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BCH Codes Saravanan Vijayakumaran sarva@ee.iitb.ac.in Department - PowerPoint PPT Presentation

BCH Codes Saravanan Vijayakumaran sarva@ee.iitb.ac.in Department of Electrical Engineering Indian Institute of Technology Bombay October 14, 2014 1 / 13 BCH Codes Discovered by Hocquenghem in 1959 and independently by Bose and Chaudhari


  1. BCH Codes Saravanan Vijayakumaran sarva@ee.iitb.ac.in Department of Electrical Engineering Indian Institute of Technology Bombay October 14, 2014 1 / 13

  2. BCH Codes • Discovered by Hocquenghem in 1959 and independently by Bose and Chaudhari in 1960 • Cyclic structure proved by Peterson in 1960 • Decoding algorithms proposed/refined by Peterson, Gorenstein and Zierler, Chien, Forney, Berlekamp, Massey. . . • We will discuss a subclass of BCH codes — binary primitive BCH codes 2 / 13

  3. Binary Primitive BCH Codes For positive integers m ≥ 3 and t < 2 m − 1 , there exists an ( n , k ) BCH code with parameters • n = 2 m − 1 • n − k ≤ mt • d min ≥ 2 t + 1 Definition Let α be a primitive element in F 2 m . The generator polynomial g ( x ) of the t -error-correcting BCH code of length 2 m − 1 is the least degree polynomial in F 2 [ x ] that has α, α 2 , α 3 , . . . , α 2 t as its roots. Let ϕ i ( x ) be the minimal polynomial of α i . Then g ( x ) is the LCM of ϕ 1 ( x ) , ϕ 2 ( x ) , . . . , ϕ 2 t ( x ) . 3 / 13

  4. Binary Primitive BCH Code of Length 7 • m = 3 and t < 2 3 − 1 = 4 • Let α be a primitive element of F 8 • For t = 1, g ( x ) is the least degree polynomial in F 2 [ x ] that has as its roots α, α 2 • α is a root of x 8 + x x 8 + x = x ( x + 1 )( x 3 + x + 1 )( x 3 + x 2 + 1 ) • Let α be a root of x 3 + x + 1 • The other roots of x 3 + x + 1 are α 2 , α 4 • For t = 1, g ( x ) = x 3 + x + 1 • For t = 2, g ( x ) is the least degree polynomial in F 2 [ x ] that has as its roots α, α 2 , α 3 , α 4 • The roots of x 3 + x 2 + 1 are α 3 , α 5 , α 6 • For t = 2, g ( x ) = ( x 3 + x + 1 )( x 3 + x 2 + 1 ) • For t = 3, g ( x ) is the least degree polynomial in F 2 [ x ] that has as its roots α, α 2 , α 3 , α 4 , α 5 , α 6 = ⇒ g ( x ) = ( x 3 + x + 1 )( x 3 + x 2 + 1 ) 4 / 13

  5. Binary Primitive BCH Code of Length 7 For a BCH code with parameters m and t , we have • n − k ≤ mt • d min ≥ 2 t + 1 t g ( x ) n − k mt d min 2 t + 1 x 3 + x + 1 1 3 3 3 3 ( x 3 + x + 1 )( x 3 + x 2 + 1 ) 2 6 6 7 5 ( x 3 + x + 1 )( x 3 + x 2 + 1 ) 3 6 9 7 7 Definition A degree m irreducible polynomial in F 2 [ x ] is said to be primitive if the smallest value of N for which it divides x N + 1 is 2 m − 1 Lemma The minimal polynomial of a primitive element is a primitive polynomial. 5 / 13

  6. Single Error Correcting BCH Codes are Hamming Codes We will prove this for m = 3. The proof of the general case is similar. Proof. • Consider a BCH code with parameter m = 3 and t = 1 • Let α be a primitive element of F 8 and a root of x 3 + x + 1 • The generator polynomial g ( x ) = x 3 + x + 1 • The code has length 7 and dimension 4 • A polynomial v ( x ) = v 0 + v 1 x + v 2 x 2 + · · · + v 6 x 6 is a code polynomial ⇐ ⇒ v ( x ) is a multiple of g ( x ) ⇐ ⇒ α is a root of v ( x ) ⇐ ⇒ v ( α ) = 0 ⇒ v 0 + v 1 α + v 2 α 2 + v 3 α 3 + · · · + v 6 α 6 = 0 v ( α ) = 0 ⇐ 6 / 13

