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Hypergeometric L -functions in average polynomial time Edgar Costa, Kiran S. Kedlaya, and David Roe Costa, Roe: Department of Mathematics, Massachusetts Institute of Technology Kedlaya: Department of Mathematics, University of California, San


  1. Hypergeometric L -functions in average polynomial time Edgar Costa, Kiran S. Kedlaya, and David Roe Costa, Roe: Department of Mathematics, Massachusetts Institute of Technology Kedlaya: Department of Mathematics, University of California, San Diego edgarc@mit.edu, kedlaya@ucsd.edu, roed@mit.edu slides at https://kskedlaya.org/slides/ ; see also arXiv:2005.13640, prerecorded talk (virtual) Algorithmic Number Theory Symposium (ANTS-XIV) University of Auckland (Te Whare W¯ ananga o T¯ amaki Makaurau) July 2, 2020 Kedlaya was supported by NSF (grant DMS-1802161) and UC San Diego (Warschawski Professorship). Costa and Roe were supported by the Simons Collaboration on Arithmetic Geometry, Number Theory, and Computation. The MIT campus sits on the traditional unceded territory of the Wampanoag Nation; we acknowledge the painful history of genocide and forced removal from this territory. The UCSD campus sits on the ancestral homelands of the Kumeyaay Nation; the Kumeyaay people continue to have an important and thriving presence in the region. Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 1 / 18

  2. Review of the prerecorded talk Contents Review of the prerecorded talk 1 Overview of the algorithm 2 A worked example 3 Future directions 4 Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 2 / 18

  3. Review of the prerecorded talk Computing an arithmetic L -function An arithmetic L -function over Q of some degree r generally has the form � det(1 − p − s F p ) − 1 p where for all but finitely many p , F p is some r × r matrix. Rewrite � ∞ � 1 det(1 − p − s F p ) − 1 = exp f p − fs Trace( F f � p ) ; f =1 to compute the Dirichlet series up to X , we need Trace( F f p ) for all prime powers p f ≤ X . We are interesting in computing the hypergeometric L -function associated to a hypergeometric datum ( α, β ) ∈ ( Q ∩ [0 , 1)) r × 2 , for which Trace( F f p ) is computed by a finite hypergeometric sum. In this paper, we focus on f = 1 and compute this trace modulo p . Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 3 / 18

  4. Review of the prerecorded talk Finite hypergeometric sums Using Gross–Koblitz to compute Gauss sums in the Beukers–Cohen–Mellit formula using the Morita p -adic Gamma function Γ p , we get for q = p p − 2 1 � � α � ( − p ) η m ( α ) − η m ( β ) p D + ξ m ( β ) � Trace( F p ) = H p � z := � β 1 − p m =0   r m Γ p ( α j + 1 − p ) / Γ p ( α j ) �  [ z ] m  m Γ p ( β j + 1 − p ) / Γ p ( β j ) j =1 where η m , ξ m , D are some combinatorial invariants of α, β and [ z ] ∈ Z × p is the unique ( p − 1)-st root of unity congruent to z modulo p . (We rig up D to ensure η m ( α ) − η m ( β ) + D + ξ m ( β ) ≥ 0; since Γ p takes values in Z × p , everything in sight is in Z p rather than Q p .) Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 4 / 18

  5. Review of the prerecorded talk Quadratic versus linear complexity � � α � The implementations in Magma and Sage compute H p � z one p at a � β time. Since the sum is over O ( p ) terms, computing all prime Dirichlet coefficients up to X requires O ( X 2 log X ) arithmetic operations. In our paper, we use the method of remainder forests (cf. Sutherland’s paper) to amortize the computation over all p ≤ X . This reduces the complexity to O ( X log 3 X ) (for fixed α, β ). � � α � Reminder: we are only computing H p � z (mod p ). However, we expect � β that one can work modulo p e with similar complexity (times some power � � for all p f ≤ X with α � of e ). It would still remain to compute H p f � z � β f ≥ 2; this requires O ( X 3 / 2 log X ) as written, but other techniques can reduce this to O ( X log ? X ) even without amortization. Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 5 / 18

  6. Review of the prerecorded talk Timings In this example α = ( 1 4 , 1 2 , 1 2 , 3 4 ) , β = ( 1 3 , 1 3 , 2 3 , 2 3 ) , z = 1 5 . This L -function has weight 1, so � α � � H p � z is uniquely determined by its reduction mod p . (See § 5.4 of the paper for more � β implementation details, and § 5.5 for a worked example.) X Amortized Sage Magma 2 10 0.07s 0.39s 0.11s 2 11 0.05s 0.68s 0.35s 2 12 0.06s 2.12s 1.29s 2 13 0.08s 7.39s 4.83s 2 14 0.12s 26.0s 18.2s 2 15 0.18s 92.3s 68.4s 2 16 0.34s 343s 280s 2 17 0.80s 1328s 1190s 2 18 2 19 2 20 2 21 2 22 2 23 2 24 2 25 2 26 X Amortized 1.81s 4.59s 10.7s 24.6s 58.0s 135s 322s 857s 1948s Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 6 / 18

