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Machine Learning for Healthcare 6.871, HST.956 Lecture 14: Causal Inference Part 1 David Sontag Does gastric bypass surgery prevent onset of diabetes? 2013 1994 2000 <4.5% 4.5%5.9% 6.0%7.4% 7.5%8.9%


  1. Machine Learning for Healthcare 6.871, HST.956 Lecture 14: Causal Inference Part 1 David Sontag

  2. Does gastric bypass surgery prevent onset of diabetes? 2013 1994 2000 <4.5% 4.5%–5.9% 6.0%–7.4% 7.5%–8.9% >9.0% • In Lecture 4 & PS2 we used machine learning for early detection of Type 2 diabetes • Health system doesn’t want to know how to predict diabetes – they want to know how to prevent it • Gastric bypass surgery is the highest negative weight (9th most predictive feature) – Does this mean it would be a good intervention?

  3. What is the likelihood this patient, with breast cancer, will survive 5 years? • Such predictive models widely used to stage patients. Should we initiate treatment? How aggressive? • What could go wrong if we trained to predict survival, and then used to guide patient care? 𝒁 Treatment Diagnosis Death 𝒀 Time “Mary” A long survival time may be because of treatment!

  4. What treatment should we give this patient? Expansion pathology (image from Andy Beck) • People respond differently to treatment • Goal: use data from other patients and their journeys to guide future treatment decisions • What could go wrong if we trained to predict (past) treatment decisions? Best this can do is Treatment A “David” match current “John” Treatment B medical practice! Treatment A “Juana”

  5. Does smoking cause lung cancer? • Doing a randomized control trial is unethical • Could we simply answer this question by comparing Pr(lung cancer | smoker) vs Pr(lung cancer | nonsmoker)? • No! Answering such questions from observational data is difficult because of confounding

  6. To properly answer, need to formulate as causal questions: Patient , 𝑌 Intervention, 𝑈 (including all (e.g. medication, ? confounding procedure) factors) Outcome , 𝑍 High dimensional Observational data

  7. Potential Outcomes Framework (Rubin-Neyman Causal Model) • Each unit (individual) 𝑦 ! has two potential outcomes: – 𝑍 ! (𝑦 " ) is the potential outcome had the unit not been treated: “ control outcome ” – 𝑍 # (𝑦 " ) is the potential outcome had the unit been treated: “ treated outcome ” • Conditional average treatment effect for unit 𝑗 : 𝐷𝐵𝑈𝐹 𝑦 ! = 𝔽 " $ |' % ) [𝑍 ) |𝑦 ! ] − 𝔽 " & |' % ) [𝑍 * |𝑦 ! ] $ ~$(" & ~$(" • Average Treatment Effect: 𝐵𝑈𝐹: = 𝔽 𝑍 ) − 𝑍 * = 𝔽 '~$(') 𝐷𝐵𝑈𝐹 𝑦

  8. Potential Outcomes Framework (Rubin-Neyman Causal Model) • Each unit (individual) 𝑦 ! has two potential outcomes: – 𝑍 ! (𝑦 " ) is the potential outcome had the unit not been treated: “ control outcome ” – 𝑍 # (𝑦 " ) is the potential outcome had the unit been treated: “ treated outcome ” • Observed factual outcome: 𝑧 ! = 𝑢 ! 𝑍 ) 𝑦 ! + 1 − 𝑢 ! 𝑍 * (𝑦 ! ) • Unobserved counterfactual outcome: +, = (1 − 𝑢 ! )𝑍 𝑧 ! ) 𝑦 ! + 𝑢 ! 𝑍 * (𝑦 ! )

  9. The fundamental problem of causal inference “The fundamental problem of causal inference” We only ever observe one of the two outcomes

