normality and automata
play

Normality and Automata Olivier Carton LIAFA Universit e Paris - PowerPoint PPT Presentation

Normality and Automata Olivier Carton LIAFA Universit e Paris Diderot & CNRS Join work with Ver onica Becher and Pablo Heiber (Universidad de Buenos Aires & CONICET) Work supported by LIA Infinis AutoMathA 2015, Leipzig Outline


  1. Normality and Automata Olivier Carton LIAFA Universit´ e Paris Diderot & CNRS Join work with Ver´ onica Becher and Pablo Heiber (Universidad de Buenos Aires & CONICET) Work supported by LIA Infinis AutoMathA 2015, Leipzig

  2. Outline Normality Compressibility One-way transducers Two-way transducers Selection Prefix selection Suffix selection

  3. Expansion of real numbers Fix an integer base b � 2. The alphabet is A = { 0 , 1 , . . . , b − 1 } . ◮ if b = 2, A = { 0 , 1 } , ◮ if b = 10, A = { 0 , 1 , 2 , . . . , 9 } . Each real number ξ ∈ [0 , 1) has an expansion in base b : x = a 1 a 2 a 3 · · · where a i ∈ A and a k � ξ = b k . k ≥ 1 In the rest of this talk: infinite word x ∈ A ω real number ξ ∈ [0 , 1) ← → 010101 · · · = (01) ω 1 / 3 ← → π/ 4 ← → 1100100100001111 · · ·

  4. Normality (Borel 1909) The number of occurrences of a word u in a word w is occ( w, u ) = |{ i : w [ i..i + | u | − 1] = u }| An infinite word x ∈ A ω (resp. a real number ξ ) is simply normal (in base b ) if for any a ∈ A , occ( x [1 ..n ] , a ) = 1 lim b. n n →∞ An infinite word x ∈ A ω (resp. a real number ξ ) is normal (in base b ) if for any u ∈ A ∗ , occ( x [1 ..n ] , u ) 1 lim = b | u | . n n →∞ In base b = 2, this means ◮ the frequencies in x of the 2 digits 0 and 1 are 1 / 2, ◮ the frequencies in x of the 4 words 00 , 01 , 10 , 11 are 1 / 4, ◮ the frequencies in x of the 8 words 000 , 001 , . . . , 111 are 1 / 8, ◮ . . .

  5. Examples Theorem (Borel 1909) Almost all real numbers are normal, that is, the measure of the set of normal numbers in [0 , 1) is 1 . Examples ◮ the infinite word (001) ω = 0010010 · · · is not simply normal in base 2, ◮ the infinite word (01) ω = 01010 · · · is simply normal in base 2 but it is not normal, ◮ the Champernowne word 012345678910111213 · · · is normal in base 10. ◮ the Champernowne word 011011100101110111 · · · is normal in base 2.

  6. Transducers Input tape a 0 a 1 a 2 a 3 a 4 a 5 a 6 a 7 Q Output tape b 0 b 1 b 2 b 3 b 4 b 5 b 6 Transitions p a | v → q for a ∈ A , v ∈ B ∗ . − −

  7. Examples A transducer is an automaton T = � Q, A, B, ∆ , I, F � where ∆ is a finite set of transitions p a | v → q where a ∈ A and v ∈ A ∗ . − − Example (Compression of blocks of consecutive 1) 1 | 1 q 0 q 1 0 | 0 1 | ε 0 | 0 If the input is 010011000111 · · · , the output is 01001000100 · · · . Example (Division by 3 in base 2) 1 | 0 0 | 0 q 0 q 1 q 2 0 | 0 1 | 1 1 | 1 0 | 1 If the input is (01) ω , the output is (000111) ω .