  7. Single Error Correcting BCH Codes are Hamming Codes Proof continued. Power Polynomial Tuple � � 0 0 0 0 0 � � 1 1 1 0 0 � � 0 1 0 α α α 2 α 2 � � 0 0 1 α 3 � � 1 + α 1 1 0 α 4 α + α 2 � � 0 1 1 α 5 1 + α + α 2 � � 1 1 1 α 6 1 + α 2 � � 1 0 1 ⇒ v 0 + v 1 α + v 2 α 2 + v 3 α 3 + · · · + v 6 α 6 = 0 v ( α ) = 0 ⇐ v 0 v 0      1 0 0 1 0 1 1  v 1 v 1     � α 6 �  = 0 ⇐ 0 1 0 1 1 1 0  = 0 1 . . ⇐ ⇒ α · · ·   ⇒   .   .     . . 0 0 1 0 1 1 1   v 6 v 6 7 / 13

  8. Degree of Generator Polynomial Theorem For a binary primitive BCH code with parameters m , t and generator polynomial g ( x ) , deg [ g ( x )] ≤ mt. Proof. • g ( x ) = LCM { ϕ 1 ( x ) , ϕ 2 ( x ) , ϕ 3 ( x ) , . . . , ϕ 2 t ( x ) } • If i is an even integer, then i = i ′ 2 a where i ′ is odd α i ′ � 2 a ⇒ α i and α i ′ have the same minimal • α i = � = polynomial • Every even power of α has the same minimal polynomial as some previous odd power of α g ( x ) = LCM { ϕ 1 ( x ) , ϕ 3 ( x ) , ϕ 5 ( x ) , . . . , ϕ 2 t − 1 ( x ) } • Since deg ( ϕ i ) divides m , we have n − k ≤ mt 8 / 13

  9. Lower Bound on Minimum Distance • We want to show that if the generator polynomial has roots α, α 2 , · · · , α 2 t then d min ≥ 2 t + 1 • Suppose there exists a nonzero codeword v = ( v 0 , v 1 , . . . , v n − 1 ) of weight δ ≤ 2 t • The corresponding code polynomial satisfies v ( α i ) = 0 for i = 1 , 2 , 3 , . . . , 2 t v 0 + v 1 α + v 2 α 2 + · · · + v n − 1 α n − 1 = 0 v 0 + v 1 α 2 + v 2 α 4 + · · · + v n − 1 α 2 ( n − 1 ) = 0 . . . v 0 + v 1 α 2 t + v 2 α 4 t + · · · + v n − 1 α 2 t ( n − 1 ) = 0 • Let j 1 , j 2 , . . . , j δ be the nonzero locations in the codeword v j 1 ( α i ) j 1 + v j 2 ( α i ) j 2 + · · · + v j δ ( α i ) j δ = 0 for i = 1 , 2 , . . . , 2 t 9 / 13

  10. Lower Bound on Minimum Distance   α 2 � j 1 α 2 t � j 1 α j 1 � � · · · α 2 � j 2 α 2 t � j 2 α j 2  � �  · · ·    α 2 � j 3 α 2 t � j 3  � � α j 3 � � · · · · · · = 0 v j 1 v j 2 v j δ     . . .   . . . . . .     α 2 � j δ α 2 t � j δ α j δ � � · · ·   α j 1 � 2 α j 1 � 2 t α j 1 � � · · · α j 2 � 2 α j 2 � 2 t α j 2  � �  · · ·    α j 3 � 2 α j 3 � 2 t  � � α j 3 � � = ⇒ · · · · · · = 0 1 1 1     . . .   . . . . . .     α j δ � 2 α j δ � 2 t α j δ � � · · · 10 / 13

  11. Lower Bound on Minimum Distance   α j 1 � 2 α j 1 � δ α j 1 � � · · · α j 2 � 2 α j 2 � δ α j 2  � �  · · ·    α j 3 � 2 α j 3 � δ  � � α j 3 � � = ⇒ · · · · · · = 0 1 1 1     . . .   . . . . . .     α j δ � 2 α j δ � δ α j δ � � · · · � � α j 1 � 2 α j 1 � δ α j 1 � � · · · � � � � α j 2 � 2 α j 2 � δ α j 2 � � � � · · · � � � α j 3 � 2 α j 3 � δ � α j 3 � � = ⇒ · · · = 0 � � � � . . . � � . . . . . . � � � � α j δ � 2 α j δ � δ α j δ � � � � · · · � � 11 / 13

  12. Lower Bound on Minimum Distance α j 1 α ( δ − 1 ) j 1 � � 1 · · · � � α j 2 α ( δ − 1 ) j 2 � � 1 · · · � � � α j 3 α ( δ − 1 ) j 3 � ⇒ α ( j 1 + ··· + j δ ) 1 · · · = = 0 � � � . . . � . . . � � . . . � � � � α j δ α ( δ − 1 ) j δ 1 · · · � � • α j 1 + ··· + j δ � = 0 since α is a nonzero field element • The determinant is a Vandermonde determinant which is not zero • This contradicts our assumption that a nonzero codeword of weight δ ≤ 2 t exists 12 / 13

  13. Questions? Takeaways? 13 / 13

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