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COMPLETELY MONOTONE FUNCTIONS IN THE STUDY OF A CLASS OF FRACTIONAL - PowerPoint PPT Presentation

COMPLETELY MONOTONE FUNCTIONS IN THE STUDY OF A CLASS OF FRACTIONAL EVOLUTION EQUATIONS Emilia Bazhlekova Joint Seminar of Analysis, Geometry and Topology Department Institute of Mathematics and Informatics Bulgarian Academy of Sciences


  1. COMPLETELY MONOTONE FUNCTIONS IN THE STUDY OF A CLASS OF FRACTIONAL EVOLUTION EQUATIONS Emilia Bazhlekova Joint Seminar of Analysis, Geometry and Topology Department Institute of Mathematics and Informatics Bulgarian Academy of Sciences

  2. Completely monotone functions ( CMF ) Bulgarian contributions: N. Obreshkov, Y. Tagamlitski, Bl. Sendov, H. Sendov A function f : (0 , ∞ ) → R is called completely monotone if it is of class C ∞ and ( − 1) n f ( n ) ( t ) ≥ 0 , for all t > 0 , n = 0 , 1 , ... Elementary examples: � b + µt − 1 � t − 1 ; e f ( t ) , f ∈ CMF ; e − λt ; ( λ + µt ) − ν ; ln ; where λ, µ, ν > 0 , b ≥ 1 . Bernstein’s theorem: f ( t ) ∈ CMF iff � ∞ e − tx dg ( x ) , f ( t ) = 0 where g ( x ) is nondecreasing and the integral converges for 0 < t < ∞ . Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 2/26

  3. Bernstein functions ( BF ) and some useful properties A C ∞ function f : (0 , ∞ ) → R is called a Bernstein function if f ( t ) ≥ 0 and f ′ ( t ) ∈ CMF . Proposition: (a) The class CMF is closed under pointwise addition and multiplication; The class BF is closed under pointwise addition, but, in general not under multiplication; (b) If f ∈ CMF and ϕ ∈ BF , then the composite function f ( ϕ ) ∈ CMF ; (c) If f ∈ BF , then f ( t ) /t ∈ CMF ; (d) Let f ∈ L 1 loc ( R + ) be a nonnegative and nonincreasing function, such that lim t → + ∞ f ( t ) = 0 . Then ϕ ( s ) = s � f ( s ) ∈ BF ; loc ( R + ) and f ∈ CMF , then � (e) If f ∈ L 1 f ( s ) admits analytic extension to the sector | arg s | < π and | arg � f ( s ) | ≤ | arg s | , | arg s | < π. Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 3/26

  4. The operators of fractional integration and differentiation J α t - the Riemann-Liouville fractional integral of order α > 0 : � t 1 J α ( t − τ ) α − 1 f ( τ ) dτ, t f ( t ) := α > 0 , Γ( α ) 0 where Γ( · ) is the Gamma function. D α t - the Riemann-Liouville fractional derivative C D α t - the Caputo fractional derivative D 1 t = C D 1 t = J 1 − α D 1 t = D 1 t J 1 − α C D α D α t = d/dt ; t , , α ∈ (0 , 1) . t t Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 4/26

  5. Mittag-Leffler function Fractional relaxation equation ( λ > 0 , 0 < α ≤ 1 ): C D α t u ( t ) + λu ( t ) = f ( t ) , t > 0 , u (0) = c 0 . The solution is given by: � t τ α − 1 E α,α ( − λτ α ) f ( t − τ ) dτ. u ( t ) = c 0 E α ( − λt α ) + 0 Mittag-Leffler function ( α, β ∈ R , α > 0 ): � ∞ ( − t ) k E α,β ( − t ) = Γ( αk + β ) , E α ( − t ) = E α, 1 ( − t ) . k =0 E 1 ( − t ) = e − t ∈ CMF E α ( − t ) ∈ CMF , iff 0 < α < 1 (Pollard, 1948) E α,β ( − t ) ∈ CMF , iff 0 ≤ α ≤ 1 , α ≤ β (Schneider, 1996; Miller, 1999) Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 5/26