  8. Example 1 | 1 q 0 q 1 0 | 0 1 | ε 0 | 0 0 1 1 0 0 1 1 1 0 q 0 0

  9. Example 1 | 1 q 0 q 1 0 | 0 1 | ε 0 | 0 0 1 1 0 0 1 1 1 0 q 0 0 1

  10. Example 1 | 1 q 0 q 1 0 | 0 1 | ε 0 | 0 0 1 1 0 0 1 1 1 0 q 1 0 1

  11. Example 1 | 1 q 0 q 1 0 | 0 1 | ε 0 | 0 0 1 1 0 0 1 1 1 0 q 1 0 1 0

  12. Example 1 | 1 q 0 q 1 0 | 0 1 | ε 0 | 0 0 1 1 0 0 1 1 1 0 q 0 0 1 0 0

  13. Example 1 | 1 q 0 q 1 0 | 0 1 | ε 0 | 0 0 1 1 0 0 1 1 1 0 q 0 0 1 0 0 1

  14. Example 1 | 1 q 0 q 1 0 | 0 1 | ε 0 | 0 0 1 1 0 0 1 1 1 0 q 1 0 1 0 0 1

  15. Example 1 | 1 q 0 q 1 0 | 0 1 | ε 0 | 0 0 1 1 0 0 1 1 1 0 q 1 0 1 0 0 1

  16. Example 1 | 1 q 0 q 1 0 | 0 1 | ε 0 | 0 0 1 1 0 0 1 1 1 0 q 1 0 1 0 0 1 0

  17. Transducers as compressors An infinite word x = a 1 a 2 a 3 · · · is compressible by a transducer a 1 | v 1 a 2 | v 2 a 3 | v 3 if there is an accepting run q 0 − − − → q 1 − − − → q 2 − − − → q 3 · · · satisfying | v 1 v 2 · · · v n | log | B | lim inf | a 1 a 2 · · · a n | log | A | < 1 . n →∞ Different notions of compressors ◮ the function x �→ T ( x ) is one-to-one ◮ deterministic lossless: the map u �→ ( v, q ) is one-to-one u | v q 0 q ◮ the function x �→ T ( x ) is bounded-to-one There is a constant K such that |{ x : T ( x ) = y }| � K .

  18. Characterization of normal words Theorem (Many people) An infinite word is normal if and only if it cannot be compressed by deterministic lossless transducers. ◮ Schnorr and Stimm (1971) non-normality ⇔ finite-state martingale success ◮ Dai, Lathrop, Lutz and Mayordomo (2004) compressibility ⇔ finite-state martingale success normality ⇒ no martingale success ◮ Bourke, Hitchcock and Vinodchandran (2005) non-normality ⇒ martingale success ◮ Becher and Heiber (2013) non-normality ⇔ compressibility (direct) ◮ Becher, Carton and Heiber generalized to bounded-to-one

  19. Randomness Randomness can be characterized as non-compressibility: lim inf n →∞ H ( x [1 ..n ]) − n > −∞ where H is the prefix Kolmogorov complexity of the finite word w . Normal infinite words are the random words for automata. Turing may compress some normal words (Champernowne’s). What is the real power needed to compress a normal word ?

  20. Ingredients Shannon (1958) ◮ frequency of u different from b −| u | implies non maximum entropy ◮ non-maximum entropy implies compressibility Huffman (1952) ◮ simple greedy implementation of Shannon’s general idea ◮ implementation by a finite state tranducer

  21. Deterministic vs Non-Deterministic transducers 0 | 1 0 | 0 q 0 q 1 q 2 0 | 0 1 | 1 1 | 1 1 | 0 Multiplication by 3 in base 2 Theorem Non-deterministic bounded-to-one transducers cannot compress normal infinite words.

  22. Counter transducers ◮ the transducer uses k -counters with integer values that can be incremented, decremented and tested for zero ◮ real-time restriction: incrementation and decrementation can only occur when a input symbol is processed Theorem Bounded-to-one counter transducers cannot compress normal infinite words. Non-real-time two-counter machines are Turing complete.

  23. Summary of the results det non-det non-rt finite-state N N N 1 counter N N N ≥ 2 counters N N T 1 stack ? C C 1 stack + 1 counter C C T where N means cannot compress normal words C means can compress some normal word T means is Turing complete and thus can compress.

  24. Two-way transducers Two-way ⊢ a 1 a 2 a 3 a 4 a 5 a 6 a 7 input tape Q One-way b 0 b 1 b 2 b 3 b 4 b 5 b 6 output tape → q for a ∈ A , v ∈ B ∗ and d ∈ { ⊳, ⊲ } . Transitions p a | v,d − − −

  25. Example: 0 n 0 10 n 1 10 n 2 1 · · · �→ 0 n 0 1 n 0 0 n 1 1 n 1 0 n 2 1 n 2 · · · ⊢| ε, ⊲ 0 | 0 , ⊲ 0 | ε, ⊳ 0 | 1 , ⊲ ⊢| ε, ⊲ 1 | ε, ⊲ 1 | ε, ⊳ q 0 q 1 q 2 1 | ε, ⊲ ⊢ 0 0 1 0 1 0 0 0 1 q 0

  26. Example: 0 n 0 10 n 1 10 n 2 1 · · · �→ 0 n 0 1 n 0 0 n 1 1 n 1 0 n 2 1 n 2 · · · ⊢| ε, ⊲ 0 | 0 , ⊲ 0 | ε, ⊳ 0 | 1 , ⊲ ⊢| ε, ⊲ 1 | ε, ⊲ 1 | ε, ⊳ q 0 q 1 q 2 1 | ε, ⊲ ⊢ 0 0 1 0 1 0 0 0 1 q 0

  27. Example: 0 n 0 10 n 1 10 n 2 1 · · · �→ 0 n 0 1 n 0 0 n 1 1 n 1 0 n 2 1 n 2 · · · ⊢| ε, ⊲ 0 | 0 , ⊲ 0 | ε, ⊳ 0 | 1 , ⊲ ⊢| ε, ⊲ 1 | ε, ⊲ 1 | ε, ⊳ q 0 q 1 q 2 1 | ε, ⊲ ⊢ 0 0 1 0 1 0 0 0 1 q 0 0

