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Rational Functions With Nonnegative Integer Coefficients Ira Gessel - PDF document

Rational Functions With Nonnegative Integer Coefficients Ira Gessel Brandeis University Waltham, MA 02454-9110 gessel@brandeis.edu March 25, 2003 THE 50th SEMINAIRE LOTHARINGIEN DE COMBINATOIRE Domaine Saint-Jacques 1. When are the


  1. Rational Functions With Nonnegative Integer Coefficients Ira Gessel Brandeis University Waltham, MA 02454-9110 gessel@brandeis.edu March 25, 2003 THE 50th SEMINAIRE LOTHARINGIEN DE COMBINATOIRE Domaine Saint-Jacques

  2. 1. When are the coefficients of a rational function nonnegative? 2. When (if they are integers) do they have a combinatorial interpretation? How can we prove that numbers are nonnegative? 1. explicit formula 2. subtract a smaller number from a larger 3. square or sum of squares

  3. 1. ( a − b + c )! ( a + b − c − 1)! is nonnegative, where ( a − b − c − 1)! a ! b ! c ! a > b + c . √ 5 , so | (1 + 2 i ) 2 n | ≤ 5 n and similarly, 2. | 1 + 2 i | = | (1 − 2 i ) 2 n | ≤ 5 n . Therefore 2 · 5 n − (1 + 2 i ) 2 n − (1 − 2 i ) 2 n is a nonnegative integer. It follows (dividing these numbers by 16) that the coefficients of x + 5 x 2 1 + x − 5 x 2 − 125 x 3 are nonnegative integers. 3. The coefficient of x p y q z n in 1 1 − (1 + x )(1 + y ) z + 4 xyz 2 is � 2 �� p ! q ! ( n − i )! i ! ( p − i )! ( q − i )!( − 2) i ( n − p )! ( n − q )! i

  4. How to get a combinatorial interpretation for a rational generating function? The transfer matrix method. Let M be a matrix and let a n be the ( i, j ) entry of n =0 a n x n is rational. If the entries of M M n . Then � ∞ are nonnegative integers, it is reasonable to say that the a n have a combinatorial interpretation. More generally, if M is a matrix whose entries are polynomials with nonnegative coefficients and with no constant term then the entries of ( I − M ) − 1 are rational functions with combinatorial interpretations. Such rational functions are called N -recognizable. N -rational functions. The class of N -rational functions in a set of variables is the smallest set of rational functions containing 1 and all the variables and closed under addition, multiplication, and the operation f �→ f/ (1 − f ) whenever f has constant term 0. N -rational functions also have combinatorial interpretations. Theorem (Sch¨ utzenberger) A series is N -recognizable if and only if it is N -rational.

  5. Are there other ways to get rational functions whose coefficients have nonnegative coefficients? The Cartier-Foata theory of free partially commutative monoids Take a graph whose vertices are variables. If S is a set of vertices, we denote by Π( S ) the product of the the elements of S . Then � − 1 � � ( − 1) | S | � ( S ) S independent has nonnegative coefficients.

  6. Example a b e d c 1 1 − a − b − c − d − e + ac + ce + eb + ed + bd + da has nonnegative coefficients. However, these rational generating functions are always N -rational (Diekert), so we don’t get anything new. I don’t know of any rational functions with combinatorial interpretations that aren’t N -rational. Are there any? Problem: N -rationality gives a combinatorial interpretation. But it does not necessarily give a nice combinatorial interpretation.

  7. Are there rational functions with nonnegative integer coefficients that are known not to be N -rational? Yes. Let a n = 1 2 · 5 n − (1 + 2 i ) 2 n − (1 − 2 i ) 2 n � � 16 Im(1 + 2 i ) n � 2 = 5 n = 1 4 sin 2 nθ ≥ 0 , � 4 where θ = tan − 1 2 . Then ∞ x + 5 x 2 a n x n = � f ( x ) := 1 + x − 5 x 2 − 125 x 3 . n =0 However, f ( x ) is not N -rational by a theorem of Berstel (1971): If u ( x ) is N -rational with radius of convergence r then r is a pole of u ( x ) , and if s is a pole of u ( x ) with | s | = r then s/r is a root of unity. In other words, if u ( x ) is N -rational, then u ( x ) can be expressed, by multisection, as a sum of rational functions with a single (necessarily positive) pole on the circle of convergence.

  8. A converse of Berstel’s theorem was given by Soittola (1976) and rediscovered by Katayama, Okamoto, and Enomoto (1978). It implies, for example, that ∞ 2 · 6 n − (1 + 2 i ) 2 n − (1 − 2 i ) 2 n � � x n � n =0 is N -rational. However, this is obvious because the series is equal to 18 x + 86 x 2 1 − 11 x 2 − 150 x 3 But Soittola’s theorem also implies that 1 + x 1 + x − 2 x 2 − 3 x 3 is N -rational, which is not so obvious. Can we prove it directly?

