Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = d � 3 + 3 d �� � 2 − 4 � � x 2 � � y ( x ) y ( x ) = dx dx logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = d � 3 + 3 d �� � 2 − 4 � � x 2 � � y ( x ) y ( x ) = dx dx � 2 � y ( x ) 3 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = d � 3 + 3 d �� � 2 − 4 � � x 2 � � y ( x ) y ( x ) = dx dx � 2 y ′ ( x ) � y ( x ) 3 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = d � 3 + 3 d �� � 2 − 4 � � x 2 � � y ( x ) y ( x ) = dx dx � 2 y ′ ( x )+ 6 � � � y ′ ( x ) y ( x ) y ( x ) 3 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = d � 3 + 3 d �� � 2 − 4 � � x 2 � � y ( x ) y ( x ) = dx dx � 2 y ′ ( x )+ 6 � � � y ′ ( x ) y ( x ) y ( x ) = 3 2 x logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = d � 3 + 3 d �� � 2 − 4 � � x 2 � � y ( x ) y ( x ) = dx dx � 2 y ′ ( x )+ 6 � � � y ′ ( x ) y ( x ) y ( x ) = 3 2 x 3 y 2 y ′ + 6 yy ′ = 2 x logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = d � 3 + 3 d �� � 2 − 4 � � x 2 � � y ( x ) y ( x ) = dx dx � 2 y ′ ( x )+ 6 � � � y ′ ( x ) y ( x ) y ( x ) = 3 2 x 3 y 2 y ′ + 6 yy ′ = 2 x y ′ � 3 y 2 + 6 y � = 2 x logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = d � 3 + 3 d �� � 2 − 4 � � x 2 � � y ( x ) y ( x ) = dx dx � 2 y ′ ( x )+ 6 � � � y ′ ( x ) y ( x ) y ( x ) = 3 2 x 3 y 2 y ′ + 6 yy ′ = 2 x y ′ � 3 y 2 + 6 y � = 2 x 2 x y ′ = 3 y 2 + 6 y logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = d � 3 + 3 d �� � 2 − 4 � � x 2 � � y ( x ) y ( x ) = dx dx � 2 y ′ ( x )+ 6 � � � y ′ ( x ) y ( x ) y ( x ) = 3 2 x 3 y 2 y ′ + 6 yy ′ = 2 x y ′ � 3 y 2 + 6 y � = 2 x 2 x y ′ = 3 y 2 + 6 y y ′ � � � ( 0 , 1 ) logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = d � 3 + 3 d �� � 2 − 4 � � x 2 � � y ( x ) y ( x ) = dx dx � 2 y ′ ( x )+ 6 � � � y ′ ( x ) y ( x ) y ( x ) = 3 2 x 3 y 2 y ′ + 6 yy ′ = 2 x y ′ � 3 y 2 + 6 y � = 2 x 2 x y ′ = 3 y 2 + 6 y � 2 x y ′ � � = � 3 y 2 + 6 y � � ( 0 , 1 ) � ( 0 , 1 ) logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = d � 3 + 3 d �� � 2 − 4 � � x 2 � � y ( x ) y ( x ) = dx dx � 2 y ′ ( x )+ 6 � � � y ′ ( x ) y ( x ) y ( x ) = 3 2 x 3 y 2 y ′ + 6 yy ′ = 2 x y ′ � 3 y 2 + 6 y � = 2 x 2 x y ′ = 3 y 2 + 6 y � 2 x y ′ � � = = 0 � 3 y 2 + 6 y � � ( 0 , 1 ) � ( 0 , 1 ) logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. The function y satisfies y 3 + 3 y 2 − 4 = x 2 . Find its derivative at the point ( 0 , 1 ) . � 3 + 3 � 2 − 4 x 2 � � y ( x ) y ( x ) = d � 3 + 3 d �� � 2 − 4 � � x 2 � � y ( x ) y ( x ) = dx dx � 2 y ′ ( x )+ 6 � � � y ′ ( x ) y ( x ) y ( x ) = 3 2 x 3 y 2 y ′ + 6 yy ′ = 2 x y ′ � 3 y 2 + 6 y � = 2 x 2 x y ′ = 3 y 2 + 6 y � 2 x y ′ � � = = 0 � 3 y 2 + 6 y � � ( 0 , 1 ) � ( 0 , 1 ) logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Graphical Check logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Graphical Check logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Graphical Check logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. Computing a derivative by implicit differentiation . logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. Computing a derivative by implicit differentiation . 1. In the equation, determine the independent variable logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. Computing a derivative by implicit differentiation . 1. In the equation, determine the independent variable, usually it’s x logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. Computing a derivative by implicit differentiation . 1. In the equation, determine the independent variable, usually it’s x, and the dependent variable logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. Computing a derivative by implicit differentiation . 1. In the equation, determine the independent variable, usually it’s x, and the dependent variable, that is, the function logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. Computing a derivative by implicit differentiation . 