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EI331 Signals and Systems Lecture 11 Bo Jiang John Hopcroft Center - PowerPoint PPT Presentation

EI331 Signals and Systems Lecture 11 Bo Jiang John Hopcroft Center for Computer Science Shanghai Jiao Tong University April 2, 2019 Contents 1. Mean-square Convergence of Fourier Series 2. Pointwise Convergence of Fourier Series 3. Fourier


  1. EI331 Signals and Systems Lecture 11 Bo Jiang John Hopcroft Center for Computer Science Shanghai Jiao Tong University April 2, 2019

  2. Contents 1. Mean-square Convergence of Fourier Series 2. Pointwise Convergence of Fourier Series 3. Fourier Series of Periodic Impulse Train 4. Filtering 1/34

  3. Best Mean-square Approximation Given orthonormal system { e 1 , . . . , e n } , best mean-square approximation of x by element in span { e 1 , . . . , e n } , i.e. by � n element of form y = a k e k is k = 1 � n y = � x , e k � e k , k = 1 with minimum mean-square error � n � x − y � 2 = � x � 2 − |� x , e k �| 2 . k = 1 2/34

  4. Geometry of Best Mean-square Approximation Orthogonal projection onto subspace span { e 1 , . . . , e n } Pythagorean theorem � n � x � 2 = |� x , e k �| 2 + � x − y � 2 x k = 1 x − y � x , e 2 � e 2 e 2 y e 1 O � x , e 1 � e 1 span { e 1 , e 2 } 3/34

  5. Convergence in Normed Vector Space In normed vector space ( V , � · � ) , sequence { x n } converges to x ∈ V if n →∞ � x n − x � = 0 lim We say x is the limit of { x n } and write x = lim n →∞ x n , x n → x , as n → ∞ . or Sequence { x n } ⊂ V is Cauchy sequence iff � x n − x m � → 0 , as n , m → ∞ . Theorem. Every convergent sequence is Cauchy. Proof. If x n → x , triangle inequality yields � x n − x m � ≤ � x n − x � + � x m − x � → 0 , as n , m → ∞ . 4/34

  6. Banach Space Normed vector space ( V , � · � ) is complete if every Cauchy sequence converges. Complete normed vector space is called Banach space. Examples of Banach spaces • ( R n , � · � p ) , ( C n , � · � p ) • DT signal space ℓ p = { x ∈ C Z : � x � p < ∞} with ℓ p norm • CT signal space L p = { x ∈ C R : � x � p < ∞} with L p norm • Space L 2 ( T ) of CT signals with period T and finite � average power, � x � 2 = 1 T | x ( t ) | 2 dt < ∞ T • Space C ( T ) of continuous T -periodic CT signals with L ∞ norm � x � ∞ = sup | x ( t ) | = sup | x ( t ) | . t ∈ [ 0 , T ] t ∈ R x n → x in L ∞ norm means uniform convergence 5/34

  7. Banach Space Examples of incomplete spaces • ( Q , | · | ) . Its completion is ( R , | · | ) • Space C ( T ) of continuous T -periodic CT signals with L 2 norm. Its completion is L 2 ( T ) ◮ periodic odd function with period T = 1  0 ≤ t ≤ 1  nt ,  n n ≤ 1 1 2 − 1 x n = 1 ,  n  1 2 − 1 n ≤ t ≤ 1 1 − nt , 2 ◮ x n ∈ C ( 1 ) ◮ x n converges to periodic square wave in L 2 norm ◮ but periodic square function not in C ( 1 ) Same vector space with different norms becomes different normed vector spaces, e.g ( C ( T ) , � · � ∞ ) vs. ( C ( T ) , � · � 2 ) 6/34

  8. Incompleteness of C ( T ) with L 2 Norm x n ( t ) 1 x n t 1 1 n − 1 x ( t ) 1 x t 1 − 1 �� � � 1 1 2 + 1 | x n ( t ) − x ( t ) | 2 dt ≤ 4 n n � x n − x � 2 2 = + n → 0 − 1 1 2 − 1 n n x ∈ L 2 ( 1 ) but x / ∈ C ( 1 ) . Also � x n − x � ∞ = 1 , ∀ n 7/34

