Introduction to ECL INEL4207 Digital Electronics Tuesday, September 27, 11
Current Switch R v C1 v IN Q 1 Q 2 V REF I EE -V EE Tuesday, September 27, 11
ECL Inverter R v C1 Q 3 v IN Q 1 Q 2 V REF v O I E3 I EE -V EE Tuesday, September 27, 11
Current Source R v C1 Q 3 v IN Q 1 Q 2 V REF v O R CS I EE Q 5 Q 4 Q 6 A 4 A 5 A 6 -V EE Tuesday, September 27, 11
Reference Voltage R 1 Q 5 D 1 V REF D 2 R 3 R 2 V EE =-5.2V Tuesday, September 27, 11
ECL with Resistor R v C1 Q 3 v IN Q 1 Q 2 V REF v O I E3 R 3 R EE I R EE -V EE2 -V EE Tuesday, September 27, 11
R 4 R v C1 Q 3 v IN Q 1 Q 2 V REF v O I E3 R 3 R EE I R EE -V EE Example: Use the above circuit design an ECL gate for which V H = − 1.7V and V L = − 2.3V . The average power dissipation should be less that 2mW. The supply voltage is − 5.2V . Neglect the base currents. Tuesday, September 27, 11
ECL-NOR Gate R C1 R C2 v C1 v C2 Q 4 Q 3 A+B B A Q 2 V REF A+B Q 1B Q 1A R E R E I EE -V EE2 -V EE2 -V EE Tuesday, September 27, 11
1. For the ECL inverter shown in the following sketch, the high voltage level is V H = − 1 . 7 V and the average power dissipated when the input is high 50 % of the time is P = 5 mW . Determine the source’s current I EE , the low voltage level V L , the reference voltage level V REF and the value of resistance R 3 . 2k � 2k � Q 3 v in v out Q 1 Q 2 V REF R 3 I EE -3.3V -5.2V Tuesday, September 27, 11
� � 2. Find V L , V H and V REF for the following circuit. Neglect base currents and assume V BE = 0 . 7 V if a transistor is ON. (25 points) 1k ! Q 2 v IN Q 1 V REF v OUT 1k ! 4k ! -2V -5V Tuesday, September 27, 11
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