1. In the equation, determine the independent variable, usually it’s x, and the dependent variable, that is, the function, which is usually y. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. Computing a derivative by implicit differentiation . 1. In the equation, determine the independent variable, usually it’s x, and the dependent variable, that is, the function, which is usually y. To start with, it may be a good idea to replace “y” with “y ( x ) ” or with “f ( x ) ”. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. Computing a derivative by implicit differentiation . 1. In the equation, determine the independent variable, usually it’s x, and the dependent variable, that is, the function, which is usually y. To start with, it may be a good idea to replace “y” with “y ( x ) ” or with “f ( x ) ”. 2. Differentiate both sides of the equation. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. Computing a derivative by implicit differentiation . 1. In the equation, determine the independent variable, usually it’s x, and the dependent variable, that is, the function, which is usually y. To start with, it may be a good idea to replace “y” with “y ( x ) ” or with “f ( x ) ”. 2. Differentiate both sides of the equation. Remember to use the chain rule for terms with y. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. Computing a derivative by implicit differentiation . 1. In the equation, determine the independent variable, usually it’s x, and the dependent variable, that is, the function, which is usually y. To start with, it may be a good idea to replace “y” with “y ( x ) ” or with “f ( x ) ”. 2. Differentiate both sides of the equation. Remember to use the chain rule for terms with y. 3. Solve for y ′ . logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. Computing a derivative by implicit differentiation . 1. In the equation, determine the independent variable, usually it’s x, and the dependent variable, that is, the function, which is usually y. To start with, it may be a good idea to replace “y” with “y ( x ) ” or with “f ( x ) ”. 2. Differentiate both sides of the equation. Remember to use the chain rule for terms with y. 3. Solve for y ′ . This is always possible, because, in any term that contains y ′ logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Algorithm. Computing a derivative by implicit differentiation . 1. In the equation, determine the independent variable, usually it’s x, and the dependent variable, that is, the function, which is usually y. To start with, it may be a good idea to replace “y” with “y ( x ) ” or with “f ( x ) ”. 2. Differentiate both sides of the equation. Remember to use the chain rule for terms with y. 3. Solve for y ′ . This is always possible, because, in any term that contains y ′ , the quantity y ′ is just a factor. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Find the equation of the tangent line of the graph defined by the equation xy 3 + xy + 3 x = 2 at the point ( 2 , − 1 ) . logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Find the equation of the tangent line of the graph defined by the equation xy 3 + xy + 3 x = 2 at the point ( 2 , − 1 ) . Dependent and independent variables. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Find the equation of the tangent line of the graph defined by the equation xy 3 + xy + 3 x = 2 at the point ( 2 , − 1 ) . Dependent and independent variables. Independent: x logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Find the equation of the tangent line of the graph defined by the equation xy 3 + xy + 3 x = 2 at the point ( 2 , − 1 ) . Dependent and independent variables. Independent: x , dependent: y . logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Find the equation of the tangent line of the graph defined by the equation xy 3 + xy + 3 x = 2 at the point ( 2 , − 1 ) . Dependent and independent variables. Independent: x , dependent: y . Differentiation with respect to x. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Find the equation of the tangent line of the graph defined by the equation xy 3 + xy + 3 x = 2 at the point ( 2 , − 1 ) . Dependent and independent variables. Independent: x , dependent: y . Differentiation with respect to x. xy 3 + xy + 3 x = 2 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Find the equation of the tangent line of the graph defined by the equation xy 3 + xy + 3 x = 2 at the point ( 2 , − 1 ) . Dependent and independent variables. Independent: x , dependent: y . Differentiation with respect to x. xy 3 + xy + 3 x = 2 d d � xy 3 + xy + 3 x � = dx ( 2 ) dx logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Find the equation of the tangent line of the graph defined by the equation xy 3 + xy + 3 x = 2 at the point ( 2 , − 1 ) . Dependent and independent variables. Independent: x , dependent: y . Differentiation with respect to x. xy 3 + xy + 3 x = 2 d d � xy 3 + xy + 3 x � = dx ( 2 ) dx y 3 + x 3 y 2 y ′ logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Find the equation of the tangent line of the graph defined by the equation xy 3 + xy + 3 x = 2 at the point ( 2 , − 1 ) . Dependent and independent variables. Independent: x , dependent: y . Differentiation with respect to x. xy 3 + xy + 3 x = 2 d d � xy 3 + xy + 3 x � = dx ( 2 ) dx y 3 + x 3 y 2 y ′ + y + xy ′ logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Find the equation of the tangent line of the graph defined by the equation xy 3 + xy + 3 x = 2 at the point ( 2 , − 1 ) . Dependent and independent variables. Independent: x , dependent: y . Differentiation with respect to x. xy 3 + xy + 3 x = 2 d d � xy 3 + xy + 3 x � = dx ( 2 ) dx y 3 + x 3 y 2 y ′ + y + xy ′ + 3 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Find the equation of the tangent line of the graph defined by the equation xy 3 + xy + 3 x = 2 at the point ( 2 , − 1 ) . Dependent and independent variables. Independent: x , dependent: y . Differentiation with respect to x. xy 3 + xy + 3 x = 2 d d � xy 3 + xy + 3 x � = dx ( 2 ) dx y 3 + x 3 y 2 y ′ + y + xy ′ + 3 = 0 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Solving for y ′ . logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Solving for y ′ . y 3 + x 3 y 2 y ′ + y + xy ′ + 3 = 0 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Solving for y ′ . y 3 + x 3 y 2 y ′ + y + xy ′ + 3 = 0 � 3 xy 2 + x � � y 3 + y + 3 � y ′ = − logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Solving for y ′ . y 3 + x 3 y 2 y ′ + y + xy ′ + 3 = 0 � 3 xy 2 + x � � y 3 + y + 3 � y ′ = − − y 3 + y + 3 y ′ = 3 xy 2 + x logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Solving for y ′ . y 3 + x 3 y 2 y ′ + y + xy ′ + 3 = 0 � 3 xy 2 + x � � y 3 + y + 3 � y ′ = − − y 3 + y + 3 y ′ = 3 xy 2 + x y ′ � � � ( 2 , − 1 ) logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Solving for y ′ . y 3 + x 3 y 2 y ′ + y + xy ′ + 3 = 0 � 3 xy 2 + x � � y 3 + y + 3 � y ′ = − − y 3 + y + 3 y ′ = 3 xy 2 + x − y 3 + y + 3 � y ′ � � = � 3 xy 2 + x � � ( 2 , − 1 ) � ( 2 , − 1 ) logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Solving for y ′ . y 3 + x 3 y 2 y ′ + y + xy ′ + 3 = 0 � 3 xy 2 + x � � y 3 + y + 3 � y ′ = − − y 3 + y + 3 y ′ = 3 xy 2 + x − y 3 + y + 3 � y ′ � � = � 3 xy 2 + x � � ( 2 , − 1 ) � ( 2 , − 1 ) − ( − 1 ) 3 +( − 1 )+ 3 = 3 · 2 · ( − 1 ) 2 + 2 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Solving for y ′ . y 3 + x 3 y 2 y ′ + y + xy ′ + 3 = 0 � 3 xy 2 + x � � y 3 + y + 3 � y ′ = − − y 3 + y + 3 y ′ = 3 xy 2 + x − y 3 + y + 3 � y ′ � � = � 3 xy 2 + x � � ( 2 , − 1 ) � ( 2 , − 1 ) − ( − 1 ) 3 +( − 1 )+ 3 = − 1 = 3 · 2 · ( − 1 ) 2 + 2 8 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Solving for y ′ . y 3 + x 3 y 2 y ′ + y + xy ′ + 3 = 0 � 3 xy 2 + x � � y 3 + y + 3 � y ′ = − − y 3 + y + 3 y ′ = 3 xy 2 + x − y 3 + y + 3 � y ′ � � = � 3 xy 2 + x � � ( 2 , − 1 ) � ( 2 , − 1 ) − ( − 1 ) 3 +( − 1 )+ 3 = − 1 = 3 · 2 · ( − 1 ) 2 + 2 8 Equation of the tangent line logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Solving for y ′ . y 3 + x 3 y 2 y ′ + y + xy ′ + 3 = 0 � 3 xy 2 + x � � y 3 + y + 3 � y ′ = − − y 3 + y + 3 y ′ = 3 xy 2 + x − y 3 + y + 3 � y ′ � � = � 3 xy 2 + x � � ( 2 , − 1 ) � ( 2 , − 1 ) − ( − 1 ) 3 +( − 1 )+ 3 = − 1 = 3 · 2 · ( − 1 ) 2 + 2 8 Equation of the tangent line: y = − 1 8 ( x − 2 ) − 1 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Solving for y ′ . y 3 + x 3 y 2 y ′ + y + xy ′ + 3 = 0 � 3 xy 2 + x � � y 3 + y + 3 � y ′ = − − y 3 + y + 3 y ′ = 3 xy 2 + x − y 3 + y + 3 � y ′ � � = � 3 xy 2 + x � � ( 2 , − 1 ) � ( 2 , − 1 ) − ( − 1 ) 3 +( − 1 )+ 3 = − 1 = 3 · 2 · ( − 1 ) 2 + 2 8 Equation of the tangent line: y = − 1 8 ( x − 2 ) − 1 = − 1 8 x − 3 4. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Solving for y ′ . y 3 + x 3 y 2 y ′ + y + xy ′ + 3 = 0 � 3 xy 2 + x � � y 3 + y + 3 � y ′ = − − y 3 + y + 3 y ′ = 3 xy 2 + x − y 3 + y + 3 � y ′ � � = � 3 xy 2 + x � � ( 2 , − 1 ) � ( 2 , − 1 ) − ( − 1 ) 3 +( − 1 )+ 3 = − 1 = 3 · 2 · ( − 1 ) 2 + 2 8 Equation of the tangent line: y = − 1 8 ( x − 2 ) − 1 = − 1 8 x − 3 4. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Graphical Check logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Graphical Check logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Graphical Check logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Gravel that is dumped off a conveyor belt forms a right circular cone whose sides rise at a 45 ◦ angle. If 2 m 3 of gravel are dumped onto the cone every second, how fast is the height of the cone rising when the cone is 10 m tall? logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Gravel that is dumped off a conveyor belt forms a right circular cone whose sides rise at a 45 ◦ angle. If 2 m 3 of gravel are dumped onto the cone every second, how fast is the height of the cone rising when the cone is 10 m tall? logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Gravel that is dumped off a conveyor belt forms a right circular cone whose sides rise at a 45 ◦ angle. If 2 m 3 of gravel are dumped onto the cone every second, how fast is the height of the cone rising when the cone is 10 m tall? Volume of a right circular cone logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Gravel that is dumped off a conveyor belt forms a right circular cone whose sides rise at a 45 ◦ angle. If 2 m 3 of gravel are dumped onto the cone every second, how fast is the height of the cone rising when the cone is 10 m tall? Volume of a right circular cone: V = logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Gravel that is dumped off a conveyor belt forms a right circular cone whose sides rise at a 45 ◦ angle. If 2 m 3 of gravel are dumped onto the cone every second, how fast is the height of the cone rising when the cone is 10 m tall? Volume of a right circular cone: V = 1 3 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Gravel that is dumped off a conveyor belt forms a right circular cone whose sides rise at a 45 ◦ angle. If 2 m 3 of gravel are dumped onto the cone every second, how fast is the height of the cone rising when the cone is 10 m tall? Volume of a right circular cone: V = 1 3 π r 2 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Gravel that is dumped off a conveyor belt forms a right circular cone whose sides rise at a 45 ◦ angle. If 2 m 3 of gravel are dumped onto the cone every second, how fast is the height of the cone rising when the cone is 10 m tall? Volume of a right circular cone: V = 1 3 π r 2 h . logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Gravel that is dumped off a conveyor belt forms a right circular cone whose sides rise at a 45 ◦ angle. If 2 m 3 of gravel are dumped onto the cone every second, how fast