  9. L 2 Convergence vs. Pointwise Convergence 1 n = 0 , k = 0 For n ≥ 0 and 0 ≤ k < 2 n , t 1 � 1 2 n ≤ t < k + 1 k n = 1 , k = 0 1 , 2 n x 2 n + k = t 0 , otherwise 1 1 n = 1 , k = 1 t 1 • x 2 n + k → 0 in L 2 norm 1 n = 2 , k = 0 1 t 1 � x 2 n + k − 0 � 2 = 2 n / 2 → 0 1 n = 2 , k = 1 t 1 • not convergent at any t 0 ∈ [ 0 , 1 ) 1 n = 2 , k = 2 ◮ ∀ n , ∃ k 1 s.t x 2 n + k 1 ( t 0 ) = 1 t ◮ ∀ n , ∃ k 0 s.t x 2 n + k 0 ( t 0 ) = 0 1 1 n = 2 , k = 3 t 1 8/34

  10. Hilbert Space Inner product space ( V , �· , ·� ) is also normed vector space � with induced norm � x � = � x , x � . ( V , �· , ·� ) is complete if ( V , � · � ) with induced norm is complete. Complete inner produce space is called Hilbert space. Examples of Hilbert spaces • R n with � x , y � = � n k = 1 x k y k ; C n with � x , y � = � n k = 1 x k ¯ y k • Space ℓ 2 with � x , y � = � ∞ k = −∞ x k ¯ y k � • Space L 2 with � x , y � = R x ( t ) y ( t ) dt � • Space L 2 ( T ) with � x , y � = 1 T x ( t ) y ( t ) dt T Example of incomplete space � • Space C ( T ) with � x , y � = 1 T x ( t ) y ( t ) dt T L 2 ( T ) is completion of C ( T ) . 9/34

  11. Complete Orthonormal Sequence Orthonormal sequence { e k : k ∈ N } in Hilbert space H is complete if every x ∈ H has expansion � ∞ x = � x , e k � e k k = 1 i.e. � n n →∞ � x − lim � x , e k � e k � = 0 k = 1 Complete orthonormal sequence also called orthonormal basis of H . Example. { δ k : k ∈ Z } is orthonormal basis of ℓ 2 10/34

  12. Parseval’s Identity If { e k : k ∈ N } orthonormal basis of H , � ∞ � x � 2 = |� x , e k �| 2 k = 1 Proof. By Pythagorean theorem � n � n � x � 2 = |� x , e k �| 2 + � x − � x , e k � e k � 2 k = 1 k = 1 Let n → ∞ and last term goes to zero by definition of orthonormal basis. 11/34

  13. Parseval’s Identity H is isomorphic to ℓ 2 , x ↔ {� x , e k � : k ∈ N } and � ∞ � x , y � = � x , e k �� y , e k � k = 1 Proof. � � � x , y � = � � x , e k � e k , � y , e m � e m � k m � � = � x , e k � � y , e m �� e k , e m � k m � � = � x , e k � � y , e m � δ [ k − m ] k m � = � x , e k �� y , e k � k NB. When x = y , we recover � x � 2 = � ∞ k = 1 |� x , e k �| 2 12/34

  14. Mean-square Convergence of Fourier Series T t : k ∈ Z } is orthonormal basis of L 2 ( T ) . Theorem. { e jk 2 π For any x ∈ L 2 ( T ) , Fourier series converges in mean-square, i.e. in L 2 norm N →∞ � x − S N ( x ) � = 0 lim NB. Convergence in mean-square does not imply pointwise convergence Parseval’s identity � � ∞ x [ k ] | 2 = � x � 2 = 1 | x ( t ) | 2 dt | ˆ T T k = −∞ Interpretation: Energy conservation x [ k ] | 2 is average power of k -th harmonic component • | ˆ • � x � 2 is average power of x 13/34