  28. Example: 0 n 0 10 n 1 10 n 2 1 · · · �→ 0 n 0 1 n 0 0 n 1 1 n 1 0 n 2 1 n 2 · · · ⊢| ε, ⊲ 0 | 0 , ⊲ 0 | ε, ⊳ 0 | 1 , ⊲ ⊢| ε, ⊲ 1 | ε, ⊲ 1 | ε, ⊳ q 0 q 1 q 2 1 | ε, ⊲ ⊢ 0 0 1 0 1 0 0 0 1 q 0 0 0

  29. Example: 0 n 0 10 n 1 10 n 2 1 · · · �→ 0 n 0 1 n 0 0 n 1 1 n 1 0 n 2 1 n 2 · · · ⊢| ε, ⊲ 0 | 0 , ⊲ 0 | ε, ⊳ 0 | 1 , ⊲ ⊢| ε, ⊲ 1 | ε, ⊲ 1 | ε, ⊳ q 0 q 1 q 2 1 | ε, ⊲ ⊢ 0 0 1 0 1 0 0 0 1 q 1 0 0

  30. Example: 0 n 0 10 n 1 10 n 2 1 · · · �→ 0 n 0 1 n 0 0 n 1 1 n 1 0 n 2 1 n 2 · · · ⊢| ε, ⊲ 0 | 0 , ⊲ 0 | ε, ⊳ 0 | 1 , ⊲ ⊢| ε, ⊲ 1 | ε, ⊲ 1 | ε, ⊳ q 0 q 1 q 2 1 | ε, ⊲ ⊢ 0 0 1 0 1 0 0 0 1 q 1 0 0

  31. Example: 0 n 0 10 n 1 10 n 2 1 · · · �→ 0 n 0 1 n 0 0 n 1 1 n 1 0 n 2 1 n 2 · · · ⊢| ε, ⊲ 0 | 0 , ⊲ 0 | ε, ⊳ 0 | 1 , ⊲ ⊢| ε, ⊲ 1 | ε, ⊲ 1 | ε, ⊳ q 0 q 1 q 2 1 | ε, ⊲ ⊢ 0 0 1 0 1 0 0 0 1 q 1 0 0

  32. Example: 0 n 0 10 n 1 10 n 2 1 · · · �→ 0 n 0 1 n 0 0 n 1 1 n 1 0 n 2 1 n 2 · · · ⊢| ε, ⊲ 0 | 0 , ⊲ 0 | ε, ⊳ 0 | 1 , ⊲ ⊢| ε, ⊲ 1 | ε, ⊲ 1 | ε, ⊳ q 0 q 1 q 2 1 | ε, ⊲ ⊢ 0 0 1 0 1 0 0 0 1 q 2 0 0

  33. Example: 0 n 0 10 n 1 10 n 2 1 · · · �→ 0 n 0 1 n 0 0 n 1 1 n 1 0 n 2 1 n 2 · · · ⊢| ε, ⊲ 0 | 0 , ⊲ 0 | ε, ⊳ 0 | 1 , ⊲ ⊢| ε, ⊲ 1 | ε, ⊲ 1 | ε, ⊳ q 0 q 1 q 2 1 | ε, ⊲ ⊢ 0 0 1 0 1 0 0 0 1 q 2 0 0 1

  34. Example: 0 n 0 10 n 1 10 n 2 1 · · · �→ 0 n 0 1 n 0 0 n 1 1 n 1 0 n 2 1 n 2 · · · ⊢| ε, ⊲ 0 | 0 , ⊲ 0 | ε, ⊳ 0 | 1 , ⊲ ⊢| ε, ⊲ 1 | ε, ⊲ 1 | ε, ⊳ q 0 q 1 q 2 1 | ε, ⊲ ⊢ 0 0 1 0 1 0 0 0 1 q 2 0 0 1 1

  35. Example: 0 n 0 10 n 1 10 n 2 1 · · · �→ 0 n 0 1 n 0 0 n 1 1 n 1 0 n 2 1 n 2 · · · ⊢| ε, ⊲ 0 | 0 , ⊲ 0 | ε, ⊳ 0 | 1 , ⊲ ⊢| ε, ⊲ 1 | ε, ⊲ 1 | ε, ⊳ q 0 q 1 q 2 1 | ε, ⊲ ⊢ 0 0 1 0 1 0 0 0 1 q 0 0 0 1 1

  36. Example: 0 n 0 10 n 1 10 n 2 1 · · · �→ 0 n 0 1 n 0 0 n 1 1 n 1 0 n 2 1 n 2 · · · ⊢| ε, ⊲ 0 | 0 , ⊲ 0 | ε, ⊳ 0 | 1 , ⊲ ⊢| ε, ⊲ 1 | ε, ⊲ 1 | ε, ⊳ q 0 q 1 q 2 1 | ε, ⊲ ⊢ 0 0 1 0 1 0 0 0 1 q 0 0 0 1 1 0

Recommend


More recommend