is the height of the cone rising when the cone is 10 m tall? Volume of a right circular cone: V = 1 3 π r 2 h . Sides rise at a 45 ◦ angle logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Gravel that is dumped off a conveyor belt forms a right circular cone whose sides rise at a 45 ◦ angle. If 2 m 3 of gravel are dumped onto the cone every second, how fast is the height of the cone rising when the cone is 10 m tall? Volume of a right circular cone: V = 1 3 π r 2 h . Sides rise at a 45 ◦ angle ⇒ r = h . logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Gravel that is dumped off a conveyor belt forms a right circular cone whose sides rise at a 45 ◦ angle. If 2 m 3 of gravel are dumped onto the cone every second, how fast is the height of the cone rising when the cone is 10 m tall? Volume of a right circular cone: V = 1 3 π r 2 h . Sides rise at a 45 ◦ angle ⇒ r = h . So the volume of this cone, in terms of its height, is logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Gravel that is dumped off a conveyor belt forms a right circular cone whose sides rise at a 45 ◦ angle. If 2 m 3 of gravel are dumped onto the cone every second, how fast is the height of the cone rising when the cone is 10 m tall? Volume of a right circular cone: V = 1 3 π r 2 h . Sides rise at a 45 ◦ angle ⇒ r = h . So the volume of this cone, in terms of its height, is V ( h ) = 1 3 π h 3 . logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions 1 3 π h 3 = V logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions 1 3 π h 3 = V � 1 � d d 3 π h 3 = dtV dt logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions 1 3 π h 3 = V � 1 � d d 3 π h 3 = dtV dt 1 3 π 3 h 2 h ′ V ′ = logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions 1 3 π h 3 = V � 1 � d d 3 π h 3 = dtV dt 1 3 π 3 h 2 h ′ = π h 2 h ′ V ′ = logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions 1 3 π h 3 = V � 1 � d d 3 π h 3 = dtV dt 1 3 π 3 h 2 h ′ = π h 2 h ′ V ′ = V ′ h ′ = π h 2 logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions 1 3 π h 3 = V � 1 � d d 3 π h 3 = dtV dt 1 3 π 3 h 2 h ′ = π h 2 h ′ V ′ = V ′ h ′ = π h 2 h ′ � = � � h = 10 m logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions 1 3 π h 3 = V � 1 � d d 3 π h 3 = dtV dt 1 3 π 3 h 2 h ′ = π h 2 h ′ V ′ = V ′ h ′ = π h 2 V ′ � h ′ � � = � � π h 2 � h = 10 m � h = 10 m logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions 1 3 π h 3 = V � 1 � d d 3 π h 3 = dtV dt 1 3 π 3 h 2 h ′ = π h 2 h ′ V ′ = V ′ h ′ = π h 2 2 m 3 V ′ � h ′ � � s = = � � π h 2 π ( 10 m ) 2 � h = 10 m � h = 10 m logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions 1 3 π h 3 = V � 1 � d d 3 π h 3 = dtV dt 1 3 π 3 h 2 h ′ = π h 2 h ′ V ′ = V ′ h ′ = π h 2 2 m 3 V ′ � 1 m h ′ � � s = = π ( 10 m ) 2 = � � π h 2 50 π s � h = 10 m � h = 10 m logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions 1 3 π h 3 = V � 1 � d d 3 π h 3 = dtV dt 1 3 π 3 h 2 h ′ = π h 2 h ′ V ′ = V ′ h ′ = π h 2 2 m 3 V ′ � 1 m s ≈ 0 . 0064 m h ′ � � s = = π ( 10 m ) 2 = � � π h 2 50 π s � h = 10 m � h = 10 m logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions 1 3 π h 3 = V � 1 � d d 3 π h 3 = dtV dt 1 3 π 3 h 2 h ′ = π h 2 h ′ V ′ = V ′ h ′ = π h 2 2 m 3 V ′ � 1 m s ≈ 0 . 0064 m h ′ � � s = = π ( 10 m ) 2 = � � π h 2 50 π s � h = 10 m � h = 10 m logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Compute the derivative of f ( x ) = arctan ( x ) . logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Compute the derivative of f ( x ) = arctan ( x ) . y = arctan ( x ) logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
Introduction Derivatives Related Rates Inverse Functions Example. Compute the derivative of f ( x ) = arctan ( x ) . y = arctan ( x ) tan ( y ) = x logo1 Bernd Schr¨ oder Louisiana Tech University, College of Engineering and Science Implicit Differentiation
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