a paraconsistent sub logic of intuitionistic
play

A Paraconsistent Sub-Logic of Intuitionistic Propositional Logic - PowerPoint PPT Presentation

Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion A Paraconsistent Sub-Logic of Intuitionistic Propositional Logic Sankha S. Basu Department of Mathematics, Indraprastha Institute of


  1. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion A Paraconsistent Sub-Logic of Intuitionistic Propositional Logic Sankha S. Basu Department of Mathematics, Indraprastha Institute of Information Technology, New Delhi, India 8th Indian Conference on Logic and its Applications (ICLA), 2019 Indian Institute of Technology Delhi, India March 05, 2019

  2. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion Scheme 1 Paraconsistency 2 Paraconsistent intuitionistic logic 3 Axiomatization 4 Soundness and Completeness 5 Conclusion

  3. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion Scheme 1 Paraconsistency 2 Paraconsistent intuitionistic logic 3 Axiomatization 4 Soundness and Completeness 5 Conclusion

  4. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion Paraconsistency Definition A theory (i.e., a set of sentences closed under some deductive relation) is said to be (negation) consistent if for no sentence α is both α and ¬ α provable, else inconsistent . A theory is said to be non-trivial if not every formula is provable, else trivial . Definition A logic is said to be paraconsistent or inconsistency tolerant if it admits inconsistent but non-trivial theories. In other words, a paraconsistent logic is a logic where it is not always possible to derive everything from a contradiction.

  5. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion Paraconsistency Classical logic, and also many non-classical logics, such as intuitionistic logic, fail in this because of the so-called principle of ‘explosion’ by which, for any sentence α , { α, ¬ α } ⊢ β (ECQ : Ex contradictione quodlibet ) Thus a necessary condition for a logic to be paraconsistent is that its consequence relation be not explosive, thus invalidating ECQ.

  6. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion Scheme 1 Paraconsistency 2 Paraconsistent intuitionistic logic 3 Axiomatization 4 Soundness and Completeness 5 Conclusion

  7. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion Stage Setting Definition Given a similarity type ν , the absolutely free algebra Fm of type ν over a countably infinite set X of generators is called the formula algebra of type ν ; its underlying set will be denoted by Fm . The elements of Fm are called ν - terms or ν - formulas and referred to by the symbols t, s, . . . or α, β, ϕ, . . . . Members of X are called (propositional) variables and denoted by the symbols x, y, . . . or p, q, . . . . Definition A logic of type ν is a pair L = � Fm , ⊢ L � , where Fm is the formula algebra of type ν , and ⊢ L is the substitution-invariant consequence relation over Fm .

  8. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion Paraconsistent Intuitionistic Logic (PIL) = # � can be Paraconsistent intuitionistic logic PIL = � Fm , | semantically specified as follows. Fm is the formula algebra of type (2 , 2 , 2 , 1 , 0 , 0), namely, of the type containing the connectives ∧ , ∨ , − → , ¬ , 0 , 1. For any Heyting algebra A , we define its extension A # = A ∪ { ω } , where ω / ∈ A for all Heyting algebras A . Let S = { A # | A is a Heyting algebra } . The additional element ω satisfies the so-called contamination priniciple , that is, ¬ ω = ω and if A is any Heyting algebra, then for any a ∈ A , a ◦ ω = ω , where ◦ denotes any of the binary connectives ∧ , ∨ , − → . Finally, for any Σ ∪ { α } ⊆ Fm , we define = # α ⇐ ⇒ for every A # ∈ S and for every valuation Σ | v # : Fm → A # , v # [Σ] ⊆ { 1 , ω } implies v # ( α ) ∈ { 1 , ω } .

  9. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion = # and | Relating | = IL Theorem = # α if and only if there is a For all Σ ∪ { α } ⊆ Fm , we have that Σ | ∆ ⊆ Σ such that var(∆) ⊆ var( α ) and ∆ | = IL α . Moreover, since IL (intuitionistic propositional logic) is finitary, we can find such a ∆ ⊆ Σ that is finite. Proof Outline = # α . Let ∆ = { ϕ ∈ Σ | var( ϕ ) ⊆ var( α ) } . Suppose Σ | Suppose ∆ �| = IL α . So there exists a Heyting algebra A and a valuation v : Fm → A such that v [∆] = { 1 } but v ( α ) � = 1. We construct the valuation v # : Fm → A # as follows. � v ( p ) if p ∈ var( α ) v # ( p ) = ∈ var( α ) ω if p / For any ϕ ∈ Σ, either var( ϕ ) ⊆ var( α ) or var( ϕ ) ∩ (var(Σ) \ var( α )) � = ∅ . In the first case, v # ( ϕ ) = 1, and in the second case, v # ( ϕ ) = ω . Thus v # [Σ] ⊆ { 1 , ω } . Then v # ( α ) ∈ { 1 , ω } . Now, v # ( α ) = v ( α ) ∈ A and v ( α ) � = 1. So v # ( α ) / ∈ { 1 , ω } . This is a contradiction, which proves that ∆ | = IL α .

