] 1 1 u (1) = G 1 ( 1 ) u (1) a s UC Irvine Geometric - PowerPoint PPT Presentation

Jan 10, 2024 •136 likes •177 views

u (1) = G 1 u (1) u (2) = G 2 u (2) u a = Gu s a s a s u a = 1 u (1) + 2 u (2) = 1 G 1 u (1) + 2 G 2 u (2) a a s s UC Irvine G 1 ( 1 ) = 0 . 5 [(1 1 ) G ( ) + (1 + 1 ) G (+) ] 1 1 u (1) = G 1 ( 1 ) u

u (1) = G 1 u (1) u (2) = G 2 u (2) u a = Gu s a s a s u a = η 1 u (1) + η 2 u (2) = η 1 G 1 u (1) + η 2 G 2 u (2) a a s s UC Irvine
G 1 ( η 1 ) = 0 . 5 ∗ [(1 − η 1 ) G ( − ) + (1 + η 1 ) G (+) ] 1 1 u (1) = G 1 ( η 1 ) u (1) a s UC Irvine
Geometric Conservation Law For deforming grids the folowing relation has to be satisfied in order to avoid influence of the grid motion on the flow solution: ∂ d Ω − V g · n dS = 0 ∂t Ω S UC Irvine

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