INC 212 Signals and systems Lecture#4: Frequency response of LTI systems Assoc. Prof. Benjamas Panomruttanarug benjamas.pan@kmutt.ac.th
Fourier Representations of f Sig ignals & LTI I Systems A signal can be represented as a weighted superposition of complex sinusoids. y ( t ) x ( t ) LTI System Output = A weighted superposition of the system response to each complex sinusoid. Frequency response The response of an LTI system to a sinusoidal input.
Continuous-time LTI system • Impulse response of continuous-time LTI system = h ( t ), input = x ( t ) = e j t • Output: j ( t ) j t j y t ( ) h ( ) e d e h ( ) e d j t H j ( ) e • Frequency response: j H j ( ) h ( ) e d
Polar form complex number c = a + jb : j arg{ } c 2 2 1 b c c e c a b and arg{ } c tan where a Polar form for H ( j ): j arg{ H j ( )} H j ( ) H j ( ) e H j ( ) Magnitude response and arg H j ( ) Phase respnse where j t arg H j y t H j e amplitude of output = amplitude of input*magnitude response phase of output = phase of input+phase response
Example 3.1 .1 RC Circuit: Frequency response The impulse response of the system relating to the input voltage to the voltage across the capacitor 1 t RC / h t ( ) e u t ( ) RC Find an expression for the frequency response, and plot the magnitude and phase response.
Frequency response: Magnitude response: 1 1 j RC H j e RC u e d H j RC 2 1 2 RC 1 1 1 j RC e 1 RC j RC 0 1 1 0 1 Phase response: RC 1 j RC arg H j arctan RC 1 RC 1 j RC
Matlab code clear;clc; R = 1; C = 1; for i = 0:100 H(i+1) = 1/(1+j*(2*pi*i)*R*C); M(i+1) = abs(H(i+1)); P(i+1) = angle(H(i+1)); end figure; subplot 211; plot((0:100),M); subplot 212; plot((0:100),P);
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