13 Nov., 2015, YITP Workshop - Developments in String Theory and Quantum Field Theory Negative anomalous dimensions in N =4 SYM Yusuke Kimura (OIQP) 1503.0621 [hep-th] with Ryo Suzuki 1
1. Introduction β brief review of N=4 SYM 2
Anomalous dimensions of N =4 SYM (Conformal Field Theory) 2 π Two-point functions π = π ππ π π½ π π½πΎ Ξ = Ξ (0) + πΞ (1) + π 2 Ξ (2) + β― π π½ π¦ π πΎ π§ = π¦ β π§ 2Ξ π½ Scaling dimension Dilatation generator β Conformal symmetry, so(4,2) πΈ = πΈ (0) + π πΈ (1) + π 2 πΈ 2 + β― πΈπ π½ (0) = Ξ π½ π π½ (0) Via the radial quantisation, π 4 β π 3 Γ π πΌ|πβͺ = πΉ|πβͺ 3
AdS/CFT correspondence 4D π = 4 Sπ(π) SYM (CFT) β string theory on π΅ππ 5 Γ π 5 4 π π΅ππ π π = 4ππ = π π‘ Ξ π, π = πΉ(π π‘ , π π΅ππ /π π‘ ) π π‘ 2 π ) ( π = π ππ Several ways of looking at the equation οΌ Check the duality οΌ Use to understand something new ο§ String theory at small curvature π π΅ππ βͺ π π‘ is difficult ο§ Gauge theory description is easier at π βͺ 1 4
Operator mixing problem π΅ π , Ξ¦ π π = 1, β― , 6 , π π½ For the SO(6) sector, the 1-loop dilatation operator is given by πΈ 1βππππ = 1 π πΌ πΌ = β 1 2 : π’π Ξ¦ π , Ξ¦ π π π , π π : β 1 4 : π’π Ξ¦ π , π π Ξ¦ π , π π : π π ππ Ξ¦ π ππ = π ππ π ππ π Ξ¦ π are just matrices ππ πΈπ π½ = π π½πΎ π πΎ 1) for a general basis Diagonalise π π½πΎ to obtain πΈπ π½ = Ξ π½ π π½ 2) Eigenvalue problem of the matrix model 5
Will study the spectrum of anomalous dimensions, focusing on the sign of them Ξ = Ξ (0) + πΞ 1 (1/π) + π(π 2 ) + β― 1. In the planar limit, anomalous dimensions are all positive 2. But it is not the case when you include non-planar corrections To understand physics of negative anomalous dimensions is to understand nonplanar corrections 6
Outline οΌ Brief review of N=4 SYM (CFT) οΌ Anomalous dimensions οΌ Dilatation operator οΌ Operator mixing problem οΌ Planar vs Non-planar οΌ Negative anomalous dimensions [1503.0621, YK-R.Suzuki] 7
2. Operator mixing problem β planar vs non-planar 8
Operator mixing π’π Ξ¦ π , Ξ¦ π π π , π π = 2π’π Ξ¦ π Ξ¦ π π π π π β 2π’π Ξ¦ π Ξ¦ π π π π π π’π Ξ¦ π , π π Ξ¦ π , π π = 2π’π Ξ¦ π π π Ξ¦ π π π β 2π’π Ξ¦ π Ξ¦ π π π π π π’π Ξ¦ π Ξ¦ π π π π π π’π π΅Ξ¦ π π’π πΆΞ¦ π = π’π πΆπ΅Ξ¦ π Ξ¦ π + π΅πΆΞ¦ π Ξ¦ π π’π Ξ¦ π Ξ¦ π π π π π π’π π΅Ξ¦ π πΆΞ¦ π = π’π π΅ π’π πΆΞ¦ π Ξ¦ π + π’π πΆ π’π π΅Ξ¦ π Ξ¦ π Dilatation operator changes the number of traces by one - Joining and splitting When the two derivatives act on nearest neighbor matrices, we get a term whose trace structure is not changed π’π Ξ¦ π Ξ¦ π π π π π π’π π΅Ξ¦ π Ξ¦ π = π’π π΅ π’π Ξ¦ π Ξ¦ π + ππ’π π΅Ξ¦ π Ξ¦ π The two derivatives acting on non-nearest neighbor matrices, the trace structure changes 9
πΌπ’π π΅Ξ¦ π Ξ¦ π = π π’π π΅Ξ¦ π Ξ¦ π β π’π π΅Ξ¦ π Ξ¦ π + 1 2 π ππ π’π π΅Ξ¦ π Ξ¦ π +πππ£πππ π’π ππππ‘ Nearest neighbour transpositions π and contractions π· on flavor indices π β Ξ¦ π Ξ¦ π = Ξ¦ π Ξ¦ π π· β Ξ¦ π Ξ¦ π = π ππ Ξ¦ π Ξ¦ π πΌ π = 1 β π + 1 2 π· πΌ = ππΌ π + πΌ ππ πΌ π : not changing the trace structure, but changing the flavour structure πΌ ππ : changing the trace structure and the flavour structure 10
Planar limit π· οΌ Dilatation operator is πΌ π = 1 β π + 2 β’ Mapped to the Hamiltonian of an integrable spin chain [02 Minahan-Zarembo] οΌ the mixing is only among operators with the same trace structure (i.e. trace structure has a meaning) π’π (Ξ¦ 6 ) Block-diagonal mixing matrix βΌ π’π Ξ¦ 3 π’π (Ξ¦ 3 ) β± Non-planar β we do not have the above properties (We can find a nice mixing pattern in non-planar situations in terms of Young diagrams) 11
