4.4 Coordinate Systems In general, people are more comfortable working with the vector space R n and its subspaces than with other types of vectors spaces and subspaces. The goal here is to impose coordinate systems on vector spaces, even if they are not in R n . THEOREM 7 The Unique Representation Theorem Let β = b 1 , … , b n be a basis for a vector space V . Then for each x in V , there exists a unique set of scalars c 1 , … , c n such that x = c 1 b 1 + ⋯ + c n b n . DEFINITION Suppose β = b 1 , … , b n is a basis for a vector space V and x is in V . The coordinates of x relative to the basis β (or the β − coordinates of x ) are the weights c 1 , … , c n such that x = c 1 b 1 + ⋯ + c n b n . In this case, the vector in R n c 1 x β = ⋮ c n is called the coordinate vector of x ( relative to β ), or the β − coordinate vector of x . 1
3 EXAMPLE: Let β = b 1 , b 2 where b 1 = and 1 0 1 b 2 = and let E = e 1 , e 2 where e 1 = and 1 0 0 e 2 = . 1 Solution: 2 If x β = , then 3 3 0 x = ____ . + ____ = 1 1 6 If x E = , then 5 1 0 x = ____ + ____ . = 0 1 2
x 2 7 6 5 4 3 2 1 x 1 1 2 3 4 5 6 7 Standard graph paper β − graph paper 3
From the last example, 6 3 0 2 . = 5 1 1 3 For a basis β = b 1 , … , b n , let c 1 c 2 b 1 b 2 ⋯ b n and x β = P β = ⋮ c n Then x = P β x β . We call P β the change-of-coordinates matrix from β to the standard basis in R n . Then − 1 x x β = P β − 1 is a change-of-coordinates matrix from the and therefore P β standard basis in R n to the basis β . 4
3 0 EXAMPLE: Let b 1 = , b 2 = , β = b 1 , b 2 and 1 1 6 x = . Find the change-of-coordinates matrix P β from β to 8 the standard basis in R 2 and change-of-coordinates matrix P β − 1 from the standard basis in R 2 to β . Solution b 1 b 2 and so P β = = − 1 1 0 3 0 3 − 1 = P β = − 1 1 1 1 3 6 2 − 1 to find x β = (b) If x = , then use P β . 8 6 1 0 6 3 − 1 x = Solution: x β = P β = − 1 1 8 3 5
Coordinate mappings allow us to introduce coordinate systems for unfamiliar vector spaces. Standard basis for P 2 : p 1 , p 2 , p 3 = 1, t , t 2 Polynomials in P 2 behave like vectors in R 3 . Since a + bt + ct 2 = ____ p 1 + ____ p 2 + ____ p 3 , a a + bt + ct 2 β = b c We say that the vector space R 3 is isomorphic to P 2 . 6
EXAMPLE: Parallel Worlds of R 3 and P 2 . Vector Space R 3 Vector Space P 2 a Vector Form: a + bt + bt 2 Vector Form: b c Vector Addition Example Vector Addition Example − 1 2 1 − 1 + 2 t − 3 t 2 + 2 + 3 t + 5 t 2 2 3 5 + = = 1 + 5 t + 2 t 2 − 3 5 2 Informally, we say that vector space V is isomorphic to W if every vector space calculation in V is accurately reproduced in W , and vice versa . Assume β is a basis set for vector space V . Exercise 25 (page 254) shows that a set u 1 , u 2 , … , u p in V is linearly independent if and only if u 1 β , u 2 β , … , u p β is linearly independent in R n . 7
EXAMPLE: Use coordinate vectors to determine if p 1 , p 2 , p 3 is a linearly independent set, where p 1 = 1 − t , p 2 = 2 − t + t 2 , and p 3 = 2 t + 3 t 2 . Solution: The standard basis set for P 2 is β = 1, t , t 2 . So p 1 β = , p 2 β = , p 3 β = Then 1 2 0 1 2 0 − 1 − 1 2 0 1 2 ⋯ 0 1 3 0 0 1 By the IMT, p 1 β , p 2 β , p 3 β is linearly ____________________ and therefore p 1 , p 2 , p 3 is linearly ____________________. Coordinate vectors also allow us to associate vector spaces with subspaces of other vectors spaces. 8
3 EXAMPLE Let β = b 1 , b 2 where b 1 = and 3 1 0 9 b 2 = and let H = span b 1 , b 2 . Find x β , if x = . 1 13 3 15 Solution: (a) Find c 1 and c 2 such that 3 0 9 c 1 + c 2 3 1 13 = 1 3 15 Corresponding augmented matrix: 3 0 9 1 0 3 3 1 13 0 1 4 ∽ 1 3 15 0 0 0 Therefore c 1 = ____ and c 2 = _____ and so x β = . 9
x 3 x 2 x 1 9 3 in R 3 is associated with the vector in R 2 13 4 15 H is isomorphic to R 2 10
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