1 EE361: SIGNALS AND SYSTEMS II CH5: DISCRETE TIME FOURIER TRANSFORM http://www.ee.unlv.edu/~b1morris/ee361
2 FOURIER TRANSFORM DERIVATION CHAPTER 5.1-5.2
3 FOURIER SERIES REMINDER ο‘ Previously, FS allowed representation of a periodic signal as a linear combination of harmonically related exponentials π π = 1 π Ο π=<π> π¦ π π βπππ 0 π ππ’ ο‘ π¦[π] = Ο π=<π> π π π πππ 0 π 2π ο‘ π 0 = π ο‘ Would like to extend this (Transform Analysis) idea to aperiodic (non-periodic) signals
4 DT FOURIER TRANSFORM DERIVATION ο‘ Intuition (same idea as CTFT): ο‘ Consider a finite signal π¦[π] ο‘ Periodic pad to get periodic signal ΰ·€ π¦[π] ο‘ Find FS representation of ΰ·€ π¦[π] ο‘ Analyze FS as π β β (π 0 β 0) to get DTFT ο‘ Note DTFT is discrete in time domain β continuous in frequency domain ο‘ Envelope π(π ππ ) of normalized FS coefficients {π π π} defines the DTFT (spectrum of π¦[π] )
5 DT FOURIER TRANSFORM PAIR 1 2π π π ππ π πππ ππ synthesis eq (inverse FT) ο‘ π¦[π] = 2π Χ¬ ο‘ π π ππ = Ο π=ββ β π¦ π π βπππ analysis eq (FT) ο‘ DTFT is discrete in time β continuous in frequency ο‘ Notice the DTFT π(π ππ ) is period with period 2π
6 DTFT CONVERGENCE ο‘ The FT converges if absolutely summable ο‘ Ο π π¦ π < β 2 < β finite energy ο‘ Ο π π¦ π ο‘ iFT has not convergence issues because π π ππ is periodic ο‘ Integral is over a finite 2π period (similar to FS)
7 FT OF PERIODIC SIGNALS ο‘ Important property ο‘ π¦ π = π πππ 0 π β π ππ = Ο π=ββ β 2ππ π β ππ 0 β 2ππ ο‘ Impulse at frequency ππ 0 and 2π shifts ο‘ Transform pair ο‘ Ο π=<π> π π π πππ 0 π β 2π Ο π=ββ β π π π π β ππ 0 ο‘ Each π π coefficient gets turned into a delta at the harmonic frequency
8 DTFT PROPERTIES AND PAIRS CHAPTER 5.3-5.6
9 PROPERTIES/PAIRS TABLES ο‘ Most often will use Tables to solve problems ο‘ Table 5.1 pg 391 β DTFT Properties ο‘ Table 5.2 pg 392 β DTFT Transform Pairs
10 NOTEWORTHY PROPERTIES ο‘ Periodicity β π π ππ = π π π π+2π ο‘ Time shift β π¦ π β π 0 β π βπππ 0 π π ππ ο‘ Frequency/phase shift β π ππ 0 π π¦ π β π π π πβπ 0 ο‘ Convolution β π¦ π β π§ π β π π ππ π π ππ 1 2π π π ππ π π π πβπ ο‘ Multiplication β π¦ π π§ π β ππ 2π Χ¬ ο‘ Notice this is an integral over a single period ο periodic convolution 1 2π π π ππ β π π ππ
11 NOTEWORTHY PAIRS I ο‘ Decaying exponential ο‘ β π = π π π£[π] π < 1 ο‘ Magnitude response
12 DECAYING EXPONENTIAL ο‘ 0 < π < 1 ο‘ β1 < π < 0 ο‘ Lowpass filter ο‘ Highpass filter
13 NOTEWORTHY PAIRS II ο‘ Impulse ο‘ π¦ π = π[π] β π π ππ = Ο π π π π βπππ = Ο π π π π βππ 0 = Ο π π π = 1 ο‘ π¦ π = π π β π 0 β π π ππ = Ο π π π β π 0 π βπππ = Ο π π π β π 0 π βπππ 0 = π βπππ 0 ο‘ Rectangle pulse sin π 2π1+1 ο‘ π¦ π = α1 π β€ π 1 β π π ππ = Ο π=βπ 1 π βπππ = π 1 2 sin π 0 π > π 1 2 ο‘ Periodic signal ο‘ π¦ π = Ο π=<π> π π π πππ 0 π β π π ππ = 2π Ο π=ββ β π π π π β ππ 0 ο‘ One period of π π copied
14 DTFT AND LTI SYSTEMS CHAPTER 5.8
15 GENERAL DIFFERENCE EQUATION SYSTEM ο‘ Solve for frequency response ο‘ Take FT of both sides ο‘ Rational form β ratio of polynomials in e βππ ο‘ Best solved using partial fraction expansion (Appendix A) ο‘ Note special heavy-side cover-up approach for repeated root
16 LTI SYSTEM APPROACH ο‘ Same techniques as in continuous case ο‘ π π ππ = πΌ π ππ π π ππ ο‘ Partial fraction expansion ο‘ Inverse FT with tables
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