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Implicit Extremes and Implicit MaxStable Laws Stilian Stoev ( - PowerPoint PPT Presentation

Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Implicit Extremes and Implicit MaxStable Laws Stilian Stoev ( sstoev@umich.edu ) University of Michigan, Ann Arbor September 19, 2014 Joint work


  1. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Implicit Extremes and Implicit Max–Stable Laws Stilian Stoev ( sstoev@umich.edu ) University of Michigan, Ann Arbor September 19, 2014 Joint work with Hans-Peter Scheffler (University of Siegen). 1/34

  2. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Problem Formulation 1 Limit Theory 2 Implicit Extreme Value Laws 3 Implicit Max–Stable Laws and their Domains of Attraction 4 An Example 5 2/34

  3. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Problem Formulation 3/34

  4. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Setup Let X 1 , . . . , X n be iid vectors in R d . They are hidden, i.e., unobserved. Observed are f ( X 1 ) , . . . , f ( X n ) for some loss function f : R d → [0 , ∞ ) . We want to know what is the behavior of the scenario that maximizes the loss X k ( n ) , where k ( n ) = Argmax k =1 ,..., n f ( X k ) . We refer to X k ( n ) as to the implicit extreme relative to the loss f . 4/34

  5. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example First observations If the law of f ( X i ) is continuous, with probability one, there are no ties among f ( X 1 ) , . . . , f ( X n ) In the case of ties (discontinuous L ( f ( X i ))), k ( n ) is taken as the smallest index maximizing the losses f ( X i ) , i = 1 , . . . , n . The motivation stems from applications: We are interested in the structure of the complex (multivariate) events modeled by X i ’s that lead to extreme losses. These implicit extremes, depending on the loss function f , may or may not be associated with extreme values of the X i ’s... General Perspective: We are interested in the structure of events leading to extreme losses! 5/34

  6. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example The simple Lemma that started it all Lemma Suppose the cdf G ( y ) := P ( f ( X 1 ) ≤ y ) is continuous. Then, for all measurable A ⊂ R , � G ( f ( x )) n − 1 P X ( d x ) P ( X k ( n ) ∈ A ) = n A Proof. There are no ties, a.s., and by symmetry and independence: P ( X k ( n ) ∈ A ) = nP ( X 1 ∈ A , f ( X i ) ≤ f ( X 1 ) , i = 2 , . . . , n ) � P ( f ( X 2 ) ≤ f ( x )) n − 1 P X ( d x ) . = n A Note: We can handle the general case of discontinuous G . 6/34

  7. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Limit Theory 7/34

  8. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Assumptions Homogeneous losses: The loss is non-negative f : R d → [0 , ∞ ) and f ( cx ) = cf ( x ) , for all c > 0 . This is not a terrible constraint, since Argmax ( f ( X 1 ) , . . . , f ( X n )) = Argmax ( h ◦ f ( X 1 ) , . . . , h ◦ f ( X n )) , for any strictly increasing h : [0 , ∞ ) → [ −∞ , ∞ ). d Regular variation on a cone: P X ∈ RV ( { a n } , D , ν ), where D ⊂ R is a closed cone, playing the role of zero. That is, v nP ( a − 1 n X ∈ · ) − → ν, as n → ∞ , d \ D . d in the space R D := R d This is an important generalization of the usual RV on R { 0 } . Note RV ( { a n } , { 0 } , ν ) ⊂ RV ( { a n } , D , ν ). However, the generalized notion of RV allows us to handle cases that are asymptotically trivial in the classical sense. Similar (but not the same as) Sid Resnick’s hidden regular variation. 8/34

  9. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example RV on cones and generalized polar coordinates d := [ −∞ , ∞ ] d . Consider the compact space R Let τ : R d → [0 , ∞ ] be a continuous and homogeneous function. Define D := { τ = 0 } (necessarily) a compact in R d . d \ D with the relative topology. d Equip R D := R d that are d The compacts in R D are closed subsets of R d bounded away from D = { τ = 0 } . That is, K ⊂ R D is compact if it is closed and K ⊂ { τ > ǫ } , for some ǫ > 0. Polar coordinates: Let θ ( x ) := x /τ ( x ). Then d ( τ, θ ) : R D → (0 , ∞ ] × S , is a homeomorphism (of topological spaces), where d : τ ( x ) = 1 } S = { τ = 1 } = { x ∈ R is equipped with the relative topology. 9/34

  10. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Regular variation Definition A probability law P X ∈ RV ( { a n } , D , ν ), if there exists a regularly varying d sequence { a n } and a non-trivial Radon measure ν on R D , such that nP X ( a − 1 n X ∈ A ) − → ν ( A ) , as n → ∞ , for all measurable A , bounded away from D , i.e., A ⊂ { τ > ǫ } , for some ǫ > 0, and such that ν ( ∂ A ) = 0. Fact (Prop 3.8 in Scheffler & Stoev (2014)) P X ∈ RV ( { a n } , D , ν ) , if and only if nP ( a − 1 n τ ( X ) > x ) → n →∞ Cx − α and w P ( θ ( X ) ∈ ·| τ ( X ) > u ) − → u →∞ σ 0 ( · ) , where σ 0 is a finite measure on S. 10/34

