on vizing s edge colouring question
play

On Vizings edge-colouring question Marthe Bonamy July 28, 2020 - PowerPoint PPT Presentation

On Vizings edge-colouring question Marthe Bonamy July 28, 2020 Marthe Bonamy On Vizings edge-colouring question 1/10 Edge colouring Marthe Bonamy On Vizings edge-colouring question 2/10 Edge colouring : Minimum number of


  1. On Vizing’s edge-colouring question Marthe Bonamy July 28, 2020 Marthe Bonamy On Vizing’s edge-colouring question 1/10

  2. Edge colouring Marthe Bonamy On Vizing’s edge-colouring question 2/10

  3. Edge colouring χ ′ : Minimum number of colors to ensure that a b ⇒ a � = b . Marthe Bonamy On Vizing’s edge-colouring question 2/10

  4. Edge colouring χ ′ : Minimum number of colors to ensure that a b ⇒ a � = b . ∆: Maximum degree of the graph. ∆ ≤ χ ′ Marthe Bonamy On Vizing’s edge-colouring question 2/10

  5. Vizing’s theorem and Kempe equivalence Theorem (Vizing ’64) For any graph G, ∆( G ) ≤ χ ′ ( G ) ≤ ∆( G ) + 1 . Marthe Bonamy On Vizing’s edge-colouring question 3/10

  6. Vizing’s theorem and Kempe equivalence Theorem (Vizing ’64) For any graph G, ∆( G ) ≤ χ ′ ( G ) ≤ ∆( G ) + 1 . Proof through “Kempe changes”. Marthe Bonamy On Vizing’s edge-colouring question 3/10

  7. Vizing’s theorem and Kempe equivalence Theorem (Vizing ’64) For any graph G, ∆( G ) ≤ χ ′ ( G ) ≤ ∆( G ) + 1 . Proof through “Kempe changes”. Marthe Bonamy On Vizing’s edge-colouring question 3/10

  8. Vizing’s theorem and Kempe equivalence Theorem (Vizing ’64) For any graph G, ∆( G ) ≤ χ ′ ( G ) ≤ ∆( G ) + 1 . Proof through “Kempe changes”. Marthe Bonamy On Vizing’s edge-colouring question 3/10

  9. Vizing’s theorem and Kempe equivalence Theorem (Vizing ’64) For any graph G, ∆( G ) ≤ χ ′ ( G ) ≤ ∆( G ) + 1 . Proof through “Kempe changes”. Marthe Bonamy On Vizing’s edge-colouring question 3/10

  10. Vizing’s theorem and Kempe equivalence Theorem (Vizing ’64) For any graph G, ∆( G ) ≤ χ ′ ( G ) ≤ ∆( G ) + 1 . Proof through “Kempe changes”. Marthe Bonamy On Vizing’s edge-colouring question 3/10

  11. Vizing’s theorem, revisited Theorem (Vizing ’64) For any graph G, for any proper edge colouring α of G, there is a proper (∆( G ) + 1) -edge colouring β of G such that α and β are Kempe-equivalent. Marthe Bonamy On Vizing’s edge-colouring question 4/10

  12. Vizing’s theorem, revisited Theorem (Vizing ’64) For any graph G, for any proper edge colouring α of G, there is a proper (∆( G ) + 1) -edge colouring β of G such that α and β are Kempe-equivalent. Conjecture (Vizing ’65) For any graph G, for any proper edge colouring α of G, there is a proper χ ′ ( G ) -edge colouring β of G such that α and β are Kempe-equivalent. Marthe Bonamy On Vizing’s edge-colouring question 4/10

  13. Vizing’s theorem, revisited Theorem (Vizing ’64) For any graph G, for any proper edge colouring α of G, there is a proper (∆( G ) + 1) -edge colouring β of G such that α and β are Kempe-equivalent. Theorem (Misra Gries ’92 (Inspired from the proof)) For any simple graph G = ( V , E ) , a (∆ + 1) -edge-coloring can be found in O ( | V | × | E | ) . Conjecture (Vizing ’65) For any graph G, for any proper edge colouring α of G, there is a proper χ ′ ( G ) -edge colouring β of G such that α and β are Kempe-equivalent. Marthe Bonamy On Vizing’s edge-colouring question 4/10