  9. By multisection, we have 1 + x N ( x ) 1 + x − 2 x 2 − 3 x 3 = 1 + 1 − 2 x 6 − 107 x 12 − 729 x 18 where N ( x ) = 2 x 2 + x 3 + 3 x 4 + 5 x 5 + 4 x 6 + 15 x 7 + 4 x 8 + 32 x 9 + 21 x 10 + 55 x 11 + 83 x 12 + 90 x 13 + 27 x 14 + 81 x 15 + 243 x 16 + 729 x 18

  10. Examples of multivariable rational functions with nonnegative coefficients. 1 A ( x, y, z ) = 1 − 2( x + y + z ) + 3( xy + xz + yz ) 1 B ( x, y, z ) = 1 − x − y − z + 4 xyz 1 C ( x, y, z ) = 1 − x − y − xz − yz + 4 xyz These all have have nonnegative coefficients, but there is no known combinatorial interpretation for any of them. Szeg˝ o, Kaluza 1933; Ismail and Tamhankar 1979

  11. Note that 1 A ( x, x, z ) = (1 − 3 x )(1 − x − 2 z ) 1 B ( x, x, z ) = (1 − 2 x )(1 − z − 2 xz ) 1 C ( x, x, z ) = (1 − 2 x )(1 − 2 xz ) The nonnegativity of A is implied by that of B and the nonnegative of B is implied by that of C : � � 1 x y z A ( x, y, z ) = (1 − x )(1 − y )(1 − z ) B 1 − x, 1 − y, 1 − z and 1 � z � B ( x, y, z ) = 1 − zC x, y, 1 − z So it suffices to show that the coefficients of C are nonnegative. However, there is another way to show that the coefficients of B are nonnegative.

  12. The coefficients of √ 1 − 4 xy D ( x, y, z ) = 1 − x − y − z + 4 xyz are nonnegative. In fact, there is an explicit formula for the coefficients: � β ( a, b, c ) x a y b z c , D ( x, y, z ) = a,b,c where  ( a − b + c )! ( a + b − c − 1)! , if a > b + c    ( a − b − c − 1)! a ! b ! c !     β ( b, a, c ) , if b > a + c  β ( a, b, c ) = ( c + a − b )! ( c + b − a )! , if a + b ≤ c   ( c − a − b )! a ! b ! c !     0 , otherwise   This follows from (1 − x − y − z + 4 xyz ) D ( x, y, z ) = √ 1 − 4 xy or from hypergeometric identities.

  13. The numbers β ( a, b, c ) are “super ballot numbers”. For c = 0 they reduce to the ballot numbers: β ( a, b, 0) = a − b � a + b � , for a > b. a + b a Also of interest is the special case of “super Catalan numbers”: T ( m, n ) = β ( m + n, n, m − 1) = 1 (2 m )! (2 n )! m ! n ! ( m + n )! . 2 In particular, (2 n )! T (1 , n ) = C n = n ! ( n + 1)! (2 n )! T (2 , n ) = 6 n ! ( n + 2)! = 4 C n − C n +1 Combinatorial interpretations of T (2 , n ) have been found by Guoce Xin, Gilles Schaeffer, and Nicholas Pippenger and Kristin Schleich (but none are known for T (3 , n ) .)

  14. Why are the coefficients of 1 C ( x, y, z ) = 1 − x − y − xz − yz + 4 xyz nonnegative? They are essentially squares. More generally, let E ( x, y, z ; λ ) 1 = 1 − (1 − λ ) x − λy − λxz − (1 − λ ) yz + xyz � α ( i, j, k ; λ ) x i y j z k . = i,j,k Ismail and Tamhankar showed, using MacMahon’s master theorem, that if i + j < k then α ( i, j, k ; λ ) = 0 and if i + j ≥ k then α ( i, j, k ; λ ) = λ 2 i + j − k (1 − λ ) k − i ( i + j − k )! k ! i ! j ! � 2 �� � i �� j � (1 − λ − 1 ) l × l k − i + l l which is clearly nonnegative for 0 < λ < 1 . (Note that C ( x, y, z ) = E (2 x, 2 y, z ; 1 / 2) .)

  15. Ismail and Tamhankar’s result can be generalized: Let A = ( a ij ) be an m × n matrix. Let r = ( r 1 , . . . , r n ) and s = ( s 1 , . . . , s m ) be sequences of nonnegative integers, and let r = r 1 + · · · + r n and s = s 1 + · · · + s m . We use the notation [ z i 1 1 · · · z i k k ] h ( z 1 , . . . , z k ) to denote the coefficient of 1 · · · z i k z i 1 in h ( z 1 , . . . , z k ) . We define F A ( r , s ) and k G A ( r , s ) by F A ( r , s ) = [ y s 1 1 y s 2 2 · · · y s m m ] m � r 1 m � r n � � � � 1 + a i 1 y i · · · 1 + a in y i i =1 i =1 and for r ≥ s , G A ( r , s ) = [ x r 1 1 x r 2 2 · · · x r n n ] � n � r − s � n � n � s 1 � s m � � � x j a 1 j x j · · · a mj x j . j =1 j =1 j =1 If r < s then G A ( r , s ) = F A ( r , s ) = 0 .

  16. It’s easy to show that � r � � r � F A ( r , s ) = G A ( r , s ) . r 1 , r 2 , . . . , r n r − s, s 1 , s 2 , . . . , s m Let A = ( a ij ) and B = ( b ij ) be two m × n matrices. Let M be the ( n + m ) × ( n + m ) matrix � B t � J , A 0 where J is an n × n matrix of ones and 0 is an m × m matrix of zeros, and let Z be the ( n + m ) × ( n + m ) diagonal matrix with diagonal entries x 1 , . . . , x n , y 1 , . . . , y m . Then � F A ( r , s ) G B ( r , s ) x r 1 n y s 1 1 · · · x r n 1 · · · y s m m r , s = 1 / det( I − ZM ) . So if A = B then each coefficient of 1 / det( I − ZM ) is a positive integer times the square of a polynomial in the a ij , and if the a ij are positive real numbers then 1 / det( I − ZM ) has nonnegative coefficients. Proof: Use MacMahon’s Master Theorem.

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