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Suslins Problem and Martin Axiom Forcing Direct Limit Construction - PowerPoint PPT Presentation

Suslins Problem and Martin Axiom Suslins Problem Martin Axiom Iterated Suslins Problem and Martin Axiom Forcing Direct Limit Construction of the model 23 July 2014 Suslins Problem and Martin Axiom 1 / 14 Suslins


  1. Suslin’s Problem and Martin Axiom Suslin’s Problem Martin Axiom Iterated Suslin’s Problem and Martin Axiom Forcing Direct Limit Construction of the model 23 July 2014 Suslin’s Problem and Martin Axiom 1 / 14

  2. Suslin’s Problem and Martin Axiom Suslin’s Problem Martin Axiom Suslin’s Problem Iterated Forcing Is there a linearly ordered set which satisfies the countable Direct Limit chain condition (ccc) and is not separable? Construction of the model Suslin’s Problem and Martin Axiom 2 / 14

  3. Suslin’s Problem and Martin Axiom Suslin’s Problem Martin Axiom Suslin’s Problem Iterated Forcing Is there a linearly ordered set which satisfies the countable Direct Limit chain condition (ccc) and is not separable? Construction of the model Such a set is called a Suslin line. The existence of a Suslin line is equivalent to the existence of a normal Suslin tree. Suslin’s Problem and Martin Axiom 2 / 14

  4. Tree Suslin’s Problem and Martin Axiom A tree is a poset ( P , < ) such that ∀ x ∈ T { y : y < x } is well ordered by < . Suslin’s Problem Martin Axiom Iterated Forcing Direct Limit Construction of the model Suslin’s Problem and Martin Axiom 3 / 14

  5. Tree Suslin’s Problem and Martin Axiom A tree is a poset ( P , < ) such that ∀ x ∈ T { y : y < x } is well ordered by < . Suslin’s Problem Suslin Tree Martin Axiom Iterated A tree is called a Suslin tree if: Forcing 1 height ( T ) = ω 1 Direct Limit Construction 2 every branch in T is at most countable of the model 3 every antichain in T is at most countable A Suslin tree is called normal if: 1 T has a unique least point 2 each level of T is at most countable 3 x not maximal has infinitely many immediate successors 4 ∀ x ∈ T there is some z > x at each greater level 5 if o ( x ) = o ( y ) = β with β limit and { z : z < x } = { z : z < y } then x = y Suslin’s Problem and Martin Axiom 3 / 14

  6. Suslin’s Problem and Martin Axiom Suslin’s MA k Problem Martin Axiom If a poset ( P , < ) satisfies ccc and D is a collection of at most Iterated k dense subsets of P , then there exists a D -generic filter on P. Forcing Direct Limit Construction of the model Suslin’s Problem and Martin Axiom 4 / 14

  7. Suslin’s Problem and Martin Axiom Suslin’s MA k Problem Martin Axiom If a poset ( P , < ) satisfies ccc and D is a collection of at most Iterated k dense subsets of P , then there exists a D -generic filter on P. Forcing Direct Limit Lemma Construction of the model If MA ℵ 1 holds then there is no Suslin tree. Suslin’s Problem and Martin Axiom 4 / 14

  8. Suslin’s Problem and Martin Axiom Suslin’s MA k Problem Martin Axiom If a poset ( P , < ) satisfies ccc and D is a collection of at most Iterated k dense subsets of P , then there exists a D -generic filter on P. Forcing Direct Limit Lemma Construction of the model If MA ℵ 1 holds then there is no Suslin tree. Solovay-Tennenbaum = MA + 2 ℵ 0 > ℵ 1 . There is a model M of ZFC such that M | Suslin’s Problem and Martin Axiom 4 / 14

  9. Suslin’s Problem and Martin Axiom Suslin’s Problem Martin Axiom Let P be a forcing notion in M and G 1 ⊆ P a M -generic filter. Iterated Forcing Direct Limit Construction of the model Suslin’s Problem and Martin Axiom 5 / 14

  10. Suslin’s Problem and Martin Axiom Suslin’s Problem Martin Axiom Let P be a forcing notion in M and G 1 ⊆ P a M -generic filter. Iterated Let Q be a poset in M [ G 1 ] and G 2 ⊆ Q a M [ G 1 ]-generic filter. Forcing Direct Limit Construction of the model Suslin’s Problem and Martin Axiom 5 / 14

  11. Suslin’s Problem and Martin Axiom Suslin’s Problem Martin Axiom Let P be a forcing notion in M and G 1 ⊆ P a M -generic filter. Iterated Let Q be a poset in M [ G 1 ] and G 2 ⊆ Q a M [ G 1 ]-generic filter. Forcing Direct Limit I want to show that there exists a G M -generic filter on R such Construction that: of the model M [ G 1 ][ G 2 ] = M [ G ] We will define this filter using Boolean algebras. Suslin’s Problem and Martin Axiom 5 / 14

  12. Suslin’s Problem and Martin Axiom Let B be a complete Boolean algebra in M . Suslin’s Problem Martin Axiom Iterated Forcing Direct Limit Construction of the model Suslin’s Problem and Martin Axiom 6 / 14

  13. Suslin’s Problem and Martin Axiom Let B be a complete Boolean algebra in M . Let C ∈ M B such that Suslin’s Problem || C is a complete Boolean algebra || = 1. Martin Axiom Iterated Forcing Direct Limit Construction of the model Suslin’s Problem and Martin Axiom 6 / 14

