresponding Conversion of SAT  Given: TM Instance of 3SAT  n unmarried men Runs in Ptime  n unmarried women  a list of pairs of partners who would marry Boolean expression of SAT is satisfiable iff  Can you arrange n marriages that avoid corresponding boolean expression of 3SAT polygomy and makes everyone happy. is satisfiable. 4

  5. The other 6 The other 6  3-DIMENSIONAL MATCHING (3DM)  3-DIMENSIONAL MATCHING (3DM)  Marriage problem with an extra dimension (add a  INSTANCE: pet).  A set M ⊆ (W x X x Y) where W, X, Y are  Given: disjoint sets having the same number of  n unmarried men elements  n unmarried women  PROBLEM  n unowned pets  a list of triplets of partners who would marry and the pet  Does M contain a matching they want  A subset M’ ⊆ M such that M’ has the same size as M  Can you arrange n marriages, with a pet as a wedding and no 2 elements in M’ agree in any coordinate. gift, that avoid polygomy and makes everyone happy…including the pet!  REDUCED FROM: 3SAT The other 6 The other 6: Graph Algorithms  The next 3 are all related to graph  VERTEX COVER theory  The vertex cover of a graph G is a set of vertices V so that every edge of G is  Vertex Cover incident to at least one vertex in V.  Clique  Hamiltonian Circuit Mathworld The other 6: Graph Algorithms The other 6: Graph Algorithms  VERTEX COVER (VC)  CLIQUE  INSTANCE:  A clique of a graph G is any complete subgraph (any subset of vertices in which  A Graph G = (V,E) and integer k ≤ |V| each pair of graph vertices is connected by  PROBLEM: an edge)  Is there a vertex cover of size k or less on G  Subset of vertices V’ such that for each edge {u,v}, at least one of u and v belongs to V’  REDUCED FROM: 3SAT Mathworld 5

  6. The other 6: Graph Algorithms The other 6: Graph Algorithms  CLIQUE  HAMILTONIAN CIRCUIT  INSTANCE:  A Hamiltonian circuit is a cycle in an undirected graph which visits each vertex  A Graph G = (V,E) and integer k ≤ |V| exactly once and also returns to the  PROBLEM: starting vertex.  Does G contain a clique of size k or more.  A subset of vertices, V’ such that every 2 vertices in V’ are joined by an edge  REDUCED FROM: VC Mathworld The other 6: one from set The other 6: Graph Algorithms theory  HAMILTONIAN CIRCUIT (HC)  PARTITION  INSTANCE:  given a multiset S of integers, is there a way to partition S into two subsets S1 and  A Graph G = (V,E) S2 such that the sums of the numbers in  PROBLEM: each subset are equal?  Does G contain a hamiltonian circuit  The subsets S1 and S2 must form a  An ordering of all vertices <v 1 ,v 2 , …, v n > such that {v i , v j } is an edge and {v n , v 1 } is an edge. partition in the sense that they are disjoint  REDUCED FROM: VC and they cover S. The other 6: one from set theory The big 7  PARTITION SAT  INSTANCE:  A finite set A and a “size function” s(a) a ∈ A 3-SAT  PROBLEM:  Is there a subset A’ ⊆ A such that 3DM VC s ( a ) s ( a ) � � = a A ' a A A ' � � � HC PARTITION CLIQUE  REDUCED FROM: 3DM 6

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