  6. Plots of E α ( − t α ) for different values of α Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 6/26

  7. Plots of t α − 1 E α,α ( − t α ) for different values of α Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 7/26

  8. Fractional evolution equation of distributed order Two alternative forms: � 1 µ ( β ) C D β t u ( t ) dβ = Au ( t ) , t > 0 , (1) 0 and � 1 µ ( β ) D β u ′ ( t ) = t Au ( t ) dβ, t > 0 , (2) 0 A - closed linear unbounded operator densely defined in a Banach space X Initial condition: u (0) = a ∈ X Reference: E. Bazhlekova, Completely monotone functions and some classes of fractional evolution equations, preprint, 2015, arXiv:1502.04647 Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 8/26

  9. Two cases for the weight function µ : • discrete distribution m � µ ( β ) = δ ( β − α ) + b j δ ( β − α j ) , (3) j =1 where 1 > α > α 1 ... > α m > 0 , b j > 0 , j = 1 , ..., m, m ≥ 0 , and δ is the Dirac delta function; • continuous distribution µ ∈ C [0 , 1] , µ ( β ) ≥ 0 , β ∈ [0 , 1] , (4) and µ ( β ) � = 0 on a set of a positive measure. Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 9/26

  10. Discrete distribution: Multi-term time-fractional equations in the Caputo sense m � α j C D α C D t u ( t ) + b j t u ( t ) = Au ( t ) , t > 0 , (5) j =1 and in the Riemann-Liouville sense m � α j u ′ ( t ) = D α t Au ( t ) + b j D t Au ( t ) , t > 0 (6) j =1 If m = 0 (single-term equations): problem (5) is equivalent to (6) with α replaced by 1 − α . All problems are generalizations of the classical abstract Cauchy problem u ′ ( t ) = Au ( t ) , t > 0; u (0) = a ∈ X. (7) Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 10/26

  11. Solution u ( t ) of (5) with A = − 1 for: m = 1 , α = 0 . 75 , α 1 = 0 . 25 , m = 0 , α = 0 . 25 m = 0 , α = 0 . 75 . Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 11/26

  12. Solution u ( t ) of (5) with A = − 1 for: m = 2 , α = 0 . 75 , α 1 = 0 . 5 , α 2 = 0 . 25 m = 1 , α = 0 . 75 , α 1 = 0 . 25 , m = 0 , α = 0 . 25 m = 0 , α = 0 . 75 . Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 12/26

  13. Unified approach to the four problems Rewrite problems (1) and (2) as an abstract Volterra integral equation � t u ( t ) = a + k ( t − τ ) Au ( τ ) dτ, t ≥ 0; a ∈ X, 0 where k 1 ( s ) = ( h ( s )) − 1 , � � k 2 ( s ) = h ( s ) /s, In the continuous distribution case: � 1 µ ( β ) s β dβ. h ( s ) = 0 In the discrete distribution case: m � h ( s ) = s α + b j s α j . j =1 Define g i ( s ) = 1 / � k i ( s ) , i = 1 , 2 . Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 13/26

  14. Particular cases In the single-term case: k 1 ( t ) = t α − 1 t − α g 1 ( s ) = s α , g 2 ( s ) = s 1 − α , Γ( α ) , k 2 ( t ) = Γ(1 − α ) , In the double-term case: t − α t − α 1 k 1 ( t ) = t α − 1 E α − α 1 ,α ( − b 1 t α − α 1 ) , k 2 ( t ) = Γ(1 − α ) + b 1 Γ(1 − α 1 ) , s g 1 ( s ) = s α + b 1 s α 1 , g 2 ( s ) = s α + b 1 s α 1 = s � k 1 ( s )!!! In the case of continuous distribution in its simplest form: µ ( β ) ≡ 1 . g 1 ( s ) = s − 1 g 2 ( s ) = s log s log s , s − 1 . Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 14/26