  14. Vizing’s theorem, revisited Theorem (Vizing ’64) For any graph G, for any proper edge colouring α of G, there is a proper (∆( G ) + 1) -edge colouring β of G such that α and β are Kempe-equivalent. Theorem (Misra Gries ’92 (Inspired from the proof)) For any simple graph G = ( V , E ) , a (∆ + 1) -edge-coloring can be found in O ( | V | × | E | ) . Conjecture (Vizing ’65) For any graph G, for any proper edge colouring α of G, there is a proper χ ′ ( G ) -edge colouring β of G such that α and β are Kempe-equivalent. Theorem (Holyer ’81) It is NP-complete to compute χ ′ . Marthe Bonamy On Vizing’s edge-colouring question 4/10

  15. Mohar’s conjecture Conjecture (Vizing ’65) For any graph G, for any proper edge colouring α of G, there is a proper χ ′ ( G ) -edge colouring β of G such that α and β are Kempe-equivalent. Marthe Bonamy On Vizing’s edge-colouring question 5/10

  16. Mohar’s conjecture Conjecture (Vizing ’65) For any graph G, for any proper edge colouring α of G, there is a proper χ ′ ( G ) -edge colouring β of G such that α and β are Kempe-equivalent. Only interesting for χ ′ ( G ) = ∆( G ). Marthe Bonamy On Vizing’s edge-colouring question 5/10

  17. Mohar’s conjecture Conjecture (Vizing ’65) For any graph G, for any proper edge colouring α of G, there is a proper χ ′ ( G ) -edge colouring β of G such that α and β are Kempe-equivalent. Only interesting for χ ′ ( G ) = ∆( G ). Conjecture (Mohar ’06) For any graph G, for any two (∆( G ) + 2) -edge colourings α and β of G, they are Kempe-equivalent. Marthe Bonamy On Vizing’s edge-colouring question 5/10

  18. Mohar’s conjecture Conjecture (Vizing ’65) For any graph G, for any proper edge colouring α of G, there is a proper χ ′ ( G ) -edge colouring β of G such that α and β are Kempe-equivalent. Only interesting for χ ′ ( G ) = ∆( G ). Conjecture (Mohar ’06) For any graph G, for any two (∆( G ) + 2) -edge colourings α and β of G, they are Kempe-equivalent. True if χ ′ ( G ) = ∆( G ). Marthe Bonamy On Vizing’s edge-colouring question 5/10

  19. Mohar’s conjecture Conjecture (Vizing ’65) For any graph G, for any proper edge colouring α of G, there is a proper χ ′ ( G ) -edge colouring β of G such that α and β are Kempe-equivalent. Only interesting for χ ′ ( G ) = ∆( G ). Conjecture (Mohar ’06) For any graph G, for any two (∆( G ) + 2) -edge colourings α and β of G, they are Kempe-equivalent. True if χ ′ ( G ) = ∆( G ). (Vizing’s conjecture) ⇒ (Mohar’s conjecture): induction on ∆( G ). Marthe Bonamy On Vizing’s edge-colouring question 5/10

  20. Small Delta Theorem (McDonald, Mohar, Scheide ’10) Vizing’s conjecture is true for ∆ = 3 . Marthe Bonamy On Vizing’s edge-colouring question 6/10

  21. Small Delta Theorem (McDonald, Mohar, Scheide ’10) Vizing’s conjecture is true for ∆ = 3 . Theorem (Asratian, Casselgren ’16) Vizing’s conjecture is true for ∆ = 4 . Marthe Bonamy On Vizing’s edge-colouring question 6/10

