D AY 107 – E XPONENTIAL G ROWTH AND D ECAY
E XPONENTIAL F UNCTION What do we know about exponents? What do we know about functions?
E XPONENTIAL F UNCTIONS Always involves the equation: b x Example: 2 3 = 2 · 2 · 2 = 8
x 2 G ROUP INVESTIGATION : y Create an x,y table. Use x values of -1, 0, 1, 2, 3, Graph the table What do you observe.
T HE T ABLE : R ESULTS x f(x) = 2 x 2 -1 = ½ -1 2 0 = 1 0 2 1 = 2 1 2 2 = 4 2 2 3 = 8 3
x 2 T HE G RAPH OF y
O BSERVATIONS What did you notice? What is the pattern? What would happen if 2 x What would happen if 5 x What real-life applications are there?
G ROUP : M ONEY D OUBLING ? You have a $100.00 Your money doubles each year. How much do you have in 5 years? Show work.
M ONEY D OUBLING Year 1: $100 *2 = $200 Year 2: $200 *2 = $400 Year 3: $400 *2 = $800 Year 4: $800 *2 = $1600 Year 5: $1600 *2 = $3200
E ARNING I NTEREST ON You have $100.00. Each year you earn 10% interest. How much $ do you have in 5 years? Show Work.
E ARNING 10% RESULTS Year 1: $100 + 100*(0.10) = $110 Year 2: $110 + 110*(0.10) = $121 Year 3: $121 + 121*(0.10) = $133.10 Year 4: $133.10 + 133.10*(0.10) = $146.41 Year 5: $146.41 + 1461.41*(0.10) = $161.05
G ROWTH M ODELS : I NVESTING The Equation is: ( t 1 ) a p r P = Principal r = Annual Rate t = Number of years
U SING THE E QUATION $100.00 10% interest 5 years 100(1+ (.10)) 5 = $161.05 What could we figure out now?
C OMPARING I NVESTMENTS Choice 1 $10,000 5.5% interest 9 years Choice 2 $8,000 6.5% interest 10 years
C HOICE 1 $10,000, 5.5% interest for 9 years. Equation: $10,000 (1 + .055) 9 Balance after 9 years: $16,190.94
C HOICE 2 $8,000 in an account that pays 6.5% interest for 10 years. Equation: $8,000 (1 + .065) 10 Balance after 10 years: $15,071.10
W HICH I NVESTMENT ? The first one yields more money. Choice 1: $16,190.94 Choice 2: $15,071.10
E XPONENTIAL D ECAY Instead of increasing, it is decreasing. ( Formula: t 1 ) y a r a = initial amount r = percent decrease t = Number of years
R EAL - LIFE E XAMPLES What is car depreciation? Car Value = $20,000 Depreciates 10% a year Figure out the following values: After 2 years After 5 years After 8 years After 10 years
E XPONENTIAL D ECAY : C AR D EPRECIATION Assume the car was purchased for $20,000 Depreciation Value after 2 Value after 5 Value after 8 Value after 10 Rate years years years years $16,200 $11,809.80 $8609.34 $6973.57 10% ( Formula: t 1 5 ) y a a = initial amount r = percent decrease t = Number of years
W HAT E LSE ? What happens when the depreciation rate changes. What happens to the values after 20 or 30 years out – does it make sense? What are the pros and cons of buying new or used cars.
A SSIGNMENT 2 Worksheets: Exponential Growth: Investing Worksheet Exponential Decay: Car Depreciation
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