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Cellular Calcium Dynamics Jussi Koivumki, Glenn Lines & Joakim - PowerPoint PPT Presentation

Cellular Calcium Dynamics Jussi Koivumki, Glenn Lines & Joakim Sundnes Cellular calcium dynamics A real cardiomyocyte is obviously not an empty cylinder, where Ca 2+ just diffuses freely... ...instead it's filled with myofibrils,


  1. Cellular Calcium Dynamics Jussi Koivumäki, Glenn Lines & Joakim Sundnes

  2. Cellular calcium dynamics

  3. A real cardiomyocyte is obviously not an empty cylinder, where Ca 2+ just diffuses freely... ...instead it's filled with myofibrils, mitochondria, sarcoplasmic reticulum, t-tubule, etc. junctional sarcoplasmic reticulum network sarcoplasmic reticulum

  4. Cellular calcium dynamics: influx This triggers Membrane Ca 2+ channels open during release of Ca 2+ the action potential from the sarcoplasmic reticulum (SR) via ryanodine receptors (RyRs)

  5. Cellular calcium dynamics: efflux Primarily, Ca 2+ is removed from the cytosol by sarcoplasmic reticulum Ca 2+ ATPase (SERCA) Secondarily, Ca 2+ is extruded by the Na + /Ca 2+ exchanger (NCX)

  6. Cellular calcium dynamics Let's take a step back and view development… Why has calcium dynamics evolved to be so complex?

  7. In addition to actions on the contractile filaments, calcium signals also regulate ● the activity of kinases, phosphatases, ion channels, exchangers and transporters, as well as ● function, growth, gene expression, differentiation, and development of cardiac muscle cells. ● The multifunctional roles require 1) high dynamic gain, as well as 2) fast propagation and 3) accurate spatial control of the calcium signals.

  8. What does “high dynamic gain” mean in the context of calcium dynamics? ● In the adult mammalian heart, calcium-induced calcium release establishes an outstanding dynamic range of calcium signals up to 1000-fold increase in the calcium concentration in only tens of – milliseconds. ● This is a totally different scale than, for example, intracellular Na+ and K+ concentrations, which vary by some tens of percent, at most. –

  9. What defines propagation speed of calcium signals in the cytosol? ● In all biological systems, diffusion is a ubiquitous mechanism equalizing the concentration gradients of all moving particles in the cells cytosol. It forms also the basis for distribution of Ca 2+ ions in the cytosol. – ● In general, in muscle cells diffusion of ions (K+, Na+, Cl-) in cytosol is relatively fast, only 2-fold slower than in water. ● However, diffusion of Ca2+ is an exception from this rule, it is 50-times slower in the cytosol than in pure water. This is due to the stationary and mobile calcium buffers that slow down – the calcium diffusion remarkably.

  10. Why is the propagation speed of calcium signals in the cytosol so slow? ● The “job” of a cardiomyocyte is to contract upon electrical stimulus and not to diffuse calcium as fast as possible... 1) Assembly of contractile elements is progressively augmented during development to fulfill the demand for more forceful contraction 2) Capacity of SR calcium stores is synchronously increased to provide more calcium release for activating contraction. ● Both of these developmental steps lead to increased cytosolic calcium buffering.

  11. How to ensure fast (enough) propagation of calcium signals in the cytosol?

  12. Main players in calcium handling are: ● Buffers ● Pumps ● Transporters/exchangers ● Ion channels

  13. Calcium buffers are large Ca 2+ binding proteins. CaM

  14. Well mixed concentrations If we assume a well mixed solution the concentration only vary with time, not space: dc dt = J IPR + J RyR + J in + J pm − J serca − J on + J o ff Where c is the calcium concentration, similarly for the endoplasmic content: dc e dt = γ ( J serca − J IPR − J RyR) − J on , e + J o ff , e where γ = v cyt / v e

  15. Calcium pumps Early model based on Hill-type formulation: V p c 2 J serca = K 2 p + c 2 Draw backs: Independent of c e and always positive, which is not the case when c e is large.