  11. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Example Cone and coors: Let τ ( x ) = min { ( x 1 ) + , . . . , ( x d ) + } so that d D = (0 , ∞ ] d . R The unit “sphere”, is now: i =1 [1 , ∞ ] i − 1 × { 1 } × [1 , ∞ ] d − i S := { x : τ ( x ) = 1 } = ∪ d Distribution: Let X = ( X i ) d i =1 with independent and Pareto X i ’s P ( X i > x ) = x − α i , ( α i > 0) , i = 1 , . . . , d . 11/34

  12. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Example (cont’d) The classic RV: In R d { 0 } , we have asymptotic independence and the heaviest tail dominates: nP ( n − 1 /α ∗ X ∈ A ) − → µ ( A ) , where α ∗ := i =1 ,..., d α i , min and d � µ ( A ) = I { α i = α ∗ } ν i ,α ∗ ( A ) , i =1 where ν i ,α is concentrated on the positive part of the i -th axis and ν i ,α ( R i − 1 × [ x , ∞ ) × R d − i ) = x − α , x ≥ 0 . That is, the limit measure µ lives on the axes. 12/34

  13. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Example (cont’d) The cone R d D := (0 , ∞ ] d : Then, X ∈ RV ( { n − 1 /α } , D , ν ), with α = α 1 + · · · + α d and where now ν lives on (0 , ∞ ) d and now has a density! Indeed, for A = ( x 1 , ∞ ] × · · · × ( x d , ∞ ] ⊂ (0 , ∞ ] d , d � P ( a − 1 n X ∈ A ) ∼ P ( X i > a n x i ) i =1 d � ( a n x i ) − α i =: a − α = ν ( A ) . n i =1 n X ∈ · ) → v ν ( · ), where By picking a n := n − 1 /α , we obtain nP ( a − 1 d d ν � α i x − α i − 1 x = ( x i ) d i =1 ∈ (0 , ∞ ] d . d x ( x ) = , i i =1 13/34

  14. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Implicit Extreme Value Laws Assumptions: (RV α ) X ∈ RV α ( { a n } , D , ν ) d → [0 , ∞ ] is Borel, 1-homogeneous, f (0) = 0. (H) f : R (F) For all ǫ > 0, the set { f > ǫ } is bounded away from D and d x ∈ K f ( x ) > 0 , inf for all compact K ⊂ R D . (C) ν ( disc ( f )) = 0. Theorem (3.13 in Scheffler & Stoev (2014)) Under the above assumptions, we have 1 d X k ( n ) − → Y , as n → ∞ , a n where P Y ( dx ) = e − Cf ( x ) − α ν ( d x ) and C := ν { f > 1 } . 14/34

  15. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Sketch of the proof By the above lemma, we have � P ( f ( X ) ≤ f ( x )) n − 1 P X ( d x ) P ( X k ( n ) ∈ a n A ) = n a n A � P ( f ( X ) ≤ f ( a n z ) n − 1 nP a − 1 = X ( d z ) (change of vars) n A � P ( f ( a − 1 n X ) ≤ f ( z )) n − 1 ν n ( dz ) = (homogeneity of f ) A where X ( d z ) ≡ nP ( a − 1 ν n ( d z ) := nP a − 1 n X ∈ d z ) . n Continuing... � 1 − nP ( f ( a − 1 � n X ) > f ( z ) � n − 1 P ( X k ( n ) ∈ a n A ) = ν n ( d z ) . n A 15/34

  16. Problem Formulation Limit Theory Implicit Extreme Value Laws Domains of Attraction An Example Sketch of the proof (cont’d) � 1 − nP ( f ( a − 1 � � n − 1 n X ) > f ( z ) P ( X k ( n ) ∈ a n A ) = ν n ( d z ) n A � 1 − nP ( a − 1 � � n − 1 n X ∈ { f > f ( z ) } = ν n ( d z ) . n A The set B z := { f > f ( z ) } is bounded away from D . If it is a continuity set of ν , by the (RV α ) and ( H ) assumptions: nP ( a − 1 nP ( a − 1 n X ∈ B z ) = n X ∈ { f > f ( z ) } − → ν ( { f > f ( z ) } ) ν ( f ( z ) · { f > 1 } ) = f ( z ) − α ν { f > 1 } . = Since by (RV α ), we also have ν n → v ν , it can be shown that � e − ν { f > 1 } f ( z ) − α ν ( d z ) , P ( X k ( n ) ∈ a n A ) − → A for all ν -continuity sets A . ✷ 16/34

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