  22. Small Delta Theorem (McDonald, Mohar, Scheide ’10) Vizing’s conjecture is true for ∆ = 3 . Theorem (Asratian, Casselgren ’16) Vizing’s conjecture is true for ∆ = 4 . Theorem (B., Defrain, Klimoˇ sov´ a, Lagoutte, Narboni ’20) Vizing’s conjecture is true for triangle-free graphs. Marthe Bonamy On Vizing’s edge-colouring question 6/10

  23. Small Delta Theorem (McDonald, Mohar, Scheide ’10) Vizing’s conjecture is true for ∆ = 3 . Theorem (Asratian, Casselgren ’16) Vizing’s conjecture is true for ∆ = 4 . Theorem (B., Defrain, Klimoˇ sov´ a, Lagoutte, Narboni ’20) Vizing’s conjecture is true for triangle-free graphs. Theorem (B., Defrain, Klimoˇ sov´ a, Lagoutte, Narboni ’20) For any triangle-free graph, all ( χ ′ + 1) -edge-colourings are Kempe-equivalent. Marthe Bonamy On Vizing’s edge-colouring question 6/10

  24. General structure By induction on χ ′ ( G ). Marthe Bonamy On Vizing’s edge-colouring question 7/10

  25. General structure By induction on χ ′ ( G ). It suffices to consider χ ′ ( G )-regular graphs. Marthe Bonamy On Vizing’s edge-colouring question 7/10

  26. General structure By induction on χ ′ ( G ). It suffices to consider χ ′ ( G )-regular graphs. Consider a target χ ′ ( G )-edge-colouring α , and M one of its color classes ( M is a perfect matching). Marthe Bonamy On Vizing’s edge-colouring question 7/10

  27. General structure By induction on χ ′ ( G ). It suffices to consider χ ′ ( G )-regular graphs. Consider a target χ ′ ( G )-edge-colouring α , and M one of its color classes ( M is a perfect matching). Goal: make M monochromatic (say with colour 1). Marthe Bonamy On Vizing’s edge-colouring question 7/10

  28. General structure By induction on χ ′ ( G ). It suffices to consider χ ′ ( G )-regular graphs. Consider a target χ ′ ( G )-edge-colouring α , and M one of its color classes ( M is a perfect matching). Goal: make M monochromatic (say with colour 1). Good ( ∈ M , coloured 1), bad ( ∈ M , not coloured 1), ugly ( �∈ M , coloured 1) edges. Marthe Bonamy On Vizing’s edge-colouring question 7/10

  29. Fan-like tools 2 u v Marthe Bonamy On Vizing’s edge-colouring question 8/10

  30. Fan-like tools 2 u v ✁ ❆ 3 Marthe Bonamy On Vizing’s edge-colouring question 8/10

  31. Fan-like tools 2 u v ✁ ❆ ✁ ❆ 3 3 Marthe Bonamy On Vizing’s edge-colouring question 8/10

  32. Fan-like tools 2 u v ✁ ❆ ✁ ❆ 3 4 Marthe Bonamy On Vizing’s edge-colouring question 8/10

  33. Fan-like tools w ✁ ❆ 3 4 2 u v ✁ ❆ ✁ ❆ 3 4 Marthe Bonamy On Vizing’s edge-colouring question 8/10

  34. Fan-like tools w ❆ ✁ 3 5 2 5 u v x ❆ ✁ ❆ ✁ 3 4 Marthe Bonamy On Vizing’s edge-colouring question 8/10

  35. Fan-like tools w ❆ ✁ 3 5 2 5 u v x ❆ ✁ ❆ ✁ ✁ ❆ 3 4 3 Marthe Bonamy On Vizing’s edge-colouring question 8/10

  36. Fan-like tools w ❆ ✁ 3 5 2 5 u v x ❆ ✁ ✁ ❆ ✁ ❆ 3 4 3 − → D v : vy → vz if vz is coloured with the colour missing at y . vw uv vx Marthe Bonamy On Vizing’s edge-colouring question 8/10

Recommend


More recommend