  10. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion = # and | Relating | = IL Proof Outline Conversely, suppose ∆ | = IL α for some ∆ ⊆ Σ with var(∆) ⊆ var( α ). Suppose v # : Fm → A # for some A # ∈ S be a valuation such that v # [Σ] ⊆ { 1 , ω } . The possible cases are v # ( p ) = ω for some p ∈ var( α ) or v # ( p ) � = ω for all p ∈ var( α ). In the first case, v # ( α ) = ω . In the second case, let A be the Heyting algebra corresponding to A # ∈ S and a 0 ∈ A (fixed). We construct a valuation v : Fm → A as follows. � v # ( p ) if p ∈ var( α ) v ( p ) = a 0 otherwise Then, since var(∆) ⊆ var( α ), v [∆] = v # [∆] ⊆ v # [Σ] ⊆ { 1 , ω } . So v [∆] ⊆ { 1 , ω } ∩ A = { 1 } . Thus v # ( α ) = v ( α ) = 1 ∈ { 1 , ω } . = # α . This proves that Σ |

  11. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion Scheme 1 Paraconsistency 2 Paraconsistent intuitionistic logic 3 Axiomatization 4 Soundness and Completeness 5 Conclusion

  12. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion An axiomatization of PIL Definition (HPIL) HPIL is the logic � Fm , ⊢ # � , where ⊢ # is the consequence relation of the deductive system with the following axioms and inference rule. 1 α − → ( β − → α ); 2 ( α − → ( β − → γ )) − → (( α − → β ) − → ( α − → γ )); 3 α − → ( β − → α ∧ β ); 4 α ∧ β − → α ; 5 α ∧ β − → β ; 6 α − → α ∨ β ; 7 β − → α ∨ β ; 8 ( α − → γ ) − → (( β − → γ ) − → ( α ∨ β − → γ )); 9 ( α − → β ) − → (( α − → ¬ β ) − → ¬ α ); 10 0 − → α ; α − → β α, [RMP] provided that var( α ) ⊆ var( β ) . β

  13. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion Connections with IL Remark Axioms (1)–(10) along with unrestricted modus ponens gives a Hilbert system for intuitionistic propositional logic (IL). It is easy to check that PIL fails to satisfy modus ponens (MP). However, it satisfies RMP as we will see later. Because of the restricted nature of the inference relation, HPIL is weaker than IL. However, the following result shows that both logics have the same theorems. Theorem For any ϕ ∈ Fm , ⊢ # ϕ if and only if ⊢ IL ϕ .

  14. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion Connections with IL Proof Outline ⇒ ) (= Immediate, since the axioms (1)–(10) are axioms of IL and RMP is also an instance of MP. ( ⇐ =) Suppose ⊢ IL ϕ and D = � ϕ 1 , . . . , ϕ n � is a proof of ϕ in IL. We use induction on the length n of D . In the inductive step, suppose ϕ = ϕ l is obtained by MP from ϕ i and ϕ j = ϕ i − → ϕ , where i, j < l . By the induction hypothesis, there are proofs of ϕ i , ϕ j in HPIL. Let � ψ 1 , . . . , ψ m � be the result of gluing these HPIL proofs so that ψ k = ϕ i ( k < m ) and ψ m = ϕ j = ϕ i − → ϕ .

  15. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion Connections with IL Proof Outline � p if p ∈ var( ϕ ) We use a substitution of variables: σ ( p ) = , a otherwise where a is some fixed variable in ϕ or 0 if var( ϕ ) = ∅ . Note that � σ ( ψ 1 ) , . . . , σ ( ψ m ) � is still a proof in HPIL. Now, σ ( ψ m ) = σ ( ψ k − → ϕ ) = σ ( ψ k ) − → σ ( ϕ ) = σ ( ψ k ) − → ϕ . Moreover, var( σ ( ψ k )) ⊆ var( ϕ ), by definition of σ . Thus ϕ follows from σ ( ψ k ) and σ ( ψ m ) by an application of RMP, and � σ ( ψ 1 ) , . . . , σ ( ψ k ) , . . . , σ ( ψ m ) , ϕ � is a proof of ϕ in HPIL.

  16. Paraconsistency Paraconsistent intuitionistic logic Axiomatization Soundness and Completeness Conclusion Restricted Deduction Theorem Theorem (Restricted Deduction Theorem) For any Σ ∪ { α, β } ⊆ Fm , we have the following. (i) Σ ∪ { α } ⊢ # β implies Σ ⊢ # α − → β . In particular, if α ⊢ # β then ⊢ # α − → β . (ii) If Σ ⊢ # α − → β and var( α ) ⊆ var( β ), then Σ ∪ { α } ⊢ # β . In particular, if ⊢ # α − → β and var( α ) ⊆ var( β ), then α ⊢ # β .

Recommend


More recommend