  10. Example – Blood pressure and age 𝑧 = 𝑐𝑚𝑝𝑝𝑒_𝑞𝑠𝑓𝑡. 𝑍 $ 𝑦 Treated 𝑍 % 𝑦 𝑦 = 𝑏𝑕𝑓

  11. Blood pressure and age 𝑧 = 𝑐𝑚𝑝𝑝𝑒_𝑞𝑠𝑓𝑡. 𝐷𝐵𝑈𝐹(𝑦) 𝑍 $ 𝑦 Treated 𝑍 % 𝑦 𝑦 = 𝑏𝑕𝑓

  12. Blood pressure and age 𝑧 = 𝑐𝑚𝑝𝑝𝑒_𝑞𝑠𝑓𝑡. 𝐵𝑈𝐹 𝑍 $ 𝑦 Treated 𝑍 % 𝑦 𝑦 = 𝑏𝑕𝑓

  13. Blood pressure and age 𝑧 = 𝑐𝑚𝑝𝑝𝑒_𝑞𝑠𝑓𝑡. 𝑍 $ 𝑦 Treated 𝑍 % 𝑦 Treated Control 𝑦 = 𝑏𝑕𝑓

  14. Blood pressure and age 𝑍 $ 𝑦 𝑧 = 𝑐𝑚𝑝𝑝𝑒_𝑞𝑠𝑓𝑡. Treated 𝑍 % 𝑦 Treated Control 𝑦 = 𝑏𝑕𝑓 Counterfactual treated Counterfactual control

  15. (age, gender, Sugar levels Sugar levels Observed exercise,treatment) had they had they sugar levels received received medication A medication B (45, F, 0, A ) 6 5.5 6 (45, F, 1, B ) 7 6.5 6.5 (55, M, 0, A ) 7 6 7 (55, M, 1, B ) 9 8 8 (65, F, 0, B ) 8.5 8 8 (65,F, 1, A ) 7.5 7 7.5 (75,M, 0, B ) 10 9 9 (75,M, 1, A ) 8 7 8 (Example from Uri Shalit)

  16. (age, gender, Sugar levels Sugar levels Observed exercise) had they had they sugar levels received received medication A medication B (45, F, 0) 6 5.5 6 (45, F, 1) 7 6.5 6.5 (55, M, 0) 7 6 7 (55, M, 1) 9 8 8 (65, F, 0) 8.5 8 8 (65,F, 1) 7.5 7 7.5 (75,M, 0) 10 9 9 (75,M, 1) 8 7 8 (Example from Uri Shalit)

  17. (age, gender, Y 0 : Sugar levels Y 1 : Sugar levels Observed exercise) had they had they sugar levels received received medication A medication B (45, F, 0) 6 5.5 6 (45, F, 1) 7 6.5 6.5 (55, M, 0) 7 6 7 (55, M, 1) 9 8 8 (65, F, 0) 8.5 8 8 (65,F, 1) 7.5 7 7.5 (75,M, 0) 10 9 9 (75,M, 1) 8 7 8 (Example from Uri Shalit)

  18. (age,gender, Sugar levels Sugar levels Observed exercise) had they had they sugar levels received received medication medication mean(sugar|medication B) – A B mean(sugar|medicaton A) = (45, F, 0) 6 5.5 6 ? (45, F, 1) 7 6.5 6.5 (55, M, 0) 7 6 7 (55, M, 1) 9 8 8 mean(sugar| had they received B) – (65, F, 0) 8.5 8 8 mean(sugar| had they received A) = (65,F, 1) 7.5 7 7.5 ? (75,M, 0) 10 9 9 (75,M, 1) 8 7 8 (Example from Uri Shalit)

  19. (age,gender, Sugar levels Sugar levels Observed exercise) had they had they sugar levels received received medication medication mean(sugar|medication B) – A B mean(sugar|medicaton A) = (45, F, 0) 6 5.5 6 7.875 - 7.125 = 0.75 (45, F, 1) 7 6.5 6.5 (55, M, 0) 7 6 7 (55, M, 1) 9 8 8 mean(sugar| had they received B) – (65, F, 0) 8.5 8 8 mean(sugar| had they received A) = (65,F, 1) 7.5 7 7.5 7.125 - 7.875 = -0.75 (75,M, 0) 10 9 9 (75,M, 1) 8 7 8 (Example from Uri Shalit)