  15. Fourier Series of L 2 Signals Correspondence between periodic functions and doubly infinite sequences; time domain vs. frequency domain FS FS ← − − → ˆ or x ( t ) ← − − → ˆ x [ k ] x x Fourier series is isomorphism between Hilbert space of L 2 signals and Hilbert space of ℓ 2 Fourier coefficients FS : L 2 ( T ) → ℓ 2 x �→ ˆ x Will see discrete-time Fourier transform goes from ˆ x to x Parseval’s theorem � x , y � L 2 ( T ) = � ˆ x , ˆ y � ℓ 2 14/34

  16. Contents 1. Mean-square Convergence of Fourier Series 2. Pointwise Convergence of Fourier Series 3. Fourier Series of Periodic Impulse Train 4. Filtering 15/34

  17. Integral Representation of Partial Sum WLOG, focus on T = 2 π and ω 0 = 1 N � x [ k ] e jkt S N ( x )( t ) = ˆ k = − N � 1 � � � N x ( τ ) e − jk τ d τ e jkt = 2 π 2 π k = − N � � N = 1 e jk ( t − τ ) d τ x ( τ ) 2 π 2 π k = − N � = 1 x ( τ ) D N ( t − τ ) d τ = ( x ∗ D N 2 π )( t ) 2 π 2 π where D N is Dirichlet kernel � N e jkt = sin(( N + 1 2 ) t ) D N ( t ) = sin( t / 2 ) k = − N 16/34

  18. Dirichlet Kernel Plot of D N 2 π for various N t t t N = 4 N = 8 N = 16 If D N 2 π → δ (more precisely, periodic impulse train on slide 22), then would have S N ( x ) = x ∗ D N 2 π → x ∗ δ = x at least for continuous x Unfortunately, exists continuous x whose Fourier partial sum S N ( x ) , as N → ∞ , fails to converge at all at some t , let alone converges to x ( t ) at such t 17/34

  19. Pointwise Convergence Theorem. If x is differentiable, then lim N →∞ S N ( x )( t ) = x ( t ) , ∀ t . Proof. Fix t . Define  x ( t − τ ) − x ( t )  , τ � = 0 F ( τ ) = sin( τ/ 2 )  − 2 x ′ ( t ) , τ = 0 � π 1 which is continuous on [ − π, π ] . Note − π D N ( τ ) d τ = 1 . 2 π � π � π S N ( x )( t ) − x ( t ) = 1 x ( t − τ ) D N ( τ ) d τ − 1 x ( t ) D N ( τ ) d τ 2 π 2 π − π − π � π = 1 [ x ( t − τ ) − x ( t )] D N ( τ ) d τ 2 π − π � π � � = 1 ( N + 1 F ( τ ) sin 2 ) τ d τ 2 π − π 18/34

  20. Pointwise Convergence Theorem. If x is differentiable, then lim N →∞ S N ( x )( t ) = x ( t ) . Proof (cont’d). Define y ( τ ) = e − j τ 2 F ( τ ) . � π � � S N ( x )( t ) − x ( t ) = 1 ( N + 1 F ( τ ) sin 2 ) τ d τ 2 π − π � π = − Im 1 y ( τ ) e − jN τ d τ 2 π − π = − Im ˆ y [ N ] Being continuous on [ − π, π ] , y ( τ ) ∈ L 2 ( 2 π ) . Bessel’s inequality implies ˆ y [ N ] → 0 , so S N ( x )( t ) − x ( t ) = − Im ˆ y [ N ] → 0 , as N → ∞ 19/34

  21. Dirichlet Test Theorem. If x satisfies following Dirichlet conditions 1. x is bounded, i.e. � x � ∞ < ∞ , 2. x is piecewise monotone, i.e. ∃ finite partition of a period s.t. x is monotone on each segment, then N →∞ S N ( x )( t ) = x ( t + ) + x ( t − ) lim 2 Example. x ( t ) 1 t 1 − 1  t ∈ ( n , n + 1  1 , 2 ) ,  N →∞ S N ( x )( t ) = lim t ∈ ( n − 1 , n ∈ Z − 1 , 2 , n ) ,   t = n 0 , 2 , 20/34

  22. Contents 1. Mean-square Convergence of Fourier Series 2. Pointwise Convergence of Fourier Series 3. Fourier Series of Periodic Impulse Train 4. Filtering 21/34

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