  15. Properties of the kernels Theorem. Let µ ( β ) be either of the form (3) or of the form (4) with the additional assumptions µ ∈ C 3 [0 , 1] , µ (1) � = 0 , and µ (0) � = 0 or µ ( β ) = aβ ν as β → 0 , where a, ν > 0 . Then for i = 1 , 2 , : (a) k i ∈ L 1 loc ( R + ) and lim t → + ∞ k i ( t ) = 0 ; (b) k i ( t ) ∈ CMF for t > 0 ; (c) k 1 ∗ k 2 ≡ 1 ; (d) g i ( s ) ∈ BF for s > 0 ; (e) g i ( s ) /s ∈ CMF for s > 0 ; (f) g i ( s ) admits analytic extension to the sector | arg s | < π and | arg g i ( s ) | ≤ | arg s | , | arg s | < π. In the discrete distribution case a stronger inequality holds: | arg g i ( s ) | ≤ α | arg s | , | arg s | < π. Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 15/26

  16. The classical abstract Cauchy problem: u ′ ( t ) = Au ( t ) , t > 0; u (0) = a ∈ X. Main result: Assume that the classical Cauchy problem is well-posed with solution u ( t ) satisfying � u ( t ) � ≤ M � a � , t ≥ 0 . Then any of the problems � 1 µ ( β ) C D β t u ( t ) dβ = Au ( t ) , t > 0 , u (0) = a ∈ X, 0 � 1 µ ( β ) D β u ′ ( t ) = t Au ( t ) dβ, t > 0 , u (0) = a ∈ X 0 is well-posed with solution satisfying the same estimate. Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 16/26

  17. The classical abstract Cauchy problem: u ′ ( t ) = Au ( t ) , t > 0; u (0) = a ∈ X. T ( t ) - solution operator (defined by T ( t ) a = u ( t ) , t ≥ 0 ); R ( s, A ) - resolvent operator of A : � ∞ R ( s, A ) = ( s − A ) − 1 = e − st T ( t ) dt, s > 0 , 0 The Hille-Yosida theorem states that the classical Cauchy problem is well-posed with solution operator T ( t ) such that � T ( t ) � ≤ M, t ≥ 0 iff R ( s, A ) is well defined for s ∈ (0 , ∞ ) and � R ( s, A ) n � ≤ M/s n , s > 0 , n ∈ N . Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 17/26

  18. Abstract Volterra integral equation � t u ( t ) = a + k ( t − τ ) Au ( τ ) dτ, t ≥ 0; a ∈ X, 0 The Laplace transform of the solution operator S ( t ) � ∞ e − st S ( t ) dt, H ( s ) = s > 0 0 is given by H ( s ) = g ( s ) g ( s ) = 1 / � s R ( g ( s ) , A ) , k ( s ) . The Generation Theorem (Pruss, 1993) states that the integral equation is well- posed with solution operator S ( t ) satisfying � S ( t ) � ≤ M, t ≥ 0 , iff � H ( n ) ( s ) � ≤ M n ! s n +1 , for all s > 0 , n ∈ N 0 . Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 18/26

  19. Main result Theorem. Suppose that the classical Cauchy problem is well-posed with solution u ( t ) satisfying � u ( t ) � ≤ M � a � , t ≥ 0 . Then problems (1) and (2) are well-posed and their solutions satisfy the same estimate. Proof: We know � R ( s, A ) n � ≤ M/s n , s > 0 , n ∈ N . We have to prove � H ( n ) ( s ) � ≤ M n ! s n +1 , for all s > 0 , n ∈ N 0 , where H ( s ) = g ( s ) s R ( g ( s ) , A ) , and g ( s ) = 1 / � k ( s ) , R ( s, A ) = ( s − A ) − 1 . Joint Seminar of Analysis, Geometry and Topology Dept. 24.03.2015, p. 19/26

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