Remark πΌ = ππΌ π + πΌ ππ Acting on a small operator πΉ = π(π) + π(1) πΉ = π(ππ) + π(π 2 ) Acting on a very large operator The planar limit is π β« π π πππ = π/π D-branes are considered to be described by large operators π βΌ π π , π β« 1 - One can not use the planar limit 12
3. Negative anomalous dimensions [1503.0621, YK-R.Suzuki] 13
Spectral problem in the so(6) singlet sector π’π (Ξ¦ π Ξ¦ π )π’π (Ξ¦ π Ξ¦ π ) , π’π (Ξ¦ π Ξ¦ π Ξ¦ π Ξ¦ π ) οΌ SO(6) singlet operators Singlets are mapped to singlets under dilatation ο§ Consider planar zero modes at one-loop - πΌ π π 0 = 0 o Giving an interesting class of operators o Thanks to integrability, there is a large degeneracy in the planar spectrum. ο§ Turning on 1/π corrections, the planar zero modes will get anomalous 1 1 dimensions of the form: πΏ = 0 + π πΏ 1 + π 2 πΏ 2 + β― οΌ Sign of πΏ 1 , πΏ 2 οΌ Operator mixing among the planar zero modes 14
π = 4 There are 4 singlet operators π’ 1 = π’π (Ξ¦ π Ξ¦ π )π’π (Ξ¦ π Ξ¦ π ) , π’ 2 = π’π (Ξ¦ π Ξ¦ π )π’π (Ξ¦ π Ξ¦ π ) π’ 3 = π’π (Ξ¦ π Ξ¦ π Ξ¦ π Ξ¦ π ) , π’ 4 = π’π (Ξ¦ π Ξ¦ π Ξ¦ π Ξ¦ π ) πΌπ’ π = ππΏ ππ π’ π 0 2 β10/π 10/π 0 2 β12/π 12/π πΏ = β12/π 2/π 4 β2 β2/π 7/π β2 9 block-diagonal if π β« 1 , where the single-traces are orthogonal to the double-traces. Use Mathematica to compute eigenvalues 15
πΏ (one-loop anomalous dimension) vs π π = 4 Planar zero mode Negative mode 16
π’ 1 = π’π (Ξ¦ π Ξ¦ π )π’π (Ξ¦ π Ξ¦ π ) , π’ 2 = π’π (Ξ¦ π Ξ¦ π )π’π (Ξ¦ π Ξ¦ π ) π = 4 π’ 3 = π’π (Ξ¦ π Ξ¦ π Ξ¦ π Ξ¦ π ) , π’ 4 = π’π (Ξ¦ π Ξ¦ π Ξ¦ π Ξ¦ π ) The negative mode looks like ππ + 3 5 π = 6π ππ π 4π 14π’ 3 β 4π’ 4 + 168π 2 978π’ 1 β 107π’ 2 + β― The leading term is given by the energy-momentum tensor, which is traceless and symmetric ππ = π’π Ξ¦ π Ξ¦ π β 1 π 6 π ππ π’π (Ξ¦ π Ξ¦ π ) ππ ππ = π ππ , π·π ππ = 0 It is annihilated by the planar dilatation operator, πΌ π = 1 β π + π·/2 πΌ π π ππ π ππ = πΌ π π ππ π ππ + π ππ πΌ π π ππ = 0 17
Planar zero modes Number of planar zero modes and singlet operators πΌ π = 1 β π + π·/2 πΌ π π 0 = 0 π· π 1 π 2 β―π π = π’π Ξ¦ (π 1 Ξ¦ π 2 β― Ξ¦ π π ) 1/2 BPS : symmetric and traceless πΌ π π· π 1 π 2 β―π π = 0 π = 4 : π· ππ π· ππ π = 6 : π· πππ π· πππ , π· ππ π· ππ π· ππ π = 8 : π· ππππ π· ππππ , π· ππππ π· ππ π· ππ , π· πππ π· πππ π· ππ , π· ππ π· ππ π· ππ π· ππ , π· ππ π· ππ π· ππ π· ππ οΌ Can not construct single-trace planar zero modes 18
π = 6 There are 15 singlet operators There are 2 planar zero modes. One stays on the zero, and the other gets a negative anomalous dimension. 19
π = 8 71 singlets 5 planar zero modes 20
On the planar zero modes Mathematica computation at π = 4,6,8,10 and analytic computation with some approximation πΌ 0 π 0 = 0 πΌπ = ππΏπ πΏ = πΏ 0 + πΏ 1 π + πΏ 2 π = π 0 + π 1 π + π 2 π 2 + β― π 2 + β― o πΏ 0 = 0 , πΏ 1 = 0 , πΏ 2 β€ 0 β’ Planar zero mode β negative mode o π 0 is a linear combination of the planar zero modes with a fixed number of traces π’π Ξ¦ 4 π’π Ξ¦ 4 π’π (Ξ¦ 2 ) is orthogonal to π’π Ξ¦ 5 π’π Ξ¦ 3 π’π (Ξ¦ 2 ) in the β’ planar limit, but they mix by the 1/π effect. β’ the number of traces might be a good quantity 21
A possible interpretation of negative modes Based on the standard correspondence of AdS/CFT Ξ = Ξ 0 + π πΏ 2 2 1 π 2 + β― πΏ 2 < 0 πΉ = πΉ 0 + πΏ 2 π π‘ π½ β² + β― No interaction (planar zero mode) Negative mode The negative modes would describe multi-particle (multi-string) states with non-zero binding energy. [02 Arutuynov, Penati, Petkou, Santambrogio, Sokatchev] The number of states might be related to the number of traces in π 0 22
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