  7. Overview of the algorithm Contents Review of the prerecorded talk 1 Overview of the algorithm 2 A worked example 3 Future directions 4 Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 7 / 18

  8. Overview of the algorithm Setup Modulo p , the trace formula becomes   p − 2 r Γ p ( α j + m ) / Γ p ( α j ) � � α � � �  z m ± p ∗ H p � z ≡ (mod p ) . �  β Γ p ( β j + m ) / Γ p ( β j ) m =0 j =1 Call the m -th summand P m . Suppose we had f ( m ) , g ( m ) ∈ Z [ m ] so that P m +1 ≡ f ( m ) g ( m ) P m (mod p ) . We could then set � g ( m ) � � 1 � 0 0 B ( m ) := = g ( m ) g ( m ) f ( m ) 1 f ( m ) / g ( m ) and then use remainder products to compute � 1 0 � B (0) . . . B ( p − 2) ≡ g (0) · · · g ( p − 2) (mod p ) . � p − 2 m =0 P m P p − 1 Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 8 / 18

  9. Overview of the algorithm Two related issues The factor ± p ∗ is determined by the zigzag function ∗ at m p − 1 : Z α,β : [0 , 1] → Z , Z α,β ( x ) := # { j : α j ≤ x } − # { j : β j ≤ x } . m This creates a “discontinuity” when p − 1 passes through α j or β j . Figure: Z α,β ( x ) for α = ( 1 4 , 1 2 , 1 2 , 3 4 ) , β = ( 1 3 , 1 3 , 2 3 , 2 3 ) Similar “discontinuities” arise from the functional equation for Γ p : � − x Γ p ( x ) x / ∈ p Z p Γ p ( x + 1) = − Γ p ( x ) x ∈ p Z p ∗ Z α,β also determines the weight and Hodge numbers of the L -function. Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 9 / 18

  10. Overview of the algorithm Resolution of the issues We resolve both issues by “ferrying”. † We break the summation at ⌊ α j ( p − 1) ⌋ , ⌊ β j ( p − 1) ⌋ , and separate primes into classes modulo lcd ( α, β ). Within each range and congruence class, we do a single amortized computation of matrix products. We then do non-amortized computations of transition matrices to “portage” or “ferry” across the breaks. For each p , we put the ranges and transitions together to obtain a product � 1 0 � computing a scalar multiple of (mod p ). � p − 2 m =0 P m P p − 1 † At ANTS-XIII in Madison, “portage” would have been a better metaphor. Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 10 / 18

  11. A worked example Contents Review of the prerecorded talk 1 Overview of the algorithm 2 A worked example 3 Future directions 4 Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 11 / 18

  12. A worked example Setup Take α = ( 1 4 , 1 2 , 1 2 , 3 4 ) , β = ( 1 3 , 1 3 , 2 3 , 2 3 ), z = 1 5 . We see that the L -function has weight 1 by plotting the zigzag function (again): In particular, computing H p modulo p is enough to determine it exactly. Denote the intervals we see by I 0 , . . . , I 5 . Since we are only working modulo p , the only intervals that contribute to the sum are I 2 = ( 1 3 , 1 2 ) and I 4 = ( 2 3 , 3 4 ). However , we do still have to compute over the other integrals in order to update the product! Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 12 / 18

  13. A worked example Amortized products For simplicity, we focus on the case p ≡ 7 (mod 12). In the intervals that contribute to the sum, we take in the matrix product f 2 , 7 ( k ) = 5184 k 4 + 8640 k 3 + 4428 k 2 + 852 k + 55 , g 2 , 7 ( k ) = 25920 k 4 + 69120 k 3 + 63360 k 2 + 23040 k + 2880 , f 4 , 7 ( k ) = 5184 k 4 + 12096 k 3 + 9612 k 2 + 2820 k + 175 , g 4 , 7 ( k ) = 25920 k 4 + 86400 k 3 + 106560 k 2 + 57600 k + 11520 . Suppose we did the remainder forest and then took p = 67. We’d see � 65 � � 54 � 0 0 S 2 (67) = , S 4 (67) = . 34 5 25 41 Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 13 / 18

  14. A worked example More amortized products and the portage In order to compute the correct sum, we also do similar computations over the other intervals. At p = 67, we get � 38 � � 50 � 0 0 S 0 (67) = , S 1 (67) = , 0 62 0 47 � 1 � � 1 � 0 0 S 3 (67) = , S 5 (67) = . 0 16 0 38 For the “ferries”, we work directly with p = 67 to compute � 1 � 1 � � 1 � � 0 0 0 T 0 (67) = , T 1 (67) = , T 2 (67) = , 0 6 0 31 − 1 12 � 1 � 1 � 1 � � � 0 0 0 T 3 (67) = , T 4 (67) = , T 5 (67) = . − 1 40 − 1 40 − 1 31 Costa, Kedlaya, Roe Hypergeometric L -functions (live) ANTS, July 2, 2020 14 / 18

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