generic and complete techniques for straight line string
play

Generic and Complete Techniques for Straight- Line String - PowerPoint PPT Presentation

Generic and Complete Techniques for Straight- Line String Constraints T aolue Chen (Birkbeck) Matthew Hague (Royal Holloway) Anthony W. Lin (Kaiserslautern) Philipp Ruemmer (Uppsala) Zhilin Wu (Chinese Academy of Science) 1 / 51 Abstract


  1. Generic and Complete Techniques for Straight- Line String Constraints T aolue Chen (Birkbeck) Matthew Hague (Royal Holloway) Anthony W. Lin (Kaiserslautern) Philipp Ruemmer (Uppsala) Zhilin Wu (Chinese Academy of Science) 1 / 51

  2. Abstract ● New techniques for string constraint solving – Straight-line fragment – String operations/assertions not fjxed – T wo semantic-conditions (regularity) – Proof of decidability ● Implementation – OSTRICH solver – Competitive, expressive, and complete 2 / 51

  3. String Programs S ::= x := f(x1, …, xn) | assert g(x1, …, xn) | S1; S2 ● f is a function from strings to strings ● g is a function from strings to boolean ● ; is sequential composition 3 / 51

  4. Example assert x in a*b*; assert y in b*; z := concat(x, y) ; assert z in a*b*; 4 / 51

  5. Example assert in(x, a*b*) assert in(x, a*b*) assert x in a*b*; assert y in b*; z := concat(x, y) ; assert z in a*b*; 5 / 51

  6. Example assert in(x, a*b*) assert in(x, a*b*) assert x in a*b*; assert y in b*; z := concat(x, y) ; Solution assert z in a*b*; 6 / 51

  7. Example assert in(x, a*b*) assert in(x, a*b*) assert x in a*b*; assert y in b*; z := concat(x, y) ; Solution assert z in a*b*; ● x = aa 7 / 51

  8. Example assert in(x, a*b*) assert in(x, a*b*) assert x in a*b*; assert y in b*; z := concat(x, y) ; Solution assert z in a*b*; ● x = aa ● y = bb 8 / 51

  9. Example assert in(x, a*b*) assert in(x, a*b*) assert x in a*b*; assert y in b*; z := concat(x, y) ; Solution assert z in a*b*; ● x = aa ● y = bb ● (z = aabb) 9 / 51

  10. Straight-Line Fragment ● Similar to single-static assignment form – Each variable only assigned once – Variables not used before they are assigned ● Free-variables are never assigned – (Our language has no loop support) 10 / 51

  11. Straight-Line Fragment ● Similar to single-static assignment form – Each variable only assigned once – Variables not used before they are assigned ● Free-variables are never assigned – (Our language has no loop support) Non-Example x := concat(y,z) y := x y := z 11 / 51

  12. Straight-Line Fragment ● Similar to single-static assignment form – Each variable only assigned once – Variables not used before they are assigned Assigned after use ● Free-variables are never assigned Assigned after use (Circular dependency) (Circular dependency) – (Our language has no loop support) Non-Example x := concat(y,z) y := x y := z 12 / 51

  13. Straight-Line Fragment ● Similar to single-static assignment form – Each variable only assigned once – Variables not used before they are assigned Assigned after use ● Free-variables are never assigned Assigned after use (Circular dependency) (Circular dependency) – (Our language has no loop support) Non-Example x := concat(y,z) Double assignment y := x Double assignment y := z 13 / 51

  14. Symbolic Execution ● Explore paths through a program ● Variables represented symbolically ● If-conditions &c. lead to constraints on variables ● Path is feasible if constraints are satisfjable ● Verifjcation / T est-case generation ● Famous tools such as Klee 14 / 51

  15. Example Path Program function get_user_header(name) while name.contains(“<script>”) name = name.replaceAll(“<script>”, “”) header = “<h1>” + name + “</h1>” assert not header.contains(“script”) end 15 / 51

  16. Example Path Program function get_user_header(name) while name.contains(“<script>”) name = name.replaceAll(“<script>”, “”) header = “<h1>” + name + “</h1>” assert not header.contains(“script”) end 16 / 51

  17. Example Path Program assert contains(n1, “<script>”); function get_user_header(name) while name.contains(“<script>”) name = name.replaceAll(“<script>”, “”) header = “<h1>” + name + “</h1>” assert not header.contains(“script”) end 17 / 51

  18. Example Path Program assert contains(n1, “<script>”); function get_user_header(name) n2 := replaceAll(n1, “<script>”, “”); while name.contains(“<script>”) name = name.replaceAll(“<script>”, “”) header = “<h1>” + name + “</h1>” assert not header.contains(“script”) end 18 / 51

