Pumping and population inversion - Laser amplification Gustav Lindgren 2015-02-12
Contents Part I: Laser pumping and population inversion Steady state laser pumping and population inversion 4-level laser Solve rate-equations in steady-state 3-level laser Laser gain saturation Introduce the upper-level model Upper-level laser Transient rate equations Solve rate-equations under Upper-level laser transients Three-level laser
Atomic transitions Energy-level diagram of Nd:YAG Simplify into ->
4-level laser Rate equations: Pumping - Decay ππ 4 ππ’ = π π π 1 β π 4 β π 4 /π 41 ππ 3 ππ’ = π 4 β π 3 Decay In/Out π 43 π 3 ππ 2 ππ’ = π 4 + π 3 β π 2 Same π 42 π 32 π 21 Atom conservation: π 1 + π 2 + π 3 + π 4 = π βOptical approximationβ, βπ/π πΆ π βͺ 1 No thermal occupancy
4-level laser At steady state: π 3 = π 3 π 4 π 43 Define beta π 21 + π 43 π 21 π 2 = π 3 β‘ πΎπ 3 π 32 π 42 π 3 For a good laser: No direct decay into lev2 πΏ 42 β 0 (π. π. π 42 β β) , β πΎ β π 21 β π 32 Fluorescent quantum efficiency, π β‘ π 4 β π 3 π 43 π π ππ Useful photons: from 4 -> upper laser * From upper laser that lase
4-level laser Calculate the pop. Inv. Population inversion, π 3 β π 2 1 β πΎ ππ π π π ππ = 1 + 1 + πΎ + 2π 43 π π π ππ ππ π π π ππ For a good laser: π 43 βͺ π π ππ - Short lev 4 lifetime πΎ β π 21 /π 32 β 0 - Short lower lev lifetime π β 1 - High fluorescent quantum efficiency π π π π ππ β π 3 β π 2 β π 1 + π π π π ππ - Red curves
3-level laser As before, for 3-level Rate equations: Pumping β decay BUT lower level is GROUND level ππ 3 π π 1 β π 3 β π 3 ππ’ = π π 3 ππ 2 ππ’ = π 3 β π 2 decays π 32 π 21 Atom conservation: π 1 + π 2 + π 3 = π as before π = π 3 π 21 As before π 32 π π ππ πΎ = π 3 = π 32 Different! π 2 π 21
3-level laser No pumping NEGATIVE pop. Inv. At steady state, -> 1 β πΎ ππ π π π ππ β 1 π 2 β π 1 = π π π ππ + 1 π 1 + 2πΎ ππ Requirements for pop. inversion: πΎ < 1 As before 1 π π π π ππ β₯ π 1βπΎ New For a good laser, πΎ β 0 π β 1 β π π π π ππ β 1 π 2 β π 1 π π π ππ + 1 π π Red curves
Population inversion All else equal: 3-level requires more pumping
Upper-level laser Lasing between two levels high above ground-level ππ 3 Pump into upper lev. = π π π 0 β π 3 ππ’ ππ£ππ Assuming, π 0 β π β« π 3 and pump efficiency, π π , ππ 3 most atoms in ground- β π π π π π β‘ π π state ππ’ ππ£ππ Rate equations: Signal included ππ 2 ππ’ = π π β π π‘ππ π 2 β π 1 β πΏ 2 π 2 ππ 1 ππ’ = π π‘ππ π 2 β π 1 + πΏ 21 π 2 β πΏ 1 π 1
Upper-level laser At steady state: π π‘ππ + πΏ 21 π 1 = π π π π‘ππ πΏ 1 + πΏ 20 + πΏ 1 πΏ 2 π π‘ππ + πΏ 1 π 2 = π π π π‘ππ πΏ 1 + πΏ 20 + πΏ 1 πΏ 2 No atom conservation! For example, changing pump changes N
Upper-level laser The pop. Inv. Saturates as the signal increases Population inversion: π π πΏ 1 β πΏ 21 Ξπ 21 = π 2 β π 1 = β 1 + πΏ 1 + πΏ 20 πΏ 1 πΏ 2 π π‘ππ πΏ 1 πΏ 2 πΏ 1 βπΏ 21 Define the small-signal population inversion, Ξπ 0 = πΏ 1 πΏ 2 π π and the effective recovery time, π πππ = π 2 1 + π 1 π 20 the expression becomes: 1 ΞN 21 = Ξπ 0 1 + π π‘ππ π πππ For a good laser: πΏ 2 β πΏ 21 πΏ 20 β 0 1 β ΞN 21 β π π π 2 β π 1 β 1 + π π‘ππ π 2 Prop. To pump-rate and lifetimes, saturation behavior
Upper-level laser β’ Condition for obtaining inversion, π 1 /π 21 < 1 i.e. fast relaxation from lower level and slow relaxation from upper level β’ Small-signal gain, π 2 Ξπ 0 βΌ π π β 1 β π 1 /π 21 i.e. small-signal gain is proportional to the pump-rate times a reduced upper-level lifetime β’ Saturation behavior, 1 Ξπ 21 = Ξπ 0 β 1 + π π‘ππ π πππ i.e. the saturation intensity depends only on the signal intensity and the effective lifetime , not on the pumping rate.
