ECEN 5032 Data Networks Communication Theory: PAM Examples Peter - PowerPoint PPT Presentation

� ECEN 5032 Data Networks Communication Theory: PAM Examples Peter Mathys mathys@colorado.edu University of Colorado, Boulder Data Networks, PAM Examples, c 1996–2005, P . Mathys – p.1/8

� ☎ ✆ � ✁✄✂ Polar PAM, Rect. , Width PAM, Rectangular Pulse of Width T B , F B = 1000 Baud 1.5 1 0.5 s(t) 0 −0.5 −1 −1.5 0 5 10 15 20 25 30 35 40 t [msec] PSD, P x =1, P x (f 1 ,f 2 ) = 97.4285%, F s =176400 Hz, N=88200, NN=2, ∆ f =2 Hz 0 −10 10log 10 (S x (f)) [dB] −20 −30 −40 −50 −60 −4000 −3000 −2000 −1000 0 1000 2000 3000 4000 f [Hz] Data Networks, PAM Examples, c 1996–2005, P . Mathys – p.2/8

� ☎ ✆ � Uniploar PAM, Rect. ✁✄✂ , Width Unipolar PAM, Rectangular Pulse of Width T B , F B = 1000 Baud 1.5 1 0.5 s(t) 0 −0.5 −1 −1.5 0 5 10 15 20 25 30 35 40 t [msec] PSD, P x =0.51698, P x (f 1 ,f 2 ) = 98.7566%, F s =176400 Hz, N=88200, NN=2, ∆ f =2 Hz 0 −10 10log 10 (S x (f)) [dB] −20 −30 −40 −50 −60 −4000 −3000 −2000 −1000 0 1000 2000 3000 4000 f [Hz] Data Networks, PAM Examples, c 1996–2005, P . Mathys – p.3/8

� ☎ ✆ � ✁✄✂ Uniploar PAM, Rect. , Width �✂✁ Unipolar PAM, Rectangular Pulse of Width T B /2, F B = 1000 Baud 1.5 1 0.5 s(t) 0 −0.5 −1 −1.5 0 5 10 15 20 25 30 35 40 t [msec] PSD, P x =0.25342, P x (f 1 ,f 2 ) = 95.0163%, F s =176400 Hz, N=88200, NN=2, ∆ f =2 Hz 0 −10 10log 10 (S x (f)) [dB] −20 −30 −40 −50 −60 −4000 −3000 −2000 −1000 0 1000 2000 3000 4000 f [Hz] Data Networks, PAM Examples, c 1996–2005, P . Mathys – p.4/8

� ☎ ✁ ✆ � ✁✄✂ Polar PAM, Tri. , Width PAM, Triangular Pulse of Width 2T B , F B = 1000 Baud 1.5 1 0.5 s(t) 0 −0.5 −1 −1.5 0 5 10 15 20 25 30 35 40 t [msec] PSD, P x =0.67555, P x (f 1 ,f 2 ) = 99.9859%, F s =176400 Hz, N=88200, NN=2, ∆ f =2 Hz 0 −10 10log 10 (S x (f)) [dB] −20 −30 −40 −50 −60 −4000 −3000 −2000 −1000 0 1000 2000 3000 4000 f [Hz] Data Networks, PAM Examples, c 1996–2005, P . Mathys – p.5/8

� ☎ ✆ � ✁ ✂ ✄ ✁ � ✁✄✂ Polar PAM, Rcf. , Width , B , α =0.2, F B = 1000 Baud PAM, Raised Cosine in Frequency Pulse of Width T 1.5 1 0.5 s(t) 0 −0.5 −1 −1.5 0 5 10 15 20 25 30 35 40 t [msec] PSD, P x =0.95616, P x (f 1 ,f 2 ) = 99.9992%, F s =176400 Hz, N=88200, NN=2, ∆ f =2 Hz 0 −10 10log 10 (S x (f)) [dB] −20 −30 −40 −50 −60 −4000 −3000 −2000 −1000 0 1000 2000 3000 4000 f [Hz] Data Networks, PAM Examples, c 1996–2005, P . Mathys – p.6/8

� Prob Symbol Error: PSK, QAM Probability of Symbol Error P s (E) for M−ary (Equally Likely) Digital PAM 0 10 M=2, polar M=2 unipolar M=4 QPSK −1 10 M=8 PSK M=16 QAM−16 M=64 QAM−64 −2 10 −3 10 P s (E) −4 10 −5 10 −6 10 −7 10 −8 10 0 2 4 6 8 10 12 14 16 18 20 E b /N 0 [dB] Data Networks, PAM Examples, c 1996–2005, P . Mathys – p.7/8

� Prob of Symbol Error: FSK Probability of Symbol Error P s (E) for M−ary (Equally Likely) Digital PAM 0 10 M=2, polar M=4 QPSK M=2 FSK coh −1 10 M=2 FSK noncoh M=4 FSK coh M=8 FSK coh −2 10 −3 10 P s (E) −4 10 −5 10 −6 10 −7 10 −8 10 0 2 4 6 8 10 12 14 16 E b /N 0 [dB] Data Networks, PAM Examples, c 1996–2005, P . Mathys – p.8/8