  20. Typical assumption – no unmeasured confounders 𝑍 * , 𝑍 ) : potential outcomes for control and treated 𝑦 : unit covariates (features) T: treatment assignment We assume: (𝑍 ! , 𝑍 " ) ⫫ 𝑈 | 𝑦 The potential outcomes are independent of treatment assignment, conditioned on covariates 𝑦

  21. Typical assumption – no unmeasured confounders 𝑍 * , 𝑍 ) : potential outcomes for control and treated 𝑦 : unit covariates (features) T: treatment assignment We assume: (𝑍 ! , 𝑍 " ) ⫫ 𝑈 | 𝑦 Ignorability

  22. Ignorability covariates 𝒚 𝑼 treatment (features) 𝒁 𝟏 𝒁 𝟐 Potential outcomes (𝑍 ! , 𝑍 " ) ⫫ 𝑈 | 𝑦

  23. Ignorability anti- hypertensive medication age, gender, 𝒚 𝑼 weight, diet, heart rate at rest,… 𝒁 𝟏 𝒁 𝟐 blood pressure blood pressure after medication after A medication B (𝑍 ! , 𝑍 " ) ⫫ 𝑈 | 𝑦

  24. No Ignorability anti- hypertensive medication age, gender, 𝒚 𝑼 weight, diet, diabetic heart rate at rest,… 𝒊 𝒁 𝟏 𝒁 𝟐 blood pressure blood pressure after medication after A medication B (𝑍 ! , 𝑍 " ) ⫫ 𝑈 | 𝑦

  25. Typical assumption – common support Y * , 𝑍 ) : potential outcomes for control and treated 𝑦 : unit covariates (features) 𝑈 : treatment assignment We assume: 𝑞 𝑈 = 𝑢 𝑌 = 𝑦 > 0 ∀𝑢, 𝑦

  26. Framing the question 1. Where could we go to for data to answer these questions? 2. What should X , T, and Y be to satisfy ignorability? 3. What is the specific causal inference question that we are interested in? 4. Are you worried about common support?

  27. Outline for lecture • How to recognize a causal inference problem • Potential outcomes framework – Average treatment effect (ATE) – Conditional average treatment effect (CATE) • Algorithms for estimating ATE and CATE

  28. Average Treatment Effect The expected causal effect of 𝑈 on 𝑍 : ATE := E [ Y 1 − Y 0 ]

  29. Average Treatment Effect – the adjustment formula • Assuming ignorability, we will derive the adjustment formula (Hernán & Robins 2010, Pearl 2009) • The adjustment formula is extremely useful in causal inference • Also called G-formula

  30. Average Treatment Effect The expected causal effect of 𝑈 on 𝑍 : ATE := E [ Y 1 − Y 0 ]

  31. Average Treatment Effect The expected causal effect of 𝑈 on 𝑍 : ATE := E [ Y 1 − Y 0 ] law of total expectation E [ Y 1 ] = ⇥ ⇤ E Y 1 ∼ p ( Y 1 | x ) [ Y 1 | x ] = E x ∼ p ( x ) ⇥ ⇤

  32. Average Treatment Effect The expected causal effect of 𝑈 on 𝑍 : ATE := E [ Y 1 − Y 0 ] E [ Y 1 ] = ignorability ⇥ ⇤ E Y 1 ∼ p ( Y 1 | x ) [ Y 1 | x ] = (𝑍 * , 𝑍 ) ) ⫫ 𝑈 | 𝑦 E x ∼ p ( x ) ⇥ ⇤ E Y 1 ∼ p ( Y 1 | x ) [ Y 1 | x, T = 1] = E x ∼ p ( x ) , T=1 E E

  33. Average Treatment Effect The expected causal effect of 𝑈 on 𝑍 : ATE := E [ Y 1 − Y 0 ] E [ Y 1 ] = ⇥ ⇤ E Y 1 ∼ p ( Y 1 | x ) [ Y 1 | x ] = E x ∼ p ( x ) ⇥ ⇤ E Y 1 ∼ p ( Y 1 | x ) [ Y 1 | x, T = 1] = E x ∼ p ( x ) , T=1 shorter notation E x ∼ p ( x ) [ E [ Y 1 | x, T = 1]]

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