  16. Alternative formulation Two main configurations: E1 Calcium binding sites exposed to cytoplasma E2 Calcium binding sites exposed to endoplasmic reticulum

  17. Model reduction Assuming steady state between s 1 and s 2 , and t 2 and t 3 . And s 1 = s 1 + s 2 and ¯ introduce ¯ t 2 = t 2 + t 3 , s 1 = K 1 c 2 s 2 1 + c 2 ✓ ◆ ✓ ◆ 1 + K 1 s 1 = s 1 ¯ = s 2 c 2 K 1

  18. Calcium release Calcium released from internal stores is mediated by 2 types of channels (receptors) I Inositol (1,4,5)-triphosphate (IP 3 ) receptors I Ryanodine receptors

  19. Ryanodine Receptors, 7.2.9 I Sits at the surface of intra cellular calcium stores I Endoplasmic Reticulum (ER) I Sarcoplasmic Reticulum (SR) I Sensitive to calcium. Both activation and inactivation. I Upon stimulation calcium is released from the stores. I To di ff erent pathways I Triggering from action potential through extra cellular calcium inflow. I Calcium oscillations observed in some neurons at fixed membrane potentials.

  20. Compartments and fluxes in the model

  21. Model equations d [ c ] = J L1 − J P1 + J L2 − J P2 dt d [ c s ] = γ ( J P2 − J L2 ) dt Ca 2+ entry = k 1 ( c e − c ) , J L1 Ca 2+ extrusion = k 2 c , J P1 Ca 2+ release = k 3 ( c s − c ) , J L2 Ca 2+ uptake = k 4 c , J P2

  22. The calcium sensitivity Release modelled with Hill type dynamics: κ 2 c n J L2 = k 3 ( c s − c ) = ( κ 1 + d + c n )( c s − c ) K n

  23. Experiments and simulations

  24. I Good agreement between experiments and simulations I Inactivation through calcium not included, but does not seem to be an important aspect

  25. Bu ff ered di ff usion, 2.2.5 Consider bu ff ering of calcium: k + [Ca 2+ ] + [B] − → [CB] ← − k − Conservation implies: ∂ 2 c ∂ c ∂ t = D c ∂ x 2 + k � w − k + cv + f ( t , x , c ) ∂ 2 v ∂ v ∂ t = D b ∂ x 2 + k � w − k + cv ∂ 2 w ∂ w ∂ t = D b ∂ x 2 − k � w + k + cv where c = [Ca 2+ ], v = [B], and w = [CB]. Bu ff er is large compared to Ca 2+ so D b is used for both bound and unbound state.

  26. Quasi static assumption Adding the bu ff er equations yields, ∂ 2 ( v + w ) ∂ ( v + w ) = D b ∂ x 2 ∂ t Thus if v + w is initially uniform, it will stay uniform, v ( x ) + w ( x ) = w 0 If bu ff ering is fast compared to f : k � ( w 0 − v ) − k + cv = 0 so: v = K eq w 0 K eq + c , where K eq = k � / k +

  27. Eliminating v and w Subtracting the equations for c t and v t and then eliminating v and w yields: c t = D c + φ ( c ) D b c xx + D b φ 0 ( c ) 1 + φ ( c )( c x ) 2 + f ( t , x , c ) 1 + φ ( c ) 1 + φ ( c ) where φ ( c ) = K eq w 0 / (K eq + c ) 2 Bu ff ering thus gives rise to a non-linear transport equation with non-linear di ff usion coe ffi cient. If c << K eq , then φ ( c ) ≈ w 0 / K eq . D c + D b w 0 K eq D e ff = 1 + w 0 K eq I.e. a linear combination of D c and D b . Reaction rate is slowed by 1 / (1 + w 0 / K eq )

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