Upper-level laser: Transient rate equation As for instance before a Q-switched pulse Assume: No signal ( π π‘ππ = 0 ), fast lower-level relaxation ( π 1 β 0 ), ππ 2 π’ = π π π’ β πΏ 2 π 2 π’ ππ’ The upper level population becomes, π’ π π π’ β² π βπΏ 2 (π’βπ’ β² ) ππ’β² π 2 π’ = ββ Applying a square pulse, π = π π0 π 2 (1 β π βπ π /π 2 ) π 2 π Define the pump efficiency, = 1 β π βπ π /π 2 π π = π 2 π’ = π π π π0 π π π /π 2 π ^Pop. In upper lev per pump-photon
3-level laser: pulses 3-level laser from prev, no signal Assume: No signal ( π π‘ππ = 0 ), Fast upper-level relaxation ( π 3 β 0 ), ππ 1 ππ’ = β ππ 2 π π’ π 1 π’ + π 2 π’ ππ’ β βπ π π π π’ + 1 π π’ β 1 ππ’ Ξπ π’ = β π π Ξπ π’ + π π π Integrate to get pop. Inv: Square pulse: = (π π π β 1) β 2π π π β exp [β π π π + 1 π’/π] Ξπ π’ π π π π + 1 If pump pulse duration is short ( π π βͺ π ), and the pumping rate is high ( π π π β« 1 Simple model-agrees with experiment! Ξπ π π β 1 β 2π βπ π π π π
Summary Steady state laser pumping and population inversion 4-level laser π 3 β π 2 π π π π ππ Difference between three β π 1 + π π π π ππ and four-level systems, and 3-level laser why four-level systems are π π π π ππ β 1 π 2 βπ 1 superior β π π π ππ π 1 + π Saturation intensity is Laser gain saturation independent of the Upper-level laser, saturation behavior 1 pumping-rate βi.e. The signal intensity Ξπ 21 = Ξπ 0 β 1+π π‘ππ π πππ needed to reduce the pop. Inv. To half its initial value doesnβt depend on the pumping rateβ Short pulses are needed to Transient rate equations obtain high pumping Upper-level laser = 1 β π βπ π /π 2 π π = π 2 π’ = π efficiency π π π0 π π π /π 2 π Three-level laser These simple models give good agreement with Ξπ π π β 1 β 2π βπ π π π reality π
Contents Part II: Laser amplification Wave propagation in atomic media Solve wave-eqs Plane-wave approximation The paraxial wave equation Single-pass laser amplification Gain narrowing Transition cross-sections See effects on the gain Gain saturation Power extraction
Wave propagation in an atomic medium Maxwellβs equations: πΌπ¦π = βπππͺ πΌπ¦π° = π² + πππ¬ Material parameters: Constitutive relations: π β magnetic permeability πͺ = ππ° π β ohmic losses π² = ππ π β dielectric permittivity (not counting π¬ = ππ + πΈ ππ’ = π 1 + π ππ’ π atomic transitions) π ππ’ (π) β resonant susceptibility due Vector field of the form: to laser transitions π π, π’ = 1 2 π π π πππ’ + π. π Assume a spatially uniform material ( πΌ β πΉ = 0 ), and apply πΌ Γ to get the wave equation: ππ’ β ππ πΌ 2 + π 2 ππ 1 + π π¦, π§, π¨ = 0 πΉ ππ
Plane-wave approximation <- Ok approx. If Consider a plane wave, wavefront is flat π 2 πΉ ππ¦ 2 , π 2 πΉ ππ§ 2 βͺ π 2 πΉ ππ¨ 2 i.e. πΌ 2 β π 2 ππ¨ 2 The equation reduces to: ππ’ β ππ 2 + π 2 ππ 1 + π π¨ = 0 π π¨ πΉ ππ
Plane-wave approximation Without losses: First, no losses 2 + π 2 ππ πΉ π¨ = 0, π π¨ Assume solutions on the form: π¨ = ππππ‘π’ β π βΞπ¨ πΉ β Ξ 2 + π 2 ππ πΉ = 0 The allowed values for Ξ are, Ξ = Β±ππ ππ β‘ Β±ππΎ With the solution, π π¨, π’ = 1 + 1 2 πΉ + π π ππ’βπΎπ¨ + πΉ + 2 πΉ β π π ππ’+πΎπ¨ + πΉ β β π βπ ππ’+πΎπ¨ β π βπ ππ’βπΎπ¨ The free space propagation constant, πΎ, may be written: πΎ = π ππ = π π = 2π Different beta π from last chapter
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