  19. Example Path Program assert contains(n1, “<script>”); function get_user_header(name) n2 := replaceAll(n1, “<script>”, “”); while name.contains(“<script>”) assert contains(n2, “<script>”); name = name.replaceAll(“<script>”, “”) header = “<h1>” + name + “</h1>” assert not header.contains(“script”) end 19 / 51

  20. Example Path Program assert contains(n1, “<script>”); function get_user_header(name) n2 := replaceAll(n1, “<script>”, “”); while name.contains(“<script>”) assert contains(n2, “<script>”); name = name.replaceAll(“<script>”, “”) header = “<h1>” + name + “</h1>” n3 := replaceAll(n2, “<script>”, “”); assert not header.contains(“script”) end 20 / 51

  21. Example Path Program assert contains(n1, “<script>”); function get_user_header(name) n2 := replaceAll(n1, “<script>”, “”); while name.contains(“<script>”) assert contains(n2, “<script>”); name = name.replaceAll(“<script>”, “”) header = “<h1>” + name + “</h1>” n3 := replaceAll(n2, “<script>”, “”); assert not header.contains(“script”) assert not contains(n3, “<script>”); end 21 / 51

  22. Example Path Program assert contains(n1, “<script>”); function get_user_header(name) n2 := replaceAll(n1, “<script>”, “”); while name.contains(“<script>”) assert contains(n2, “<script>”); name = name.replaceAll(“<script>”, “”) header = “<h1>” + name + “</h1>” n3 := replaceAll(n2, “<script>”, “”); assert not header.contains(“script”) assert not contains(n3, “<script>”); hdr = concat(“<h1>”, n3, “</h1>”); end 22 / 51

  23. Example Path Program assert contains(n1, “<script>”); function get_user_header(name) n2 := replaceAll(n1, “<script>”, “”); while name.contains(“<script>”) assert contains(n2, “<script>”); name = name.replaceAll(“<script>”, “”) header = “<h1>” + name + “</h1>” n3 := replaceAll(n2, “<script>”, “”); assert not header.contains(“script”) assert not contains(n3, “<script>”); hdr = concat(“<h1>”, n3, “</h1>”); end assert contains(hdr, “<script>”); 23 / 51

  24. Example Path Program assert contains(n1, “<script>”); function get_user_header(name) n2 := replaceAll(n1, “<script>”, “”); while name.contains(“<script>”) assert contains(n2, “<script>”); name = name.replaceAll(“<script>”, “”) header = “<h1>” + name + “</h1>” n3 := replaceAll(n2, “<script>”, “”); assert not header.contains(“script”) assert not contains(n3, “<script>”); hdr = concat(“<h1>”, n3, “</h1>”); end assert contains(hdr, “<script>”); Assertion in code negated 24 / 51

  25. Example Path Program assert contains(n1, “<script>”); function get_user_header(name) n2 := replaceAll(n1, “<script>”, “”); while name.contains(“<script>”) assert contains(n2, “<script>”); name = name.replaceAll(“<script>”, “”) header = “<h1>” + name + “</h1>” n3 := replaceAll(n2, “<script>”, “”); assert not header.contains(“script”) assert not contains(n3, “<script>”); hdr = concat(“<h1>”, n3, “</h1>”); end assert contains(hdr, “<script>”); Assertion in code negated ● No solution: path correct! 25 / 51

  26. Solving Such Constraints Straight-line with ● Regular constraints, concat, fjnite transductions – x := concat(y, z); x’ = T(x); assert x’ in a*b*; – EXPSPACE-c / PSPACE-c [Lin, Barcelo, 2016] ● Regular constraints, concat, replaceAll – x := replaceAll(y, e, z) – Undecidable if e can be a variable – EXPSPACE / PSPACE if e is a regular expression – Undecidable with length constraints – [Chen et al, 2018] 26 / 51

  27. Generic Approach Which string constraints can we allow? ● Maintain decidability ● Expressivity: capture most benchmarks ● Easy: solve with a straight-forward algorithm ● Extensible: allow users-defjned string functions ● Effjcient: solve competitively 27 / 51

  28. Basic Approach: Go Backwards For one variable, assume: ● assert g(x) – g is a regular constraint ● x : = f(y) – suppose x must satisfy a regular constraint – take the weakest precondition Pre(f, x) – Pre(f, x) is a regular constraint on y 28 / 51

  29. Basic Approach: Go Backwards For one variable, assume: ● assert g(x) – g is a regular constraint ● x : = f(y) – suppose x must satisfy a regular constraint – take the weakest precondition Pre(f, x) – Pre(f, x) is a regular constraint on y Regular contraints on output variables become regular constraints on input variables. 29 / 51

Recommend


More recommend