  14. Suslin’s Problem and Martin Axiom Let B be a complete Boolean algebra in M . Let C ∈ M B such that Suslin’s Problem || C is a complete Boolean algebra || = 1. Martin Axiom D is a maximal subset in M B such that: Iterated Forcing 1 || c ∈ C || = 1 ∀ c ∈ D Direct Limit 2 c 1 , c 2 ∈ D , c 1 � = c 2 ⇒ || c 1 = c 2 || < 1 Construction of the model Suslin’s Problem and Martin Axiom 6 / 14

  15. Suslin’s Problem and Martin Axiom Let B be a complete Boolean algebra in M . Let C ∈ M B such that Suslin’s Problem || C is a complete Boolean algebra || = 1. Martin Axiom D is a maximal subset in M B such that: Iterated Forcing 1 || c ∈ C || = 1 ∀ c ∈ D Direct Limit 2 c 1 , c 2 ∈ D , c 1 � = c 2 ⇒ || c 1 = c 2 || < 1 Construction of the model I define + D : ∀ c 1 , c 2 ∈ D ∃ c ∈ D such that || c = c 1 + C c 2 || = 1 this c is unique and I define c = c 1 + D c 2 . The operations · D and − D are defined similarly. Suslin’s Problem and Martin Axiom 6 / 14

  16. Suslin’s Problem and Martin Axiom Let B be a complete Boolean algebra in M . Let C ∈ M B such that Suslin’s Problem || C is a complete Boolean algebra || = 1. Martin Axiom D is a maximal subset in M B such that: Iterated Forcing 1 || c ∈ C || = 1 ∀ c ∈ D Direct Limit 2 c 1 , c 2 ∈ D , c 1 � = c 2 ⇒ || c 1 = c 2 || < 1 Construction of the model I define + D : ∀ c 1 , c 2 ∈ D ∃ c ∈ D such that || c = c 1 + C c 2 || = 1 this c is unique and I define c = c 1 + D c 2 . The operations · D and − D are defined similarly. With this operations D is a complete Boolean algebra ( in M ). I define B ∗ C = D . Suslin’s Problem and Martin Axiom 6 / 14

  17. Suslin’s Problem and Martin Axiom Theorem Let B be a complete Boolean algebra in M , let C ∈ M B be Suslin’s such that || C is a complete Boolean algebra || = 1 and let Problem D = B ∗ C such that B is a complete subalgebra of D . Then Martin Axiom Iterated 1 If G 1 is an M -generic ultrafilter on B , C = i G 1 ( C ) and G 2 Forcing is an M [ G 1 ]-generic ultrafilter on C then there is an Direct Limit M -generic ultrafilter G on B ∗ C such that: Construction of the model M [ G 1 ][ G 2 ] = M [ G ] 2 If G is an M -generic ultrafilter on B ∗ C . G 1 = G ∩ B and C = i G 1 ( C ) then there is an M [ G 1 ]-generic ultrafilter G 2 on C such that: M [ G 1 ][ G 2 ] = M [ G ] Suslin’s Problem and Martin Axiom 7 / 14

  18. Suslin’s Problem and Martin Axiom Suslin’s Problem Martin Axiom Iterated Forcing Lemma Direct Limit Construction B satisfies ccc and || C satisfies ccc || = 1 iff B ∗ C satisfies ccc. of the model Suslin’s Problem and Martin Axiom 8 / 14

  19. Suslin’s Problem and Martin Axiom Let α be a limit ordinal. Suslin’s Let { B i } i <α a sequence such that Problem - B i is a complete Boolean algebra Martin Axiom Iterated - if i < j B i is a complete subalgebra of B j Forcing Direct Limit Construction of the model Suslin’s Problem and Martin Axiom 9 / 14

  20. Suslin’s Problem and Martin Axiom Let α be a limit ordinal. Suslin’s Let { B i } i <α a sequence such that Problem - B i is a complete Boolean algebra Martin Axiom Iterated - if i < j B i is a complete subalgebra of B j Forcing Direct Limit Direct limit Construction of the model The completion B of � i <α B i is called direct limit of { B i } . B = limdir i ≤ α B i . Suslin’s Problem and Martin Axiom 9 / 14

  21. Suslin’s Problem and Martin Axiom Let α be a limit ordinal. Suslin’s Let { B i } i <α a sequence such that Problem - B i is a complete Boolean algebra Martin Axiom Iterated - if i < j B i is a complete subalgebra of B j Forcing Direct Limit Direct limit Construction of the model The completion B of � i <α B i is called direct limit of { B i } . B = limdir i ≤ α B i . Lemma Then if each B i is k -saturated then B is k -saturated. In particular if each B i satisfies ccc then B satisfies ccc. Suslin’s Problem and Martin Axiom 9 / 14

  22. Suslin’s Problem and Martin Axiom Suslin’s Problem Martin Axiom Let M be a transitive model of ZFC + GCH. Iterated Forcing We will construct a complete Boolean algebra B such that if G Direct Limit is an M -generic filter on B then Construction of the model = MA + 2 ℵ 0 ≤ ℵ 2 M [ G ] | Suslin’s Problem and Martin Axiom 10 / 14

  23. Suslin’s Problem and Martin Axiom B α Suslin’s Let { B α } be a sequence such that: Problem 1 α < β ⇒ B α is a complete subalgebra of B β Martin Axiom Iterated 2 γ limit ⇒ B γ = limdir i ≤ γ B i Forcing 3 each B α satisfies ccc Direct Limit Construction 4 | B α | ≤ ℵ 2 of the model Suslin’s Problem and Martin Axiom 11 / 14

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